結果
問題 | No.654 Air E869120 |
ユーザー |
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提出日時 | 2019-06-14 18:11:33 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 40 ms / 2,000 ms |
コード長 | 2,689 bytes |
コンパイル時間 | 2,235 ms |
コンパイル使用メモリ | 187,240 KB |
実行使用メモリ | 6,824 KB |
最終ジャッジ日時 | 2024-11-08 02:51:41 |
合計ジャッジ時間 | 3,809 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge3 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 5 |
other | AC * 35 |
ソースコード
#include <math.h>#include <bits/stdc++.h>//一括で読み込みtypedef long long ll;using namespace std;struct flowEdge{ll to, cap, rev;};class Max_Flow//最大流問題のDinic法。頂点数10^3,辺数10^4程度なら大体間に合う{public:vector<vector<flowEdge>> G;vector<ll>level, iter;void init(ll size_){G.resize(size_);level.resize(size_);iter.resize(size_);}void add_flowEdge(ll from, ll to, ll cap){G[from].push_back(flowEdge{to, cap, (ll)G[to].size()});G[to].push_back(flowEdge{from, 0, (ll)G[from].size()-1});}void bfs(ll s){for (ll i = 0; i < level.size(); i++) level[i] = -1;queue<ll> que;level[s] = 0;que.push(s);while (!que.empty()){ll v = que.front(); que.pop();for (ll i = 0; i < G[v].size(); i++){flowEdge &e = G[v][i];if (e.cap > 0 && level[e.to] < 0){level[e.to] = level[v] + 1;que.push(e.to);}}}}ll dfs(ll v, ll t, ll f){if (v == t) return f;for (ll &i = iter[v]; i < G[v].size(); i++){flowEdge &e = G[v][i];if (e.cap > 0 && level[v] < level[e.to]){ll d = dfs(e.to, t, min(f, e.cap));if (d > 0) {e.cap -= d;G[e.to][e.rev].cap += d;return d;}}}return 0;}ll max_flow(ll s, ll t){ll flow = 0;for(;;){bfs(s);if (level[t] < 0) return flow;for (int i = 0; i < iter.size(); i++) iter[i] = 0;ll f;while ((f = dfs(s, t, (1LL<<60))) > 0){flow += f;}}}};ll n, m, d, u[1009], v[1009], p[1009], q[1009], w[1009];vector<pair<ll, ll>> L;//最大流の頂点int main(){cin >> n >> m >> d;for (int i = 0; i < m; i++)//辺数{cin >> u[i] >> v[i] >> p[i] >> q[i] >> w[i];q[i] += d;L.push_back(make_pair(u[i], p[i]));//出発座標と時刻L.push_back(make_pair(v[i], q[i]));//到着座標と時刻}sort(L.begin(), L.end());Max_Flow X;X.init(L.size()+2);//頂点数で初期化for (int i = 0; i < m; i++){int pos1 = lower_bound(L.begin(), L.end(), make_pair(u[i], p[i])) - L.begin();//ソート後の頂点番号を求めるint pos2 = lower_bound(L.begin(), L.end(), make_pair(v[i], q[i])) - L.begin();X.add_flowEdge(pos1, pos2, w[i]);//つなぐ頂点とコスト}for (int i = 1; i < L.size(); i++){if (L[i-1].first == L[i].first) X.add_flowEdge(i-1, i, (1LL<<60));}if(L[0].first == 1) X.add_flowEdge(L.size(), 0, (1LL<<60));if(L[L.size()-1].first == n) X.add_flowEdge(L.size()-1, L.size()+1, (1LL<<60));cout << X.max_flow(L.size(), L.size()+1) << endl;//開始頂点から終了頂点までの最大流を求めるreturn 0;}