結果

問題 No.238 Mr. K's Another Gift
ユーザー torus711
提出日時 2015-07-05 23:37:58
言語 C++11(廃止可能性あり)
(gcc 13.3.0)
結果
WA  
実行時間 -
コード長 3,167 bytes
コンパイル時間 815 ms
コンパイル使用メモリ 99,016 KB
実行使用メモリ 6,216 KB
最終ジャッジ日時 2024-07-08 00:56:17
合計ジャッジ時間 3,155 ms
ジャッジサーバーID
(参考情報)
judge5 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2 WA * 1
other AC * 34 WA * 6
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <iostream>
#include <iomanip>
#include <sstream>
#include <vector>
#include <string>
#include <set>
#include <unordered_set>
#include <map>
#include <unordered_map>
#include <stack>
#include <queue>
#include <deque>
#include <algorithm>
#include <functional>
#include <iterator>
#include <limits>
#include <numeric>
#include <utility>
#include <cmath>
#include <cassert>
#include <cstdio>
using namespace std; using namespace placeholders;
using LL = long long;
using ULL = unsigned long long;
using VI = vector< int >;
using VVI = vector< vector< int > >;
using VS = vector< string >;
using SS = stringstream;
using PII = pair< int, int >;
using VPII = vector< pair< int, int > >;
template < typename T = int > using VT = vector< T >;
template < typename T = int > using VVT = vector< vector< T > >;
template < typename T = int > using LIM = numeric_limits< T >;
template < typename T > inline istream& operator>>( istream &s, vector< T > &v ){ for ( T &t : v ) { s >> t; } return s; }
template < typename T > inline ostream& operator<<( ostream &s, const vector< T > &v ){ for ( int i = 0; i < int( v.size() ); ++i ){ s << ( " " + !i
    ) << v[i]; } return s; }
template < typename T > inline T fromString( const string &s ) { T res; istringstream iss( s ); iss >> res; return res; };
template < typename T > inline string toString( const T &a ) { ostringstream oss; oss << a; return oss.str(); };
#define REP2( i, n ) REP3( i, 0, n )
#define REP3( i, m, n ) for ( int i = ( int )( m ); i < ( int )( n ); ++i )
#define GET_REP( a, b, c, F, ... ) F
#define REP( ... ) GET_REP( __VA_ARGS__, REP3, REP2 )( __VA_ARGS__ )
#define FOR( e, c ) for ( auto &e : c )
#define ALL( c ) ( c ).begin(), ( c ).end()
#define AALL( a, t ) ( t* )a, ( t* )a + sizeof( a ) / sizeof( t )
#define DRANGE( c, p ) ( c ).begin(), ( c ).begin() + ( p ), ( c ).end()
#define SZ( v ) ( (int)( v ).size() )
#define PB push_back
#define EM emplace
#define EB emplace_back
#define BI back_inserter
#define EXIST( c, e ) ( ( c ).find( e ) != ( c ).end() )
#define MP make_pair
#define fst first
#define snd second
#define DUMP( x ) cerr << #x << " = " << ( x ) << endl
string solve( const string &a, const string &b )
{
const int N = SZ( a ), M = SZ( b );
VVI dp( M + 1, VI( 2 ) );
dp[0][0] = 1;
// dp[ b ][ b ]
REP( i, M )
{
dp[i][1] |= dp[i][0];
REP( j, 2 )
{
if ( a[ i + j ] == b[i] )
{
dp[ i + 1 ][j] |= dp[i][j];
}
}
}
return dp[M][1] ? a : "";
}
int main()
{
cin.tie( 0 );
ios::sync_with_stdio( false );
string S;
cin >> S;
const int L = SZ( S );
if ( L % 2 == 0 && equal( ALL( S ), S.rbegin() ) )
{
S.insert( L / 2, "a" );
cout << S << endl;
return 0;
}
REP( i, 2 )
{
string a = S.substr( 0, ( L - 1 ) / 2 + i );
string b = S.substr( ( L - 1 ) / 2 + ( L - 1 ) % 2 + i );
reverse( ALL( a ) );
string res = SZ( a ) < SZ( b ) ? solve( b, a ) : solve( a, b );
if ( res != "" )
{
string rev( res );
reverse( ALL( rev ) );
if ( L % 2 == 0 )
{
rev += S[ L / 2 ];
}
rev += res;
cout << rev << endl;
return 0;
}
}
cout << "NA" << endl;
return 0;
}
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