結果

問題 No.42 貯金箱の溜息
ユーザー fumiphys
提出日時 2019-07-19 19:52:47
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 25 ms / 5,000 ms
コード長 6,193 bytes
コンパイル時間 1,768 ms
コンパイル使用メモリ 175,084 KB
実行使用メモリ 5,248 KB
最終ジャッジ日時 2024-12-26 00:21:27
合計ジャッジ時間 2,467 ms
ジャッジサーバーID
(参考情報)
judge3 / judge5
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ファイルパターン 結果
other AC * 3
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ソースコード

diff #
プレゼンテーションモードにする

// includes
#include <bits/stdc++.h>
// macros
#define ll long long int
#define pb emplace_back
#define mk make_pair
#define pq priority_queue
#define FOR(i, a, b) for(int i=(a);i<(b);++i)
#define rep(i, n) FOR(i, 0, n)
#define rrep(i, n) for(int i=((int)(n)-1);i>=0;i--)
#define irep(itr, st) for(auto itr = (st).begin(); itr != (st).end(); ++itr)
#define irrep(itr, st) for(auto itr = (st).rbegin(); itr != (st).rend(); ++itr)
#define vrep(v, i) for(int i = 0; i < (v).size(); i++)
#define all(x) (x).begin(),(x).end()
#define sz(x) ((int)(x).size())
#define UNIQUE(v) v.erase(unique(v.begin(), v.end()), v.end())
#define FI first
#define SE second
#define dump(a, n) for(int i = 0; i < n; i++)cout << a[i] << "\n "[i + 1 != n];
#define dump2(a, n, m) for(int i = 0; i < n; i++)for(int j = 0; j < m; j++)cout << a[i][j] << "\n "[j + 1 != m];
#define bit(n) (1LL<<(n))
#define INT(n) int n; cin >> n;
#define LL(n) ll n; cin >> n;
#define DOUBLE(n) double n; cin >> n;
using namespace std;
template <class T>bool chmax(T &a, const T &b){if(a < b){a = b; return 1;} return 0;}
template <class T>bool chmin(T &a, const T &b){if(a > b){a = b; return 1;} return 0;}
template <typename T> istream &operator>>(istream &is, vector<T> &vec){for(auto &v: vec)is >> v; return is;}
template <typename T> ostream &operator<<(ostream &os, const vector<T>& vec){for(int i = 0; i < vec.size(); i++){ os << vec[i]; if(i + 1 != vec.size
    ())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr =
    itr; if(++titr != st.end())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const unordered_set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr;
    auto titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto
    titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const unordered_multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os <<
    *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &p){os << p.first << " " << p.second; return os;}
template <typename T1, typename T2> ostream &operator<<(ostream &os, const map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end(); ++itr){ os <<
    itr->first << ":" << itr->second; auto titr = itr; if(++titr != mp.end())os << " "; } return os;}
template <typename T1, typename T2> ostream &operator<<(ostream &os, const unordered_map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end();
    ++itr){ os << itr->first << ":" << itr->second; auto titr = itr; if(++titr != mp.end())os << " "; } return os;}
// types
typedef pair<int, int> P;
typedef pair<ll, int> Pl;
typedef pair<ll, ll> Pll;
typedef pair<double, double> Pd;
typedef complex<double> cd;
// constants
const int inf = 1e9;
const ll linf = 1LL << 50;
const double EPS = 1e-10;
const int mod = 1e9 + 9;
const int dx[4] = {-1, 0, 1, 0};
const int dy[4] = {0, -1, 0, 1};
// solve
template <int MOD>
struct ModInt {
ll x = 0;
ModInt(){}
ModInt(ll x_){
x = int(x_ % MOD);
if(x < 0)x += MOD;
}
ModInt(const ModInt &m){
x = m.x;
}
ModInt& operator+=(const ModInt &y){
x = (x + y.x) % MOD;
if(x < 0)x += MOD;
return *this;
}
ModInt& operator-=(const ModInt &y){
x = (x - y.x) % MOD;
if(x < 0)x += MOD;
return *this;
}
ModInt& operator*=(const ModInt &y){
x = (x * y.x) % MOD;
if(x < 0)x += MOD;
return *this;
}
ModInt& operator/=(const ModInt &y){
x = (x * y.inverse().x) % MOD;
if(x < 0)x += MOD;
return *this;
}
ModInt inverse() const{
ll res = 1;
ll tmp = MOD - 2;
ll curr = x;
while(tmp){
if(tmp % 2 == 1)res = res * curr % MOD;
curr = curr * curr % MOD;
tmp /= 2;
}
return ModInt(res);
}
ModInt operator-() const{
return ModInt(-x);
}
ModInt operator+(const ModInt &y) const{
return ModInt(*this) += y;
}
ModInt operator-(const ModInt &y) const{
return ModInt(*this) -= y;
}
ModInt operator*(const ModInt &y) const{
return ModInt(*this) *= y;
}
ModInt operator/(const ModInt &y) const{
return ModInt(*this) /= y;
}
bool operator==(const ModInt &y) const{
return x == y.x;
}
bool operator!=(const ModInt &y) const{
return x != y.x;
}
friend ostream& operator<<(ostream &os, const ModInt<MOD> &m){
return os << m.x;
}
friend istream& operator>>(istream &is, ModInt<MOD> &m){
long t;
is >> t;
m = ModInt<MOD>(t);
return is;
}
};
template <typename T>
struct LagrangeInterpolationM{
int n = 0;
vector<T> x, y;
vector<T> nume;
LagrangeInterpolationM(){}
LagrangeInterpolationM(const vector<T> &x, const vector<T> &y): x(x), y(y){
n = x.size() - 1;
nume.resize(n + 1);
for(int i = 0; i <= n; i++){
T t = T(1);
for(int j = 0; j <= n; j++){
if(i == j)continue;
t = t * (x[i] - x[j]);
}
nume[i] = t.inverse();
}
}
T val(T t){
T a = T(1);
for(int i = 0; i <= n; i++){
if(t == x[i])return y[i];
a = a * (t - x[i]);
}
T res = T(0);
for(int i = 0; i <= n; i++){
res += y[i] * nume[i] * (a / (t - x[i]));
}
return res;
}
};
ll dp[7][3010];
int main(int argc, char const* argv[])
{
ios_base::sync_with_stdio(false);
cin.tie(0);
cout << fixed << setprecision(20);
dp[0][0] = 1;
int c[6] = {1, 5, 10, 50, 100, 500};
rep(i, 6){
rep(j, 3001){
dp[i+1][j] = dp[i][j];
if(j-c[i]>=0)dp[i+1][j] = (dp[i+1][j] + dp[i+1][j-c[i]]);
}
}
vector<LagrangeInterpolationM<ModInt<mod>>> lag(500);
rep(i, 500){
vector<ModInt<mod>> x(6), y(6);
rep(j, 6){
x[j] = j;
y[j] = dp[6][j*500+i];
}
lag[i] = LagrangeInterpolationM<ModInt<mod>>(x, y);
}
INT(t);
rep(i_, t){
LL(m);
cout << lag[m%500].val(m/500) << endl;
}
return 0;
}
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