結果

問題 No.577 Prime Powerful Numbers
ユーザー fumiphysfumiphys
提出日時 2019-07-18 00:29:33
言語 C++14
(gcc 12.3.0 + boost 1.83.0)
結果
WA  
実行時間 -
コード長 5,260 bytes
コンパイル時間 1,894 ms
コンパイル使用メモリ 179,312 KB
実行使用メモリ 15,452 KB
最終ジャッジ日時 2024-06-06 05:02:12
合計ジャッジ時間 2,952 ms
ジャッジサーバーID
（参考情報） 		judge3 / judge5
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 61 ms
15,324 KB
testcase_01 AC 61 ms
15,192 KB
testcase_02 AC 70 ms
15,328 KB
testcase_03 WA -
testcase_04 AC 62 ms
15,328 KB
testcase_05 WA -
testcase_06 WA -
testcase_07 WA -
testcase_08 WA -
testcase_09 WA -
testcase_10 AC 69 ms
15,324 KB
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ソースコード

diff # 

// includes
#include <bits/stdc++.h>

// macros
#define ll long long int
#define pb emplace_back
#define mk make_pair
#define pq priority_queue
#define FOR(i, a, b) for(int i=(a);i<(b);++i)
#define rep(i, n) FOR(i, 0, n)
#define rrep(i, n) for(int i=((int)(n)-1);i>=0;i--)
#define irep(itr, st) for(auto itr = (st).begin(); itr != (st).end(); ++itr)
#define irrep(itr, st) for(auto itr = (st).rbegin(); itr != (st).rend(); ++itr)
#define vrep(v, i) for(int i = 0; i < (v).size(); i++)
#define all(x) (x).begin(),(x).end()
#define sz(x) ((int)(x).size())
#define UNIQUE(v) v.erase(unique(v.begin(), v.end()), v.end())
#define FI first
#define SE second
#define dump(a, n) for(int i = 0; i < n; i++)cout << a[i] << "\n "[i + 1 != n];
#define dump2(a, n, m) for(int i = 0; i < n; i++)for(int j = 0; j < m; j++)cout << a[i][j] << "\n "[j + 1 != m];
#define bit(n) (1LL<<(n))
#define INT(n) int n; cin >> n;
#define LL(n) ll n; cin >> n;
#define DOUBLE(n) double n; cin >> n;
using namespace std;

template <class T>bool chmax(T &a, const T &b){if(a < b){a = b; return 1;} return 0;}
template <class T>bool chmin(T &a, const T &b){if(a > b){a = b; return 1;} return 0;}
template <typename T> istream &operator>>(istream &is, vector<T> &vec){for(auto &v: vec)is >> v; return is;}
template <typename T> ostream &operator<<(ostream &os, const vector<T>& vec){for(int i = 0; i < vec.size(); i++){ os << vec[i]; if(i + 1 != vec.size())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const unordered_set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const unordered_multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &p){os << p.first << " " << p.second; return os;}
template <typename T1, typename T2> ostream &operator<<(ostream &os, const map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end(); ++itr){ os << itr->first << ":" << itr->second; auto titr = itr; if(++titr != mp.end())os << " "; } return os;}
template <typename T1, typename T2> ostream &operator<<(ostream &os, const unordered_map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end(); ++itr){ os << itr->first << ":" << itr->second; auto titr = itr; if(++titr != mp.end())os << " "; } return os;}

//  types
typedef pair<int, int> P;
typedef pair<ll, int> Pl;
typedef pair<ll, ll> Pll;
typedef pair<double, double> Pd;
typedef complex<double> cd;

// constants
const int inf = 1e9;
const ll linf = 1LL << 50;
const double EPS = 1e-10;
const int mod = 1e9 + 7;
const int dx[4] = {-1, 0, 1, 0};
const int dy[4] = {0, -1, 0, 1};

template <typename T>
T power(T a, T n, T mod) {
  T res = 1;
  T tmp = n;
  T curr = a;
  while(tmp){
    if(tmp % 2 == 1){
      res = (T)(res * curr % mod);
    }
    curr = (T)(curr * curr % mod);
    tmp >>= 1;
  }

  return res;
}


// solve
template <typename T>
vector<T> list_prime(T n){
  vector<T> res;
  vector<bool> i_prime = vector<bool>(n+1, true);
  for(ll i = 2; i <= n; i++){
    if(i_prime[i]){
      res.push_back(i);
      for(ll j = 2; j * i <= n; j++){
        i_prime[i * j] = false;
      }
    }
  }
  return res;
}

template <typename T>
bool suspect(T a, int s, T d, T n){
  T x = power<T>(a, d, n);
  if(x == 1)return true;
  for(int r = 0; r < s; r++){
    if(x == n - 1)return true;
    x = x * x % n;
  }
  return false;
}

template <typename T>
bool millar_rabin(T n){
  if(n <= 1 || (n > 2 && n % 2 == 0))return false;
  vector<ll> test = {2, 3, 5, 7, 11, 13, 17, 19, 23};
  T d = n - 1;
  int s = 0;
  while(d % 2 == 0)s++, d /= 2;
  for(int i = 0; i < test.size() && test[i] < n; i++){
    if(!suspect<T>(test[i], s, d, n))return false;
  }
  return true;
}



int main(int argc, char const* argv[])
{
  ios_base::sync_with_stdio(false);
  cin.tie(0);
  cout << fixed << setprecision(20);
  INT(q);
  vector<ll> p = list_prime<ll>(1000000);
  set<ll> st;
  rep(i, sz(p)){
    ll tmp = p[i];
    while(tmp <= (ll)(1e18)){
      st.insert(tmp);
      tmp *= p[i];
      if(tmp <= 0)break;
    }
  }
  rep(i_, q){
    LL(n);
    if(n <= 2){
      cout << "No" << endl;
      continue;
    }
    if(n % 2 == 0){
      cout << "Yes" << endl;
      continue;
    }
    bool ok = false;
    for(int i = 1; i <= 60; i++){
      ll ns = (1LL << i);
      ll rem = n - ns;
      if(rem <= 1)break;
      if(millar_rabin(rem))ok = true;
      else{
        ll sq = sqrt(rem);
        if(sq * sq == rem)ok = true;
        else{
          if(st.find(rem) != st.end())ok = true;
        }
      }
    }
    if(ok)cout << "Yes" << endl;
    else cout << "No" << endl;
  }
  return 0;
}
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