結果

問題 No.92 逃走経路
ユーザー bal4u
提出日時 2019-07-11 21:32:34
言語 C
(gcc 13.3.0)
結果
RE  
(最新)
AC  
(最初)
実行時間 -
コード長 2,071 bytes
コンパイル時間 959 ms
コンパイル使用メモリ 32,376 KB
実行使用メモリ 7,168 KB
最終ジャッジ日時 2024-11-08 10:57:24
合計ジャッジ時間 2,015 ms
ジャッジサーバーID
(参考情報)
judge3 / judge1
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 2
other AC * 17 RE * 1
権限があれば一括ダウンロードができます
コンパイルメッセージ
main.c: In function 'in':
main.c:8:14: warning: implicit declaration of function 'getchar_unlocked' [-Wimplicit-function-declaration]
    8 | #define gc() getchar_unlocked()
      |              ^~~~~~~~~~~~~~~~
main.c:16:24: note: in expansion of macro 'gc'
   16 |         int n = 0, c = gc();
      |                        ^~
main.c: In function 'out':
main.c:9:15: warning: implicit declaration of function 'putchar_unlocked' [-Wimplicit-function-declaration]
    9 | #define pc(c) putchar_unlocked(c)
      |               ^~~~~~~~~~~~~~~~
main.c:26:21: note: in expansion of macro 'pc'
   26 |         while (i--) pc(b[i]);
      |                     ^~

ソースコード

diff #
プレゼンテーションモードにする

// yukicoder: No.92
// 2019.7.11 bal4u
#include <stdio.h>
#include <stdlib.h>
#if 1
#define gc() getchar_unlocked()
#define pc(c) putchar_unlocked(c)
#else
#define gc() getchar()
#define pc(c) putchar(c)
#endif
int in() { //
int n = 0, c = gc();
do n = 10 * n + (c & 0xf); while ((c = gc()) >= '0');
return n;
}
void out(int n) { //
int i;
char b[20];
i = 0; while (n) b[i++] = n % 10 + '0', n /= 10;
while (i--) pc(b[i]);
}
#define INF 0x7fffffff
typedef struct { int a, id; } Q;
Q q[700000]; int top;
typedef struct { int a, b, c; } T;
T t[1005]; int M;
int to[105][1005], mo[105][1005], hi[105]; int N;
int d[1005], K;
char ans[105], f[105][105];
int aa[2010][2], sz;
int cmp(const void *a, const void *b) { return ((T *)a)->c - ((T *)b)->c; }
// t[i].c >= x i
int lower_bound(int x) {
int m, l = 0, r = M;
while (l+1 < r) {
m = (l+r)/2;
if (t[m].c < x) l = m; else r = m;
}
return t[l].c < x? r: l;
}
int dfs(int a, int id) {
int i;
top = 0, q[top].a = a, q[top++].id = id;
while (top) {
a = q[--top].a, id = q[top].id;
if (id == K) return 1;
for (i = 0; i < hi[a]; i++) {
if (mo[a][i] == d[id]) q[top].a = to[a][i], q[top++].id = id+1;
}
}
return 0;
}
int main()
{
int i, k, a, b, c;
N = in(), M = in(), K = in();
for (i = 0; i < M; i++) {
a = in(), b = in(), c = in();
t[i].a = a, t[i].b = b, t[i].c = c;
k = hi[a]++, to[a][k] = b, mo[a][k] = c;
k = hi[b]++, to[b][k] = a, mo[b][k] = c;
}
qsort(t, M, sizeof(T), cmp); t[M].c = INF;
i = K; while (i--) d[i] = in();
i = lower_bound(d[0]);
while (t[i].c == d[0]) {
a = t[i].a, b = t[i].b;
if (!f[a][b]) f[a][b] = 1, aa[sz][0] = t[i].a, aa[sz++][1] = t[i].b;
if (!f[b][a]) f[b][a] = 1, aa[sz][0] = t[i].b, aa[sz++][1] = t[i].a;
i++;
}
k = 0; for (i = 0; i < sz; i++) {
a = aa[i][0], b = aa[i][1];
if (!ans[a] && dfs(b, 1)) ans[a] = 1, k++;
}
out(k), pc('\n');
for (i = 1; i <= N; i++) if (ans[i]) out(i), pc(' ');
pc('\n');
return 0;
}
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