結果
問題 | No.844 split game |
ユーザー | MarcusAureliusAntoninus |
提出日時 | 2019-06-28 22:09:24 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 67 ms / 2,000 ms |
コード長 | 841 bytes |
コンパイル時間 | 2,207 ms |
コンパイル使用メモリ | 198,728 KB |
最終ジャッジ日時 | 2025-01-07 05:32:43 |
ジャッジサーバーID (参考情報) |
judge3 / judge1 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 4 |
other | AC * 56 |
コンパイルメッセージ
main.cpp: In function ‘int main()’: main.cpp:15:31: warning: format ‘%lld’ expects argument of type ‘long long int*’, but argument 4 has type ‘int64_t*’ {aka ‘long int*’} [-Wformat=] 15 | scanf("%d%d%lld", &l, &r, &p); | ~~~^ ~~ | | | | | int64_t* {aka long int*} | long long int* | %ld main.cpp:35:20: warning: format ‘%lld’ expects argument of type ‘long long int’, but argument 2 has type ‘__gnu_cxx::__alloc_traits<std::allocator<long int>, long int>::value_type’ {aka ‘long int’} [-Wformat=] 35 | printf("%lld\n", maxDP.back()); | ~~~^ ~~~~~~~~~~~~ | | | | long long int __gnu_cxx::__alloc_traits<std::allocator<long int>, long int>::value_type {aka long int} | %ld main.cpp:6:14: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 6 | scanf("%d%d%d", &N, &M, &A); | ~~~~~^~~~~~~~~~~~~~~~~~~~~~ main.cpp:15:22: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 15 | scanf("%d%d%lld", &l, &r, &p); | ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~
ソースコード
#include <bits/stdc++.h> int main() { int N, M, A; scanf("%d%d%d", &N, &M, &A); using vpi = std::vector<std::pair<int, int64_t>>; using vvpi = std::vector<vpi>; vvpi spans(N + 1); for (int i{}; i < M; i++) { int l, r; int64_t p; scanf("%d%d%lld", &l, &r, &p); spans[r].push_back({l, p}); } std::vector<int64_t> dp(N + 1, -(1ll << 60)); std::vector<int64_t> maxDP(N + 1); dp[0] = 0; for (int i{1}; i <= N; i++) { for (auto& e: spans[i]) { int64_t last_bonus{}; if (i == N) last_bonus += A; if (dp[e.first - 1] != -(1ll << 60)) dp[i] = std::max(dp[i], dp[e.first - 1] + e.second - A + last_bonus); if (e.first > 1) dp[i] = std::max(dp[i], maxDP[e.first - 2] + e.second - 2 * A + last_bonus); } maxDP[i] = std::max({maxDP[i - 1], dp[i]}); } printf("%lld\n", maxDP.back()); return 0; }