結果
| 問題 | No.545 ママの大事な二人の子供 |
| コンテスト | |
| ユーザー |
ckawatak
|
| 提出日時 | 2019-04-27 18:56:10 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
AC
|
| 実行時間 | 156 ms / 2,000 ms |
| コード長 | 1,113 bytes |
| 記録 | |
| コンパイル時間 | 376 ms |
| コンパイル使用メモリ | 82,160 KB |
| 実行使用メモリ | 92,536 KB |
| 最終ジャッジ日時 | 2024-11-29 02:00:15 |
| 合計ジャッジ時間 | 3,838 ms |
|
ジャッジサーバーID (参考情報) |
judge5 / judge2 |
(要ログイン)
| ファイルパターン | 結果 |
|---|---|
| other | AC * 32 |
ソースコード
N = int(input())
A = []
B = []
for _ in range(N):
pair = list(map(int, input().split()))
A.append(pair[0])
B.append(pair[1])
def calc_diffs(n,offset):
diffs = []
for i in range(1 << n):
diff = 0
for j in range(n):
if i & (1<<j):
diff = diff + A[j+offset]
else:
diff = diff - B[j+offset]
diffs.append(diff)
diffs = list(set(diffs))
return sorted(diffs)
def lower_bound(n, ns):
left = 0
right = len(ns)
while left < right:
middle = (left + right)//2
if 0 <= n + ns[middle]:
right = middle-1
else:
left = middle+1
return right
def solve():
if N == 1:
return min(A[0], B[0])
ldiffs = calc_diffs(N//2,0)
rdiffs = calc_diffs(N-N//2, N//2)
mindiff = float('inf')
for left in ldiffs:
i = lower_bound(left, rdiffs)
for j in range(-1,2):
index = i+j
if 0 <= index < len(rdiffs):
mindiff = min(mindiff, abs(left+rdiffs[index]))
return mindiff
print(solve())
ckawatak