#348123 (C++17) No.124 門松列(3)

提出ソース

結果

問題	No.124 門松列(3)
ユーザー	fumiphys
提出日時	2019-05-23 00:26:39
言語	C++17 (gcc 12.3.0 + boost 1.83.0)
結果	AC
実行時間	10 ms / 5,000 ms
コード長	6,175 bytes
コンパイル時間	2,528 ms
コンパイル使用メモリ	218,652 KB
実行使用メモリ	6,944 KB
最終ジャッジ日時	2024-09-17 09:41:37
合計ジャッジ時間	2,990 ms
ジャッジサーバーID （参考情報）	judge6 / judge3

このコードへのチャレンジ
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テストケース

テストケース表示

入力	結果	実行時間実行使用メモリ
testcase_00	AC	5 ms 6,812 KB
testcase_01	AC	2 ms 6,944 KB
testcase_02	AC	2 ms 6,944 KB
testcase_03	AC	6 ms 6,944 KB
testcase_04	AC	10 ms 6,944 KB
testcase_05	AC	9 ms 6,944 KB
testcase_06	AC	2 ms 6,940 KB
testcase_07	AC	2 ms 6,940 KB
testcase_08	AC	1 ms 6,944 KB
testcase_09	AC	1 ms 6,940 KB
testcase_10	AC	2 ms 6,944 KB
testcase_11	AC	2 ms 6,940 KB
testcase_12	AC	2 ms 6,940 KB
testcase_13	AC	2 ms 6,940 KB
testcase_14	AC	1 ms 6,940 KB
testcase_15	AC	1 ms 6,944 KB
testcase_16	AC	2 ms 6,940 KB
testcase_17	AC	2 ms 6,940 KB
testcase_18	AC	2 ms 6,944 KB
testcase_19	AC	2 ms 6,944 KB
testcase_20	AC	2 ms 6,944 KB
testcase_21	AC	2 ms 6,940 KB
testcase_22	AC	2 ms 6,944 KB
testcase_23	AC	4 ms 6,944 KB
testcase_24	AC	6 ms 6,940 KB
testcase_25	AC	6 ms 6,940 KB
testcase_26	AC	3 ms 6,940 KB
testcase_27	AC	2 ms 6,940 KB
testcase_28	AC	9 ms 6,940 KB
testcase_29	AC	9 ms 6,940 KB

権限があれば一括ダウンロードができます

ソースコード

raw source code

// includes
#include <bits/stdc++.h>

// macros
#define ll long long int
#define pb emplace_back
#define mk make_pair
#define pq priority_queue
#define FOR(i, a, b) for(int i=(a);i<(b);++i)
#define rep(i, n) FOR(i, 0, n)
#define rrep(i, n) for(int i=((int)(n)-1);i>=0;i--)
#define irep(itr, st) for(auto itr = (st).begin(); itr != (st).end(); ++itr)
#define irrep(itr, st) for(auto itr = (st).rbegin(); itr != (st).rend(); ++itr)
#define vrep(v, i) for(int i = 0; i < (v).size(); i++)
#define all(x) (x).begin(),(x).end()
#define sz(x) ((int)(x).size())
#define UNIQUE(v) v.erase(unique(v.begin(), v.end()), v.end())
#define FI first
#define SE second
#define dump(a, n) for(int i = 0; i < n; i++)cout << a[i] << "\n "[i + 1 != n];
#define dump2(a, n, m) for(int i = 0; i < n; i++)for(int j = 0; j < m; j++)cout << a[i][j] << "\n "[j + 1 != m];
#define bit(n) (1LL<<(n))
#define INT(n) int n; cin >> n;
#define LL(n) ll n; cin >> n;
#define DOUBLE(n) double n; cin >> n;
using namespace std;

//  types
typedef pair<int, int> P;
typedef pair<ll, int> Pl;
typedef pair<ll, ll> Pll;
typedef pair<double, double> Pd;
typedef complex<double> cd;
 
// constants
const int inf = 1e9;
const ll linf = 1LL << 50;
const double EPS = 1e-10;
const int mod = 1e9 + 7;
const int dx[4] = {-1, 0, 1, 0};
const int dy[4] = {0, -1, 0, 1};

