結果

問題 No.833 かっこいい電車
ユーザー hitonanodehitonanode
提出日時 2019-05-24 21:53:43
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 77 ms / 2,000 ms
コード長 4,284 bytes
コンパイル時間 1,624 ms
コンパイル使用メモリ 176,584 KB
実行使用メモリ 8,832 KB
最終ジャッジ日時 2024-07-02 03:41:02
合計ジャッジ時間 3,909 ms
ジャッジサーバーID
（参考情報） 		judge5 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2
other AC * 30
権限があれば一括ダウンロードができます

ソースコード

diff # 

#include <bits/stdc++.h>
using namespace std;
using lint = long long int;
using pint = pair<int, int>;
using plint = pair<lint, lint>;
struct fast_ios { fast_ios(){ cin.tie(0); ios::sync_with_stdio(false); cout << fixed << setprecision(20); }; } fast_ios_;
#define FOR(i, begin, end) for(int i=(begin),i##_end_=(end);i<i##_end_;i++)
#define IFOR(i, begin, end) for(int i=(end)-1,i##_begin_=(begin);i>=i##_begin_;i--)
#define REP(i, n) FOR(i,0,n)
#define IREP(i, n) IFOR(i,0,n)
template<typename T> istream &operator>>(istream &is, vector<T> &vec){ for (auto &v : vec) is >> v; return is; }
template<typename T> ostream &operator<<(ostream &os, const vector<T> &vec){ os << "["; for (auto v : vec) os << v << ","; os << "]"; return os; }
template<typename T> ostream &operator<<(ostream &os, const deque<T> &vec){ os << "deq["; for (auto v : vec) os << v << ","; os << "]"; return os; }
template<typename T> ostream &operator<<(ostream &os, const set<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; }
template<typename T> ostream &operator<<(ostream &os, const unordered_set<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; }
template<typename T> ostream &operator<<(ostream &os, const multiset<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; }
template<typename T> ostream &operator<<(ostream &os, const unordered_multiset<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; }
template<typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &pa){ os << "(" << pa.first << "," << pa.second << ")"; return os; }
template<typename TK, typename TV> ostream &operator<<(ostream &os, const map<TK, TV> &mp){ os << "{"; for (auto v : mp) os << v.first << "=>" << v.second << ","; os << "}"; return os; }
template<typename TK, typename TV> ostream &operator<<(ostream &os, const unordered_map<TK, TV> &mp){ os << "{"; for (auto v : mp) os << v.first << "=>" << v.second << ","; os << "}"; return os; }
template<typename T> void ndarray(vector<T> &vec, int len) { vec.resize(len); }
template<typename T, typename... Args> void ndarray(vector<T> &vec, int len, Args... args) { vec.resize(len); for (auto &v : vec) ndarray(v, args...); }
template<typename T> bool mmax(T &m, const T q) { if (m < q) {m = q; return true;} else return false; }
template<typename T> bool mmin(T &m, const T q) { if (m > q) {m = q; return true;} else return false; }
template<typename T1, typename T2> pair<T1, T2> operator+(const pair<T1, T2> &l, const pair<T1, T2> &r) { return make_pair(l.first + r.first, l.second + r.second); }
template<typename T1, typename T2> pair<T1, T2> operator-(const pair<T1, T2> &l, const pair<T1, T2> &r) { return make_pair(l.first - r.first, l.second - r.second); }
#define dbg(x) cerr << #x << " = " << (x) << " (L" << __LINE__ << ") " << __FILE__ << endl;
#define FI first
#define SE second
#define ALL(x) (x).begin(), (x).end()
#define SZ(x) ((lint)(x).size())
#define POW2(n) (1LL << (n))

// 1-indexed BIT (i : [1, len])
template<typename T>
struct BIT
{
    int len;
    vector<T> val;
    BIT(int num) : len(num), val(num + 1) {}
    BIT() : BIT(0) {}
    void reset() { fill(val.begin(), val.end(), 0); }
    void add(int pos, T v) { while (pos > 0 and pos <= len) val[pos] += v, pos += pos & -pos; }
    T sum(int pos) const // (0, pos]
    {
        T res = 0;
        while (pos > 0) res += val[pos], pos -= pos & -pos;
        return res;
    }
};
template<typename T> ostream &operator<<(ostream &os, const BIT<T> &b){ T prv = 0; os << "["; REP(i, b.len) { T nxt = b.sum(i + 1); os << nxt - prv << ","; prv = nxt; } os << "]"; return os; }

int N, Q;

int main()
{
    cin >> N >> Q;
    BIT<lint> bit(N + 1);
    REP(i, N)
    {
        lint A;
        cin >> A;
        bit.add(i + 1, A);
    }
    set<int> cut;
    REP(i, N + 2) cut.insert(i);
    REP(_, Q)
    {
        int q;
        lint x;
        cin >> q >> x;
        if (q == 3) bit.add(x, 1);
        if (q == 1) cut.erase(x);
        if (q == 2) cut.insert(x);
        if (q == 4)
        {
            auto itr = cut.lower_bound(x);
            auto r = *itr;
            auto l = *prev(itr);
            printf("%lld\n", bit.sum(r) - bit.sum(l));
        }
    }
}
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