結果
問題 | No.42 貯金箱の溜息 |
ユーザー |
|
提出日時 | 2019-07-19 19:52:47 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 25 ms / 5,000 ms |
コード長 | 6,193 bytes |
コンパイル時間 | 1,768 ms |
コンパイル使用メモリ | 175,084 KB |
実行使用メモリ | 5,248 KB |
最終ジャッジ日時 | 2024-12-26 00:21:27 |
合計ジャッジ時間 | 2,467 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge5 |
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ファイルパターン | 結果 |
---|---|
other | AC * 3 |
ソースコード
// includes#include <bits/stdc++.h>// macros#define ll long long int#define pb emplace_back#define mk make_pair#define pq priority_queue#define FOR(i, a, b) for(int i=(a);i<(b);++i)#define rep(i, n) FOR(i, 0, n)#define rrep(i, n) for(int i=((int)(n)-1);i>=0;i--)#define irep(itr, st) for(auto itr = (st).begin(); itr != (st).end(); ++itr)#define irrep(itr, st) for(auto itr = (st).rbegin(); itr != (st).rend(); ++itr)#define vrep(v, i) for(int i = 0; i < (v).size(); i++)#define all(x) (x).begin(),(x).end()#define sz(x) ((int)(x).size())#define UNIQUE(v) v.erase(unique(v.begin(), v.end()), v.end())#define FI first#define SE second#define dump(a, n) for(int i = 0; i < n; i++)cout << a[i] << "\n "[i + 1 != n];#define dump2(a, n, m) for(int i = 0; i < n; i++)for(int j = 0; j < m; j++)cout << a[i][j] << "\n "[j + 1 != m];#define bit(n) (1LL<<(n))#define INT(n) int n; cin >> n;#define LL(n) ll n; cin >> n;#define DOUBLE(n) double n; cin >> n;using namespace std;template <class T>bool chmax(T &a, const T &b){if(a < b){a = b; return 1;} return 0;}template <class T>bool chmin(T &a, const T &b){if(a > b){a = b; return 1;} return 0;}template <typename T> istream &operator>>(istream &is, vector<T> &vec){for(auto &v: vec)is >> v; return is;}template <typename T> ostream &operator<<(ostream &os, const vector<T>& vec){for(int i = 0; i < vec.size(); i++){ os << vec[i]; if(i + 1 != vec.size())os << " ";} return os;}template <typename T> ostream &operator<<(ostream &os, const set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr =itr; if(++titr != st.end())os << " ";} return os;}template <typename T> ostream &operator<<(ostream &os, const unordered_set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr;auto titr = itr; if(++titr != st.end())os << " ";} return os;}template <typename T> ostream &operator<<(ostream &os, const multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; autotitr = itr; if(++titr != st.end())os << " ";} return os;}template <typename T> ostream &operator<<(ostream &os, const unordered_multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os <<*itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;}template <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &p){os << p.first << " " << p.second; return os;}template <typename T1, typename T2> ostream &operator<<(ostream &os, const map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end(); ++itr){ os <<itr->first << ":" << itr->second; auto titr = itr; if(++titr != mp.end())os << " "; } return os;}template <typename T1, typename T2> ostream &operator<<(ostream &os, const unordered_map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end();++itr){ os << itr->first << ":" << itr->second; auto titr = itr; if(++titr != mp.end())os << " "; } return os;}// typestypedef pair<int, int> P;typedef pair<ll, int> Pl;typedef pair<ll, ll> Pll;typedef pair<double, double> Pd;typedef complex<double> cd;// constantsconst int inf = 1e9;const ll linf = 1LL << 50;const double EPS = 1e-10;const int mod = 1e9 + 9;const int dx[4] = {-1, 0, 1, 0};const int dy[4] = {0, -1, 0, 1};// solvetemplate <int MOD>struct ModInt {ll x = 0;ModInt(){}ModInt(ll x_){x = int(x_ % MOD);if(x < 0)x += MOD;}ModInt(const ModInt &m){x = m.x;}ModInt& operator+=(const ModInt &y){x = (x + y.x) % MOD;if(x < 0)x += MOD;return *this;}ModInt& operator-=(const ModInt &y){x = (x - y.x) % MOD;if(x < 0)x += MOD;return *this;}ModInt& operator*=(const ModInt &y){x = (x * y.x) % MOD;if(x < 0)x += MOD;return *this;}ModInt& operator/=(const ModInt &y){x = (x * y.inverse().x) % MOD;if(x < 0)x += MOD;return *this;}ModInt inverse() const{ll res = 1;ll tmp = MOD - 2;ll curr = x;while(tmp){if(tmp % 2 == 1)res = res * curr % MOD;curr = curr * curr % MOD;tmp /= 2;}return ModInt(res);}ModInt operator-() const{return ModInt(-x);}ModInt operator+(const ModInt &y) const{return ModInt(*this) += y;}ModInt operator-(const ModInt &y) const{return ModInt(*this) -= y;}ModInt operator*(const ModInt &y) const{return ModInt(*this) *= y;}ModInt operator/(const ModInt &y) const{return ModInt(*this) /= y;}bool operator==(const ModInt &y) const{return x == y.x;}bool operator!=(const ModInt &y) const{return x != y.x;}friend ostream& operator<<(ostream &os, const ModInt<MOD> &m){return os << m.x;}friend istream& operator>>(istream &is, ModInt<MOD> &m){long t;is >> t;m = ModInt<MOD>(t);return is;}};template <typename T>struct LagrangeInterpolationM{int n = 0;vector<T> x, y;vector<T> nume;LagrangeInterpolationM(){}LagrangeInterpolationM(const vector<T> &x, const vector<T> &y): x(x), y(y){n = x.size() - 1;nume.resize(n + 1);for(int i = 0; i <= n; i++){T t = T(1);for(int j = 0; j <= n; j++){if(i == j)continue;t = t * (x[i] - x[j]);}nume[i] = t.inverse();}}T val(T t){T a = T(1);for(int i = 0; i <= n; i++){if(t == x[i])return y[i];a = a * (t - x[i]);}T res = T(0);for(int i = 0; i <= n; i++){res += y[i] * nume[i] * (a / (t - x[i]));}return res;}};ll dp[7][3010];int main(int argc, char const* argv[]){ios_base::sync_with_stdio(false);cin.tie(0);cout << fixed << setprecision(20);dp[0][0] = 1;int c[6] = {1, 5, 10, 50, 100, 500};rep(i, 6){rep(j, 3001){dp[i+1][j] = dp[i][j];if(j-c[i]>=0)dp[i+1][j] = (dp[i+1][j] + dp[i+1][j-c[i]]);}}vector<LagrangeInterpolationM<ModInt<mod>>> lag(500);rep(i, 500){vector<ModInt<mod>> x(6), y(6);rep(j, 6){x[j] = j;y[j] = dp[6][j*500+i];}lag[i] = LagrangeInterpolationM<ModInt<mod>>(x, y);}INT(t);rep(i_, t){LL(m);cout << lag[m%500].val(m/500) << endl;}return 0;}