結果

問題 No.803 Very Limited Xor Subset
ユーザー tpyneriver
提出日時 2019-05-30 13:34:05
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 95 ms / 2,000 ms
コード長 3,678 bytes
コンパイル時間 170 ms
コンパイル使用メモリ 82,284 KB
実行使用メモリ 76,684 KB
最終ジャッジ日時 2024-09-17 16:06:24
合計ジャッジ時間 4,921 ms
ジャッジサーバーID
(参考情報)
judge2 / judge4
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 4
other AC * 43
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

class GE():
#mod2  A1, max(bit_length) M
def __init__(self, A, mod, M = 0):
self.N = len(A)
if M:
self.M = M
else:
self.M = len(A[0])
self.mod = mod
self.A = A[:]
self.uptri = None
self.A2 = None
self.pivot = []
self.R = None
def ut(self):
if self.mod != 2:
if self.uptri is not None:
return self.uptri
self.uptri = self.A[:]
c = 0
for i in range(self.N):
if i + c >= self.M:
break
while self.uptri[i][i+c] == 0:
for j in range(i+1, self.N):
if self.uptri[j][i+c]:
self.uptri[i], self.uptri[j] = self.uptri[j], self.uptri[i]
break
else:
c += 1
if i + c == self.M:
break
else:
self.pivot.append((i, i+c))
t = pow(self.uptri[i][i+c], self.mod - 2, self.mod)
for j in range(i+1, self.N):
tj = t * self.uptri[j][i+c]
self.uptri[j][i+c:] = [(aj - tj*ai) % self.mod for ai, aj in zip(self.uptri[i][i+c:], self.uptri[j][i+c:])]
continue
break
for pi, pj in self.pivot[::-1]:
t = pow(self.uptri[pi][pj], self.mod-2, self.mod)
self.uptri[pi][pj:] = [(ai * t) % self.mod for ai in self.uptri[pi][pj:]]
for i in range(pi-1, -1, -1):
ti = self.uptri[i][pj]
self.uptri[i][pj:] = [(ai - api*ti) % self.mod for ai, api in zip(self.uptri[i][pj:], self.uptri[pi][pj:])]
return self.uptri
else:
if self.A2 is not None:
return self.A2
self.A2 = self.A[:]
c = 0
for i in range(self.N):
if i + c >= self.M:
break
while not self.A2[i] & 2**(i+c):
for j in range(i+1, self.N):
if self.A2[j] & 2**(i+c):
self.A2[i], self.A2[j] = self.A2[j], self.A2[i]
break
else:
c += 1
if i + c == self.M:
break
else:
self.pivot.append((i, i+c))
for j in range(i+1, self.N):
if self.A2[j] & 2**(i+c):
self.A2[j] ^= self.A2[i]
continue
break
for pi, pj in self.pivot[::-1]:
for i in range(pi-1, -1, -1):
if 2**pj & self.A2[i]:
self.A2[i] ^= self.A2[pi]
return self.A2
def rank(self):
if self.R is not None:
return self.R
self.ut()
self.R = len(self.pivot)
return self.R
import sys
N, M, X = map(int, input().split())
mod = 10**9+7
A = list(map(int,input().split())) + [X]
AM = [sum(2**j if 2**i & a else 0 for j, a in enumerate(A)) for i in range(30)]
for _ in range(M):
t, l, r = map(int, sys.stdin.readline().split())
AM.append(2**r - 2**(l-1) + 2**N*t)
T = GE(AM, 2, N+1)
ans = 0
for u in T.ut():
if u == 2**N:
break
else:
ans = pow(2, N-T.rank(), mod)
print(ans)
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