結果
| 問題 |
No.844 split game
|
| コンテスト | |
| ユーザー |
MarcusAureliusAntoninus
|
| 提出日時 | 2019-06-28 22:09:24 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 67 ms / 2,000 ms |
| コード長 | 841 bytes |
| コンパイル時間 | 2,207 ms |
| コンパイル使用メモリ | 198,728 KB |
| 最終ジャッジ日時 | 2025-01-07 05:32:43 |
|
ジャッジサーバーID (参考情報) |
judge3 / judge1 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 4 |
| other | AC * 56 |
コンパイルメッセージ
main.cpp: In function ‘int main()’:
main.cpp:15:31: warning: format ‘%lld’ expects argument of type ‘long long int*’, but argument 4 has type ‘int64_t*’ {aka ‘long int*’} [-Wformat=]
15 | scanf("%d%d%lld", &l, &r, &p);
| ~~~^ ~~
| | |
| | int64_t* {aka long int*}
| long long int*
| %ld
main.cpp:35:20: warning: format ‘%lld’ expects argument of type ‘long long int’, but argument 2 has type ‘__gnu_cxx::__alloc_traits<std::allocator<long int>, long int>::value_type’ {aka ‘long int’} [-Wformat=]
35 | printf("%lld\n", maxDP.back());
| ~~~^ ~~~~~~~~~~~~
| | |
| long long int __gnu_cxx::__alloc_traits<std::allocator<long int>, long int>::value_type {aka long int}
| %ld
main.cpp:6:14: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
6 | scanf("%d%d%d", &N, &M, &A);
| ~~~~~^~~~~~~~~~~~~~~~~~~~~~
main.cpp:15:22: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
15 | scanf("%d%d%lld", &l, &r, &p);
| ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~
ソースコード
#include <bits/stdc++.h>
int main()
{
int N, M, A;
scanf("%d%d%d", &N, &M, &A);
using vpi = std::vector<std::pair<int, int64_t>>;
using vvpi = std::vector<vpi>;
vvpi spans(N + 1);
for (int i{}; i < M; i++)
{
int l, r;
int64_t p;
scanf("%d%d%lld", &l, &r, &p);
spans[r].push_back({l, p});
}
std::vector<int64_t> dp(N + 1, -(1ll << 60));
std::vector<int64_t> maxDP(N + 1);
dp[0] = 0;
for (int i{1}; i <= N; i++)
{
for (auto& e: spans[i])
{
int64_t last_bonus{};
if (i == N) last_bonus += A;
if (dp[e.first - 1] != -(1ll << 60))
dp[i] = std::max(dp[i], dp[e.first - 1] + e.second - A + last_bonus);
if (e.first > 1)
dp[i] = std::max(dp[i], maxDP[e.first - 2] + e.second - 2 * A + last_bonus);
}
maxDP[i] = std::max({maxDP[i - 1], dp[i]});
}
printf("%lld\n", maxDP.back());
return 0;
}
MarcusAureliusAntoninus