結果
問題 | No.575 n! / m / m / m... |
ユーザー |
![]() |
提出日時 | 2019-04-20 21:57:32 |
言語 | C (gcc 13.3.0) |
結果 |
AC
|
実行時間 | 6 ms / 2,000 ms |
コード長 | 2,471 bytes |
コンパイル時間 | 292 ms |
コンパイル使用メモリ | 32,640 KB |
実行使用メモリ | 5,248 KB |
最終ジャッジ日時 | 2024-10-02 06:57:58 |
合計ジャッジ時間 | 1,636 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 23 |
ソースコード
// yukicoder: No.575 n! / m / m / m...// 2019.4.20 bal4u#include <stdio.h>#include <math.h>#define SIZE 50long long factor[SIZE]; int power[SIZE];int ptbl[] = {3, 5, 7, 11, 13, 17, 19, 23, 29,31, 37, 41, 43, 47, 53, 59, 61, 67, 71,73, 79, 83, 89, 97, 101, 103, 107, 109, 113,127, 131, 137, 139, 149, 151, 157, 163, 167, 173,179, 181, 191, 193, 197, 199, 211, 223, 227, 229,233, 239, 241, 251, 257, 263, 269, 271, 277, 281,283, 293, 307, 311, 313, 317, 331, 337, 347, 349,353, 359, 367, 373, 379, 383, 389, 397, 401, 409,419, 421, 431, 433, 439, 443, 449, 457, 461, 463,467, 479, 487, 491, 499, 503, 509, 521, 523, 541,547, 557, 563, 569, 571, 577, 587, 593, 599, 601,607, 613, 617, 619, 631, 641, 643, 647, 653, 659,661, 673, 677, 683, 691, 701, 709, 719, 727, 733,739, 743, 751, 757, 761, 769, 773, 787, 797, 809,811, 821, 823, 827, 829, 839, 853, 857, 859, 863,877, 881, 883, 887, 907, 911, 919, 929, 937, 941,947, 953, 967, 971, 977, 983, 991, 997, 0 };int prime_factor(long long n){int i, d, sz;int *pp;sz = 0;if ((n & 1) == 0) {factor[sz] = 2;do n >>= 1, power[sz]++;while ((n & 1) == 0);sz++;}for (pp = ptbl; n > 1 && *pp > 0; pp++) {if (n % *pp) continue;d = *pp;factor[sz] = d;do n /= d, power[sz]++;while (n % d == 0);sz++;}if (n > 1) {int b = (int)sqrt((double)n);for (i = 1009; n > 1; i += 2) {if (i > b) {factor[sz] = n, power[sz++] = 1;break;}if (n % i == 0) {factor[sz] = i;do n /= i, power[sz]++;while (n % i == 0);sz++;}}}return sz;}#define PI 3.1415926535897932384626433832795#define E 2.7182818284590452353602874713526double calc(int n, long long m, long long c){int i;double a = 0;for (i = 2; i <= n; i++) a += log10((double)i);return a - c*log10((double)m);}long long check(long long n, long long f, int p){long long c = 0, d = f;while (d <= n) c += n/d, d *= f;return c / p;}int main(){int i, sz;long long n, m, c, d;double p;scanf("%lld%lld", &n, &m);sz = prime_factor(m);c = 0x7fffffffffffffLL; for (i = 0; i < sz; i++) {d = check(n, factor[i], power[i]);if (d < c) c = d;}if (n <= 1000) p = calc((int)n, m, c);else p = 0.5*log10(2*PI*n) + n*log10(n/E)+ log10(1 + 1/(12.0*n)) - c*log10((double)m);d = (long long)(p+1e-8);p -= d;p = pow(10, p);printf("%lfe%lld\n", p, d);return 0;}