結果
| 問題 |
No.613 Solitude by the window
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2019-04-27 23:13:35 |
| 言語 | D (dmd 2.109.1) |
| 結果 |
AC
|
| 実行時間 | 1 ms / 2,000 ms |
| コード長 | 2,742 bytes |
| コンパイル時間 | 918 ms |
| コンパイル使用メモリ | 120,028 KB |
| 実行使用メモリ | 6,944 KB |
| 最終ジャッジ日時 | 2024-06-22 01:03:24 |
| 合計ジャッジ時間 | 1,599 ms |
|
ジャッジサーバーID (参考情報) |
judge2 / judge1 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 21 |
ソースコード
/*
x -> x (x + 4) = (x + 2)^2 - 4
x + 2 -> (x + 2)^2 - 2
z[0] = 4, z[n + 1] = z[n]^2 - 2
z[n] = a^(2^n) + b^(2^n)
a + b = 4, a b = 1
a, b = 2 \pm sqrt(3)
T^2 - 4 T + 1 = 0
(P / 3) = +1 if P == 1 (mod 3)
(P / 3) = -1 if P == 2 (mod 3)
(3 / P) = +1 if P == 1, 11 (mod 12)
(3 / P) = -1 if P == 5, 7 (mod 12)
(0) P = 3
z[n] = 2 2^(2^n) = 2 if n >= 1
(+1) P == 1, 11 (mod 12)
a^*: period | P - 1
(-1) P == 5, 7 (mod 12)
b = a^P (Frobenius aut.)
a^(P+1) = 1
a^*: period | P + 1
*/
import std.conv, std.functional, std.stdio, std.string;
import std.algorithm, std.array, std.bigint, std.complex, std.container, std.math, std.numeric, std.range, std.regex, std.typecons;
import core.bitop;
class EOFException : Throwable { this() { super("EOF"); } }
string[] tokens;
string readToken() { for (; tokens.empty; ) { if (stdin.eof) { throw new EOFException; } tokens = readln.split; } auto token = tokens.front; tokens.popFront; return token; }
int readInt() { return readToken.to!int; }
long readLong() { return readToken.to!long; }
real readReal() { return readToken.to!real; }
bool chmin(T)(ref T t, in T f) { if (t > f) { t = f; return true; } else { return false; } }
bool chmax(T)(ref T t, in T f) { if (t < f) { t = f; return true; } else { return false; } }
int binarySearch(alias pred, T)(in T[] as) { int lo = -1, hi = cast(int)(as.length); for (; lo + 1 < hi; ) { const mid = (lo + hi) >> 1; (unaryFun!pred(as[mid]) ? hi : lo) = mid; } return hi; }
int lowerBound(T)(in T[] as, T val) { return as.binarySearch!(a => (a >= val)); }
int upperBound(T)(in T[] as, T val) { return as.binarySearch!(a => (a > val)); }
long power(long a, long e, long m) {
long x = a % m, y = 1 % m;
for (; e; e >>= 1) {
if (e & 1) {
y = (y * x) % m;
}
x = (x * x) % m;
}
return y;
}
void main() {
try {
for (; ; ) {
const N = readLong();
const P = readLong();
long ans;
if (P == 3) {
ans = (N == 0) ? 1 : 2;
} else {
// T^2 - 4 T + 1
long[] mul(long[] a, long[] b) {
return [(a[0] * b[0] - a[1] * b[1]) % P, (a[0] * b[1] + a[1] * b[0] + 4 * a[1] * b[1]) % P];
}
long n = power(2, N, (P % 12 == 1 || P % 12 == 11) ? (P - 1) : (P + 1));
long[] x = [0, 1], y = [1, 0];
for (long e = n; e; e >>= 1) {
if (e & 1) {
y = mul(y, x);
}
x = mul(x, x);
}
debug {
writefln("T^%s == %s + %s T (mod T^2 - 4 T + 1)", n, y[0], y[1]);
}
ans = (2 * y[0] + 4 * y[1]) % P;
}
ans -= 2;
ans = (ans % P + P) % P;
writeln(ans);
}
} catch (EOFException e) {
}
}