結果

問題 No.848 なかよし旅行
ユーザー fumiphysfumiphys
提出日時 2019-07-07 15:12:01
言語 C++14
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 93 ms / 2,000 ms
コード長 5,606 bytes
コンパイル時間 2,230 ms
コンパイル使用メモリ 187,844 KB
実行使用メモリ 10,652 KB
最終ジャッジ日時 2024-11-08 00:58:39
合計ジャッジ時間 3,880 ms
ジャッジサーバーID
（参考情報） 		judge3 / judge5
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 93 ms
10,652 KB
testcase_01 AC 2 ms
5,248 KB
testcase_02 AC 2 ms
5,248 KB
testcase_03 AC 2 ms
5,248 KB
testcase_04 AC 2 ms
5,248 KB
testcase_05 AC 2 ms
5,248 KB
testcase_06 AC 2 ms
5,248 KB
testcase_07 AC 2 ms
5,248 KB
testcase_08 AC 2 ms
5,248 KB
testcase_09 AC 3 ms
5,248 KB
testcase_10 AC 3 ms
5,248 KB
testcase_11 AC 21 ms
5,248 KB
testcase_12 AC 26 ms
5,504 KB
testcase_13 AC 33 ms
6,272 KB
testcase_14 AC 14 ms
5,248 KB
testcase_15 AC 31 ms
6,400 KB
testcase_16 AC 49 ms
8,192 KB
testcase_17 AC 35 ms
7,168 KB
testcase_18 AC 19 ms
5,248 KB
testcase_19 AC 17 ms
5,248 KB
testcase_20 AC 11 ms
5,248 KB
testcase_21 AC 40 ms
7,168 KB
testcase_22 AC 39 ms
7,424 KB
testcase_23 AC 10 ms
5,248 KB
testcase_24 AC 2 ms
5,248 KB
testcase_25 AC 55 ms
7,936 KB
testcase_26 AC 2 ms
5,248 KB
testcase_27 AC 2 ms
5,248 KB
testcase_28 AC 2 ms
5,248 KB
testcase_29 AC 2 ms
5,248 KB
権限があれば一括ダウンロードができます

ソースコード

diff # 

// includes
#include <bits/stdc++.h>

// macros
#define ll long long int
#define pb emplace_back
#define mk make_pair
#define pq priority_queue
#define FOR(i, a, b) for(int i=(a);i<(b);++i)
#define rep(i, n) FOR(i, 0, n)
#define rrep(i, n) for(int i=((int)(n)-1);i>=0;i--)
#define irep(itr, st) for(auto itr = (st).begin(); itr != (st).end(); ++itr)
#define irrep(itr, st) for(auto itr = (st).rbegin(); itr != (st).rend(); ++itr)
#define vrep(v, i) for(int i = 0; i < (v).size(); i++)
#define all(x) (x).begin(),(x).end()
#define sz(x) ((int)(x).size())
#define UNIQUE(v) v.erase(unique(v.begin(), v.end()), v.end())
#define FI first
#define SE second
#define dump(a, n) for(int i = 0; i < n; i++)cout << a[i] << "\n "[i + 1 != n];
#define dump2(a, n, m) for(int i = 0; i < n; i++)for(int j = 0; j < m; j++)cout << a[i][j] << "\n "[j + 1 != m];
#define bit(n) (1LL<<(n))
#define INT(n) int n; cin >> n;
#define LL(n) ll n; cin >> n;
#define DOUBLE(n) double n; cin >> n;
using namespace std;

//  types
typedef pair<int, int> P;
typedef pair<ll, int> Pl;
typedef pair<ll, ll> Pll;
typedef pair<double, double> Pd;
typedef complex<double> cd;

// constants
const int inf = 1e9;
const ll linf = 1LL << 50;
const double EPS = 1e-10;
const int mod = 1e9 + 7;
const int dx[4] = {-1, 0, 1, 0};
const int dy[4] = {0, -1, 0, 1};

