結果
問題 | No.243 出席番号(2) |
ユーザー |
|
提出日時 | 2019-07-18 02:05:46 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 1,136 ms / 2,000 ms |
コード長 | 5,539 bytes |
コンパイル時間 | 1,849 ms |
コンパイル使用メモリ | 173,408 KB |
実行使用メモリ | 5,248 KB |
最終ジャッジ日時 | 2024-12-24 00:04:44 |
合計ジャッジ時間 | 14,670 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge3 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 30 |
ソースコード
// includes#include <bits/stdc++.h>// macros#define ll long long int#define pb emplace_back#define mk make_pair#define pq priority_queue#define FOR(i, a, b) for(int i=(a);i<(b);++i)#define rep(i, n) FOR(i, 0, n)#define rrep(i, n) for(int i=((int)(n)-1);i>=0;i--)#define irep(itr, st) for(auto itr = (st).begin(); itr != (st).end(); ++itr)#define irrep(itr, st) for(auto itr = (st).rbegin(); itr != (st).rend(); ++itr)#define vrep(v, i) for(int i = 0; i < (v).size(); i++)#define all(x) (x).begin(),(x).end()#define sz(x) ((int)(x).size())#define UNIQUE(v) v.erase(unique(v.begin(), v.end()), v.end())#define FI first#define SE second#define dump(a, n) for(int i = 0; i < n; i++)cout << a[i] << "\n "[i + 1 != n];#define dump2(a, n, m) for(int i = 0; i < n; i++)for(int j = 0; j < m; j++)cout << a[i][j] << "\n "[j + 1 != m];#define bit(n) (1LL<<(n))#define INT(n) int n; cin >> n;#define LL(n) ll n; cin >> n;#define DOUBLE(n) double n; cin >> n;using namespace std;template <class T>bool chmax(T &a, const T &b){if(a < b){a = b; return 1;} return 0;}template <class T>bool chmin(T &a, const T &b){if(a > b){a = b; return 1;} return 0;}template <typename T> istream &operator>>(istream &is, vector<T> &vec){for(auto &v: vec)is >> v; return is;}template <typename T> ostream &operator<<(ostream &os, const vector<T>& vec){for(int i = 0; i < vec.size(); i++){ os << vec[i]; if(i + 1 != vec.size())os << " ";} return os;}template <typename T> ostream &operator<<(ostream &os, const set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr =itr; if(++titr != st.end())os << " ";} return os;}template <typename T> ostream &operator<<(ostream &os, const unordered_set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr;auto titr = itr; if(++titr != st.end())os << " ";} return os;}template <typename T> ostream &operator<<(ostream &os, const multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; autotitr = itr; if(++titr != st.end())os << " ";} return os;}template <typename T> ostream &operator<<(ostream &os, const unordered_multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os <<*itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;}template <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &p){os << p.first << " " << p.second; return os;}template <typename T1, typename T2> ostream &operator<<(ostream &os, const map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end(); ++itr){ os <<itr->first << ":" << itr->second; auto titr = itr; if(++titr != mp.end())os << " "; } return os;}template <typename T1, typename T2> ostream &operator<<(ostream &os, const unordered_map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end();++itr){ os << itr->first << ":" << itr->second; auto titr = itr; if(++titr != mp.end())os << " "; } return os;}// typestypedef pair<int, int> P;typedef pair<ll, int> Pl;typedef pair<ll, ll> Pll;typedef pair<double, double> Pd;typedef complex<double> cd;// constantsconst int inf = 1e9;const ll linf = 1LL << 50;const double EPS = 1e-10;const int mod = 1e9 + 7;const int dx[4] = {-1, 0, 1, 0};const int dy[4] = {0, -1, 0, 1};// solvetemplate <typename T>T power(T a, T n, T mod) {T res = 1;T tmp = n;T curr = a;while(tmp){if(tmp % 2 == 1){res = (T)(res * curr % mod);}curr = (T)(curr * curr % mod);tmp >>= 1;}return res;}struct Factorial{int n;const int MOD = 1e9 + 7;vector<long long> fac;vector<long long> inv_;Factorial(int n): n(n){fac.resize(n + 1);inv_.resize(n + 1);calc_factorial();calc_inv();}void calc_factorial(){fac[0] = 1;for(int i = 1; i <= n; i++){fac[i] = i * fac[i-1] % MOD;}}void calc_inv(){inv_[n] = power<long long>(fac[n], MOD - 2, MOD);for(int i = n - 1; i >= 0; i--){inv_[i] = (i + 1) * inv_[i+1] % MOD;}}long long& operator[](size_t i){if(i < 0 || i > n){cerr << "list index out of range" << endl;abort();}return fac[i];}long long inv(size_t i){if(i < 0 || i > n){cerr << "list index out of range" << endl;abort();}return inv_[i];}long long comb(int n, int k){if(n < k)return 0;long long res = fac[n];res = res * inv_[n-k] % MOD;res = res * inv_[k] % MOD;return res;}long long perm(int n, int k){if(n < k)return 0;long long res = fac[n];res = res * inv_[n-k] % MOD;return res;}long long h(int n, int k){if(n == 0 && k == 0)return 1;return comb(n + k - 1, k);}};ll dp[2][5001];int c[5001];int sum[5001];int main(int argc, char const* argv[]){ios_base::sync_with_stdio(false);cin.tie(0);cout << fixed << setprecision(20);INT(n); vector<int> a(n); cin >> a;rep(i, n)c[a[i]]++;rep(i, n)sum[i] = (i > 0 ? sum[i-1]: 0) + c[i];dp[0][0] = 1;Factorial fac(n);rep(i, n - 1){rep(j, n + 1)dp[(i+1)&1][j] = 0;rep(j, i + 2){for(int k = 0; k <= min(i + 1 - j, c[i+1]); k++){ll remk = fac.comb(i + 1 - j, k);ll cik = fac.perm(c[i+1], k);(dp[(i+1)&1][j+k+1] += (remk * cik % mod) * (dp[i&1][j] * (sum[i] - j) % mod) % mod) %= mod;(dp[(i+1)&1][j+k] += (remk * cik % mod) * (dp[i&1][j] * 1 % mod) % mod) %= mod;}}}int k = sum[n-1];ll res = dp[(n-1)&1][k] * fac[n-k] % mod;cout << res << endl;return 0;}