結果

問題 No.90 品物の並び替え
ユーザー lskjfsdhj
提出日時 2019-07-21 17:29:36
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 610 ms / 5,000 ms
コード長 3,786 bytes
コンパイル時間 1,108 ms
コンパイル使用メモリ 107,880 KB
実行使用メモリ 6,944 KB
最終ジャッジ日時 2024-06-22 11:45:52
合計ジャッジ時間 2,593 ms
ジャッジサーバーID
(参考情報)
judge4 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 1
other AC * 9
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include<iostream>
#include <iomanip>
#include <vector>
#include <algorithm>
#include <string>
#include <cmath>
#include <map>
#include <set>
#include <bitset>
#include <stack>
#include <queue>
#include <fstream>
#include <functional>
using namespace std;
using ll = long long;
#define all(x) (x).begin(),(x).end()
#define PRI(n) cout << n <<endl;
#define PRI2(n, m) cout << n << " " << m << " "<<endl;
#define REP(i, n) for(int i = 0; i < (int)n; ++i)
#define REPbit(bit, n) for(int bit = 0; bit < (int)(1<<n); ++bit)
#define FOR(i, t, n) for(int i = t; i <= (int)n; ++i)
const char alphabet[26] = {'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r',
's', 't', 'u', 'v', 'w', 'x', 'y', 'z'};
const ll MOD = (ll) 1e9 + 7;
const int MAX_INT = 1 << 17;
struct edge {
int to, cost;
bool flag = false;
};
bool isPrime(ll x) {
if (x == 0)return 0;
if (x == 1)return 0;
if (x == 2)return 1;
if (x % 2 == 0)return 0;
FOR(i, 3, x - 1) {
if (x % i == 0)return 0;
}
return 1;
}
ll GCD(ll a, ll b) {
if (b == 0)return a;
return GCD(b, a % b);
}
ll LCM(ll a, ll b) {
ll gcd = GCD(a, b);
return a / gcd * b;
}
ll nCr(int n, int r) {
vector<ll> C(r + 1);
C[0] = 1;
FOR(i, 1, n) for (int j = min(i, r); j < 1; --j)C[j] = (C[j] + C[j - 1]) % MOD;
return C[r];
}
template<class T>
class SegTree {
int n;
vector<T> data;
T def;
function<T(T, T)> operation;
function<T(T, T)> update;
T _query(int a, int b, int k, int l, int r) {
if (r <= a || b <= l) return def;
if (a <= l && r <= b)
return data[k];
else {
T c1 = _query(a, b, 2 * k + 1, l, (l + r) / 2);
T c2 = _query(a, b, 2 * k + 2, (l + r) / 2, r);
return operation(c1, c2);
}
}
public:
SegTree(size_t _n, T _def, function<T(T, T)> _operation,
function<T(T, T)> _update)
: def(_def), operation(_operation), update(_update) {
n = 1;
while (n < _n) {
n *= 2;
}
data = vector<T>(2 * n - 1, def);
}
void change(int i, T x) {
i += n - 1;
data[i] = update(data[i], x);
while (i > 0) {
i = (i - 1) / 2;
data[i] = operation(data[i * 2 + 1], data[i * 2 + 2]);
}
}
T query(int a, int b) {
return _query(a, b, 0, 0, n);
}
T operator[](int i) {
return data[i + n - 1];
}
};
struct UnionFind {
vector<int> par;
vector<int> rank;
UnionFind(int N) {
for (int i = 0; i < N; ++i) {
par.push_back(i);
rank.push_back(0);
}
}
int find(int x) {
if (par[x] == x)return x;
else return par[x] = find(par[x]);
}
void unite(int x, int y) {
x = find(x);
y = find(y);
if (x == y)return;
if (rank[x] < rank[y])par[x] = y;
else {
par[y] = x;
if (rank[x] == rank[y])rank[x]++;
}
}
bool same(int x, int y) {
return find(x) == find(y);
}
};
ll N, K;
string S;
int A[100][100];
int main() {
cin >> N >> K;
vector<int> v;
REP(i, N)v.push_back(i);
REP(i, K) {
int a, b, c;
cin >> a >> b >> c;
A[a][b] = c;
}
int ans = 0;
do {
set<int> s;
int score = 0;
for(auto x:v){
REP(i,100){
if(A[x][i]==0)continue;
if(s.count(i)){
score+=A[x][i];
}
}
s.insert(x);
}
ans = max(ans,score);
// PRI(score)
} while (next_permutation(all(v)));
PRI(ans)
return 0;
}
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