// solve
template <class T>bool chmax(T &a, const T &b){if(a < b){a = b; return 1;} return 0;}
template <class T>bool chmin(T &a, const T &b){if(a > b){a = b; return 1;} return 0;}
template <typename T> istream &operator>>(istream &is, vector<T> &vec){for(auto &v: vec)is >> v; return is;}
template <typename T> ostream &operator<<(ostream &os, const vector<T>& vec){for(int i = 0; i < vec.size(); i++){ os << vec[i]; if(i + 1 != vec.size())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const unordered_set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const unordered_multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &p){os << p.first << " " << p.second; return os;}
template <typename T1, typename T2> ostream &operator<<(ostream &os, const map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end(); ++itr){ os << itr->first << ":" << itr->second; auto titr = itr; if(++titr != mp.end())os << " "; } return os;}
template <typename T1, typename T2> ostream &operator<<(ostream &os, const unordered_map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end(); ++itr){ os << itr->first << ":" << itr->second; auto titr = itr; if(++titr != mp.end())os << " "; } return os;}

template <typename T>
struct Graph_ {
  int n;
  vector<vector<pair<int, T> > > edge;
  vector<T> dis;
  Graph_(int ns) {
    n = ns;
    edge.resize(n);
    dis.resize(n);
  }
  void dijkstra(int s){
    dijkstra(s, 0);
  }
  T dijkstra(int s, int t){
    // initialize
    fill(dis.begin(), dis.end(), -1);
    vector<bool> used;
    used.resize(n);
    fill(used.begin(), used.end(), false);
    dis[s] = 0;
    // dijkstra
    priority_queue<pair<T, int>, vector<pair<T, int> >, greater<pair<T, int> > > q;
    q.push(make_pair(0, s));
    while(!q.empty()){
      pair<T, int> p = q.top(); q.pop();
      int at = p.second;
      T distance = p.first;
      if(used[at])continue;
      used[at] = true;
      for(auto itr = edge[at].begin(); itr != edge[at].end(); ++itr){
        int to = (*itr).first;
        T cost = (*itr).second;
        if(used[to])continue;
        if(dis[to] == -1 || dis[to] > distance + cost){
          q.push(make_pair(distance + cost, to));
          dis[to] = distance + cost;
        }
      }
    }
    return dis[t];
  }
  void adde(int at, int to, T cost){
    edge[at].push_back(make_pair(to, cost));
  }
  [[deprecated("This function takes O(edge[at].size()).")]]
  void remove(int at, int to){
    int index = -1;
    for(int i = 0; i < edge[at].size(); i++){
      if(edge[at][i].first == to){
        index = i;
        break;
      }
    }
    edge[at].erase(edge[at].begin() + index);
  }
};

typedef struct Graph_<int> GraphI;
typedef struct Graph_<ll> GraphL;
typedef struct Graph_<double> GraphD;

int main(int argc, char const* argv[])
{
  ios_base::sync_with_stdio(false);
  cin.tie(0);
  cout << fixed << setprecision(20);
  INT(n); INT(m); INT(p); INT(q); LL(t); p--; q--;
  GraphL graph(n);
  rep(i, m){
    INT(a); INT(b); LL(c); a--; b--;
    graph.adde(a, b, c);
    graph.adde(b, a, c);
  }
  graph.dijkstra(0); vector<ll> diso = graph.dis;
  graph.dijkstra(p); vector<ll> disp = graph.dis;
  graph.dijkstra(q); vector<ll> disq = graph.dis;
  ll res = -1;
  if(diso[p] + disp[q] + disq[0] <= t || diso[q] + disq[p] + disp[0] <= t){
    cout << t << endl;
    return 0;
  }
  rep(i, n){
    rep(j, n){
      ll tmp = max(disp[i] + disp[j], disq[i] + disq[j]);
      if(tmp + diso[i] + diso[j] > t)continue;
      res = max(res, t - tmp);
    }
  }
  cout << res << endl;
  return 0;
}
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