結果
問題 | No.442 和と積 |
ユーザー |
![]() |
提出日時 | 2019-04-17 22:50:34 |
言語 | C (gcc 13.3.0) |
結果 |
WA
(最新)
AC
(最初)
|
実行時間 | - |
コード長 | 3,313 bytes |
コンパイル時間 | 1,169 ms |
コンパイル使用メモリ | 32,768 KB |
実行使用メモリ | 6,944 KB |
最終ジャッジ日時 | 2024-07-04 23:17:45 |
合計ジャッジ時間 | 1,681 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge5 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 17 WA * 1 |
ソースコード
// yukicoder: No.442 和と積// 2019.4.17 bal4u#include <stdio.h>#include <math.h>#define SIZE 50long long factor[3][SIZE];int power[3][SIZE];int sz[3];int ptbl[] = {3, 5, 7, 11, 13, 17, 19, 23, 29,31, 37, 41, 43, 47, 53, 59, 61, 67, 71,73, 79, 83, 89, 97, 101, 103, 107, 109, 113,127, 131, 137, 139, 149, 151, 157, 163, 167, 173,179, 181, 191, 193, 197, 199, 211, 223, 227, 229,233, 239, 241, 251, 257, 263, 269, 271, 277, 281,283, 293, 307, 311, 313, 317, 331, 337, 347, 349,353, 359, 367, 373, 379, 383, 389, 397, 401, 409,419, 421, 431, 433, 439, 443, 449, 457, 461, 463,467, 479, 487, 491, 499, 503, 509, 521, 523, 541,547, 557, 563, 569, 571, 577, 587, 593, 599, 601,607, 613, 617, 619, 631, 641, 643, 647, 653, 659,661, 673, 677, 683, 691, 701, 709, 719, 727, 733,739, 743, 751, 757, 761, 769, 773, 787, 797, 809,811, 821, 823, 827, 829, 839, 853, 857, 859, 863,877, 881, 883, 887, 907, 911, 919, 929, 937, 941,947, 953, 967, 971, 977, 983, 991, 997, 0 };int prime_factor(int id, long long n){int i, d, size;int *pp;size = 0;if ((n & 1) == 0) {factor[id][size] = 2;do n >>= 1, power[id][size]++;while ((n & 1) == 0);size++;}for (pp = ptbl; n > 1 && *pp > 0; pp++) {if (n % *pp) continue;d = *pp;factor[id][size] = d;do n /= d, power[id][size]++;while (n % d == 0);size++;}if (n > 1) {int b = (int)sqrt((double)n);for (i = 1009; n > 1; i += 2) {if (i > b) {factor[id][size] = n, power[id][size++] = 1;break;}if (n % i == 0) {factor[id][size] = i;do n /= i, power[id][size]++;while (n % i == 0);size++;}}}return size;}int f[SIZE];int main(){int i, j;long long A, B, a, b, a2, b2, ans;scanf("%lld%lld", &A, &B);if (A == B) {if (A & 1) ans = A;else ans = A << 1;printf("%lld\n", ans);return 0;}a = A, b = B;a2 = 1; while ((a & 1) == 0) a2 <<= 1, a >>= 1;b2 = 1; while ((b & 1) == 0) b2 <<= 1, b >>= 1;if (a2 < b2) ans = a2;else ans = b2;if (ans > 1 && (a > 0x4ffffffffffffffLL || b > 0x4ffffffffffffffLL)) {printf("%lld\n", ans); return 0;}sz[0] = prime_factor(0, A);sz[1] = prime_factor(1, B);sz[2] = prime_factor(2, A+B);i = j = 0; while (i < sz[0] && j < sz[1]) {while (factor[1][j] > factor[0][i] && i < sz[0]) i++;while (factor[1][j] < factor[0][i] && j < sz[1]) j++;if (i < sz[0] && j < sz[1] && factor[0][i] == factor[1][j]) {power[0][i] += power[1][j], factor[1][j] = 0;i++, j++;}}ans = 1;i = j = 0; while (i < sz[0] && j < sz[2]) {while (factor[2][j] > factor[0][i] && i < sz[0]) i++;while (factor[2][j] < factor[0][i] && j < sz[2]) j++;if (i < sz[0] && j < sz[2] && factor[0][i] == factor[2][j]) {if (power[0][i] > power[2][j]) power[0][i] = power[2][j];while (power[0][i]--) ans *= factor[0][i];i++, j++;}}i = j = 0; while (i < sz[1] && j < sz[2]) {while (factor[2][j] > factor[1][i] && i < sz[1]) i++;while (factor[2][j] < factor[1][i] && j < sz[2]) j++;if (i < sz[1] && j < sz[2] && factor[1][i] == factor[2][j]) {if (power[1][i] > power[2][j]) power[1][i] = power[2][j];while (power[1][i]--) ans *= factor[1][i];}i++, j++;}printf("%lld\n", ans);return 0;}