結果

問題 No.697 池の数はいくつか
ユーザー fumiphysfumiphys
提出日時 2019-05-15 23:45:28
言語 C++14
(gcc 12.3.0 + boost 1.83.0)
結果
MLE  
実行時間 -
コード長 4,001 bytes
コンパイル時間 1,624 ms
コンパイル使用メモリ 172,376 KB
実行使用メモリ 814,672 KB
最終ジャッジ日時 2024-11-25 14:56:34
合計ジャッジ時間 52,090 ms
ジャッジサーバーID
(参考情報)
judge2 / judge4
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 3 ms
158,020 KB
testcase_01 AC 2 ms
115,588 KB
testcase_02 AC 2 ms
177,340 KB
testcase_03 AC 2 ms
6,816 KB
testcase_04 AC 2 ms
6,816 KB
testcase_05 AC 2 ms
6,820 KB
testcase_06 AC 2 ms
6,816 KB
testcase_07 AC 2 ms
6,816 KB
testcase_08 AC 2 ms
6,816 KB
testcase_09 AC 2 ms
6,816 KB
testcase_10 AC 2 ms
6,816 KB
testcase_11 AC 2 ms
6,816 KB
testcase_12 AC 3 ms
6,820 KB
testcase_13 AC 2 ms
6,816 KB
testcase_14 AC 2 ms
6,816 KB
testcase_15 AC 2 ms
6,820 KB
testcase_16 AC 2 ms
6,820 KB
testcase_17 AC 2 ms
6,820 KB
testcase_18 AC 2 ms
6,816 KB
testcase_19 AC 3 ms
6,816 KB
testcase_20 AC 3 ms
6,820 KB
testcase_21 AC 3 ms
6,816 KB
testcase_22 AC 3 ms
6,820 KB
testcase_23 AC 2 ms
6,816 KB
testcase_24 AC 752 ms
21,436 KB
testcase_25 AC 1,730 ms
55,024 KB
testcase_26 AC 2,621 ms
136,464 KB
testcase_27 AC 4,116 ms
80,208 KB
testcase_28 AC 1,305 ms
31,160 KB
testcase_29 MLE -
testcase_30 TLE -
testcase_31 MLE -
testcase_32 TLE -
testcase_33 TLE -
testcase_34 TLE -
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ソースコード

diff #

// includes
#include <bits/stdc++.h>

// macros
#define ll long long int
#define pb emplace_back
#define mk make_pair
#define pq priority_queue
#define FOR(i, a, b) for(int i=(a);i<(b);++i)
#define rep(i, n) FOR(i, 0, n)
#define rrep(i, n) for(int i=((int)(n)-1);i>=0;i--)
#define irep(itr, st) for(auto itr = (st).begin(); itr != (st).end(); ++itr)
#define irrep(itr, st) for(auto itr = (st).rbegin(); itr != (st).rend(); ++itr)
#define vrep(v, i) for(int i = 0; i < (v).size(); i++)
#define all(x) (x).begin(),(x).end()
#define sz(x) ((int)(x).size())
#define UNIQUE(v) v.erase(unique(v.begin(), v.end()), v.end())
#define FI first
#define SE second
#define dump(a, n) for(int i = 0; i < n; i++)cout << a[i] << "\n "[i + 1 != n];
#define dump2(a, n, m) for(int i = 0; i < n; i++)for(int j = 0; j < m; j++)cout << a[i][j] << "\n "[j + 1 != m];
#define bit(n) (1LL<<(n))
using namespace std;

//  types
typedef pair<int, int> P;
typedef pair<ll, int> Pl;
typedef pair<ll, ll> Pll;
typedef pair<double, double> Pd;
typedef complex<double> cd;
 
// constants
const int inf = 1e9;
const ll linf = 1LL << 50;
const double EPS = 1e-10;
const int mod = 1e9 + 7;
const int dx[4] = {-1, 0, 1, 0};
const int dy[4] = {0, -1, 0, 1};

// solve
template <class T>bool chmax(T &a, const T &b){if(a < b){a = b; return 1;} return 0;}
template <class T>bool chmin(T &a, const T &b){if(a > b){a = b; return 1;} return 0;}
template <typename T> istream &operator>>(istream &is, vector<T> &vec){for(auto &v: vec)is >> v; return is;}
template <typename T> ostream &operator<<(ostream &os, const vector<T>& vec){for(int i = 0; i < vec.size(); i++){ os << vec[i]; if(i + 1 != vec.size())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const unordered_set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const unordered_multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &p){os << p.first << " " << p.second; return os;}
template <typename T1, typename T2> ostream &operator<<(ostream &os, const map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end(); ++itr){ os << itr->first << ":" << itr->second; auto titr = itr; if(++titr != mp.end())os << " "; } return os;}
template <typename T1, typename T2> ostream &operator<<(ostream &os, const unordered_map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end(); ++itr){ os << itr->first << ":" << itr->second; auto titr = itr; if(++titr != mp.end())os << " "; } return os;}

int a[3001][3001];
int h, w;
bool vis[3001][3001];

void dfs(int i, int j){
}

int main(int argc, char const* argv[])
{
  ios_base::sync_with_stdio(false);
  cin.tie(0);
  cin >> h >> w;
  rep(i, h){
    rep(j, w){
      cin >> a[i][j];
    }
  }
  int res = 0;
  rep(i, h){
    rep(j, w){
      if(!vis[i][j] && a[i][j] == 1){
        res++;
        queue<P> q;
        q.push(mk(i, j));
        while(!q.empty()){
          auto p = q.front(); q.pop();
          int i1 = p.FI;
          int j1 = p.SE;
          vis[i1][j1] = true;
          rep(k, 4){
            int nx = i1 + dx[k];
            int ny = j1 + dy[k];
            if(nx >= 0 && nx < h && ny >= 0 && ny < w && !vis[nx][ny] && a[nx][ny] == 1){
              q.push(mk(nx, ny));
            }
          }
        }
      }
    }
  }
  cout << res << endl;
  return 0;
}

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