// solve
template <class T>bool chmax(T &a, const T &b){if(a < b){a = b; return 1;} return 0;}
template <class T>bool chmin(T &a, const T &b){if(a > b){a = b; return 1;} return 0;}
template <typename T> istream &operator>>(istream &is, vector<T> &vec){for(auto &v: vec)is >> v; return is;}
template <typename T> ostream &operator<<(ostream &os, const vector<T>& vec){for(int i = 0; i < vec.size(); i++){ os << vec[i]; if(i + 1 != vec.size())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const unordered_set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const unordered_multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &p){os << p.first << " " << p.second; return os;}
template <typename T1, typename T2> ostream &operator<<(ostream &os, const map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end(); ++itr){ os << itr->first << ":" << itr->second; auto titr = itr; if(++titr != mp.end())os << " "; } return os;}
template <typename T1, typename T2> ostream &operator<<(ostream &os, const unordered_map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end(); ++itr){ os << itr->first << ":" << itr->second; auto titr = itr; if(++titr != mp.end())os << " "; } return os;}

template <typename T>
struct Graph_ {
  int n;
  vector<vector<pair<int, T> > > edge;
  vector<T> dis;
  Graph_(int ns) {
    n = ns;
    edge.resize(n);
    dis.resize(n);
  }
  void dijkstra(int s){
    dijkstra(s, 0);
  }
  T dijkstra(int s, int t){
    // initialize
    fill(dis.begin(), dis.end(), -1);
    vector<bool> used;
    used.resize(n);
    fill(used.begin(), used.end(), false);
    dis[s] = 0;
    // dijkstra
    priority_queue<pair<T, int>, vector<pair<T, int> >, greater<pair<T, int> > > q;
    q.push(make_pair(0, s));
    while(!q.empty()){
      pair<T, int> p = q.top(); q.pop();
      int at = p.second;
      T distance = p.first;
      if(used[at])continue;
      used[at] = true;
      for(auto itr = edge[at].begin(); itr != edge[at].end(); ++itr){
        int to = (*itr).first;
        T cost = (*itr).second;
        if(used[to])continue;
        if(dis[to] == -1 || dis[to] > distance + cost){
          q.push(make_pair(distance + cost, to));
          dis[to] = distance + cost;
        }
      }
    }
    return dis[t];
  }
  void adde(int at, int to, T cost){
    edge[at].push_back(make_pair(to, cost));
  }
  [[deprecated("This function takes O(edge[at].size()).")]]
    void remove(int at, int to){
      int index = -1;
      for(int i = 0; i < edge[at].size(); i++){
        if(edge[at][i].first == to){
          index = i;
          break;
        }
      }
      edge[at].erase(edge[at].begin() + index);
    }
};

typedef struct Graph_<int> GraphI;
typedef struct Graph_<ll> GraphL;
typedef struct Graph_<double> GraphD;

int w, h;
int a[101][101];

bool ok(int a, int b, int c){
  if(a == 0 || b == 0)return true;
  if(a == b || b == c || c == a)return false;
  if(a < b && b < c)return false;
  if(c < b && b < a)return false;
  return true;
}

int index(int i, int j, int k){
  return k * w * h + i * w + j;
}

bool oki(int i, int j){
  if(i >= 0 && i < h && j >= 0 && j < w)return true;
  return false;
}

int main(int argc, char const* argv[])
{
  ios_base::sync_with_stdio(false);
  cin.tie(0);
  cin >> w >> h;
  rep(i, h){
    rep(j, w)cin >> a[i][j];
  }
  GraphI graph(h * w * 10);
  graph.adde(0, index(0, 1, a[0][0]), 1);
  graph.adde(0, index(1, 0, a[0][0]), 1);
  rep(i, h){
    rep(j, w){
      rep(k, 4){
        rep(l, 4){
          int kx = i + dx[k];
          int ky = j + dy[k];
          int lx = i + dx[l];
          int ly = j + dy[l];
          if(oki(kx, ky) && oki(lx, ly)){
            int from = a[kx][ky];
            int to = a[lx][ly];
            if(ok(from, a[i][j], to)){
              graph.adde(index(i, j, a[kx][ky]), index(lx, ly, a[i][j]), 1);
            }
          }
        }
      }
    }
  }

  graph.dijkstra(0);
  int res = inf;
  FOR(i, 1, 10){
    if(graph.dis[index(h-1, w-1, i)] >= 0)res = min(res, graph.dis[index(h-1, w-1, i)]);
  }
  if(res == inf)cout << -1 << endl;
  else cout << res << endl;
  return 0;
}

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結果

テストケース

ソースコード