結果

問題 No.313 π
ユーザー peroonperoon
提出日時 2019-05-09 04:04:00
言語 C++14
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 3 ms / 5,000 ms
コード長 1,240 bytes
コンパイル時間 1,746 ms
コンパイル使用メモリ 168,276 KB
実行使用メモリ 5,376 KB
最終ジャッジ日時 2024-07-02 00:42:30
合計ジャッジ時間 3,459 ms
ジャッジサーバーID
（参考情報） 		judge2 / judge4
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 3 ms
5,248 KB
testcase_01 AC 3 ms
5,376 KB
testcase_02 AC 2 ms
5,376 KB
testcase_03 AC 2 ms
5,376 KB
testcase_04 AC 2 ms
5,376 KB
testcase_05 AC 3 ms
5,376 KB
testcase_06 AC 2 ms
5,376 KB
testcase_07 AC 3 ms
5,376 KB
testcase_08 AC 3 ms
5,376 KB
testcase_09 AC 3 ms
5,376 KB
testcase_10 AC 3 ms
5,376 KB
testcase_11 AC 3 ms
5,376 KB
testcase_12 AC 3 ms
5,376 KB
testcase_13 AC 2 ms
5,376 KB
testcase_14 AC 2 ms
5,376 KB
testcase_15 AC 3 ms
5,376 KB
testcase_16 AC 3 ms
5,376 KB
testcase_17 AC 3 ms
5,376 KB
testcase_18 AC 3 ms
5,376 KB
testcase_19 AC 2 ms
5,376 KB
testcase_20 AC 2 ms
5,376 KB
testcase_21 AC 2 ms
5,376 KB
testcase_22 AC 3 ms
5,376 KB
testcase_23 AC 3 ms
5,376 KB
testcase_24 AC 3 ms
5,376 KB
testcase_25 AC 3 ms
5,376 KB
testcase_26 AC 3 ms
5,376 KB
testcase_27 AC 2 ms
5,376 KB
testcase_28 AC 3 ms
5,376 KB
testcase_29 AC 3 ms
5,376 KB
testcase_30 AC 2 ms
5,376 KB
testcase_31 AC 3 ms
5,376 KB
testcase_32 AC 3 ms
5,376 KB
testcase_33 AC 2 ms
5,376 KB
権限があれば一括ダウンロードができます
コンパイルメッセージ
In file included from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/istream:39,
                 from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/sstream:38,
                 from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/complex:45,
                 from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/ccomplex:39,
                 from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/x86_64-pc-linux-gnu/bits/stdc++.h:54,
                 from main.cpp:1:
In member function 'std::basic_ostream<_CharT, _Traits>::__ostream_type& std::basic_ostream<_CharT, _Traits>::operator<<(long long int) [with _CharT = char; _Traits = std::char_traits<char>]',
    inlined from 'int main()' at main.cpp:58:5:
/home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/ostream:202:25: warning: 'shortage' may be used uninitialized [-Wmaybe-uninitialized]
  202 |       { return _M_insert(__n); }
      |                ~~~~~~~~~^~~~~
main.cpp: In function 'int main()':
main.cpp:48:8: note: 'shortage' was declared here
   48 |     ll shortage;
      |        ^~~~~~~~
In member function 'std::basic_ostream<_CharT, _Traits>::__ostream_type& std::basic_ostream<_CharT, _Traits>::operator<<(long long int) [with _CharT = char; _Traits = std::char_traits<char>]',
    inlined from 'int main()' at main.cpp:58:5:
/home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/ostream:202:25: warning: 'excess' may be used uninitialized [-Wmaybe-uninitialized]
  202 |       { return _M_insert(__n); }
      |                ~~~~~~~~~^~~~~
main.cpp: In function 'int main()':
main.cpp:47:8: note: 'excess' was declared here
   47 |     ll excess;
      |        ^~~~~~

ソースコード

diff # 

#include<bits/stdc++.h>
using namespace std;
using ll = long long;

template<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }
template<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }

#define FOR(i,a,b) for(ll i=(a);i<(b);++i)
#define ALL(v) (v).begin(), (v).end()
#define p(s) cout<<(s)<<endl
#define p2(s, t) cout << (s) << " " << (t) << endl
#define br() p("")
#define pn(s) cout << (#s) << " " << (s) << endl
#define p_yes() p("Yes")
#define p_no() p("No")

const ll mod = 1e9 + 7;
const ll inf = 1e18;

template < typename T >
void vprint(T &V){
	for(auto v : V){
    	cout << v << " ";
	}
	cout << endl;
}

int main(){
    cin.tie(0);
    ios::sync_with_stdio(false);

    // 正しい値
    ll A[10] = {20104, 20063, 19892, 20011, 19874, 20199, 19898, 20163, 19956, 19841};
  
    // input
    string s;
    cin >> s;

    vector<ll> B(10);
    for(char c : s){
        if(isdigit(c)){
            ll v = c - '0';
            B[v]++;
        }
    }

    ll excess;
    ll shortage;
    FOR(i, 0, 10){
        if(A[i]>B[i]){
            shortage = i;
        }
        if(A[i]<B[i]){
            excess = i;
        }
    }

    p2(excess, shortage);
    
    return 0;
}
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