結果

問題 No.269 見栄っ張りの募金活動
ユーザー penguinshunyapenguinshunya
提出日時 2019-07-22 11:11:57
言語 C++17
(gcc 12.3.0 + boost 1.83.0)
結果
TLE  
実行時間 -
コード長 3,724 bytes
コンパイル時間 2,627 ms
コンパイル使用メモリ 219,448 KB
実行使用メモリ 18,208 KB
最終ジャッジ日時 2024-06-23 18:34:03
合計ジャッジ時間 8,954 ms
ジャッジサーバーID
(参考情報)
judge2 / judge4
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
6,816 KB
testcase_01 AC 2 ms
6,940 KB
testcase_02 AC 2 ms
6,944 KB
testcase_03 TLE -
testcase_04 -- -
testcase_05 -- -
testcase_06 -- -
testcase_07 -- -
testcase_08 -- -
testcase_09 -- -
testcase_10 -- -
testcase_11 -- -
testcase_12 -- -
testcase_13 -- -
testcase_14 -- -
testcase_15 -- -
testcase_16 -- -
testcase_17 -- -
testcase_18 -- -
testcase_19 -- -
testcase_20 -- -
testcase_21 -- -
testcase_22 -- -
testcase_23 -- -
testcase_24 -- -
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
#define rep(i, n) for (int i = 0; i < int(n); i++)
#define rrep(i, n) for (int i = int(n) - 1; i >= 0; i--)
#define reps(i, n) for (int i = 1; i <= int(n); i++)
#define rreps(i, n) for (int i = int(n); i >= 1; i--)
#define repc(i, n) for (int i = 0; i <= int(n); i++)
#define rrepc(i, n) for (int i = int(n); i >= 0; i--)
#define repi(i, a, b) for (int i = int(a); i < int(b); i++)
#define repic(i, a, b) for (int i = int(a); i <= int(b); i++)
#define each(x, y) for (auto &x : y)
#define all(a) (a).begin(), (a).end()
#define bit(b) (1ll << (b))
using namespace std;
using i32 = int;
using i64 = long long;
using u64 = unsigned long long;
using f80 = long double;
using vi32 = vector<i32>;
using vi64 = vector<i64>;
using vu64 = vector<u64>;
using vf80 = vector<f80>;
using vstr = vector<string>;
inline void yes() { cout << "Yes" << '\n'; exit(0); }
inline void no() { cout << "No" << '\n'; exit(0); }
inline i64 gcd(i64 a, i64 b) { if (min(a, b) == 0) return max(a, b); if (a % b == 0) return b; return gcd(b, a % b); }
inline i64 lcm(i64 a, i64 b) { return a / gcd(a, b) * b; }
inline u64 xorshift() { static u64 x = 88172645463325252ull; x = x ^ (x << 7); return x = x ^ (x >> 9); }
void solve(); int main() { ios::sync_with_stdio(0); cin.tie(0); cout << fixed << setprecision(16); solve(); return 0; }
template <typename T> class pqasc : public priority_queue<T, vector<T>, greater<T>> {};
template <typename T> class pqdesc : public priority_queue<T, vector<T>, less<T>> {};
template <typename T> inline void amax(T &x, T y) { if (x < y) x = y; }
template <typename T> inline void amin(T &x, T y) { if (x > y) x = y; }
template <typename T> inline T power(T x, i64 n, T e = 1) { T r = e; while (n > 0) { if (n & 1) r *= x; x *= x; n >>= 1; } return r; }
template <typename T> istream& operator>>(istream &is, vector<T> &v) { each(x, v) is >> x; return is; }
template <typename T> ostream& operator<<(ostream &os, vector<T> &v) { rep(i, v.size()) { if (i) os << ' '; os << v[i]; } return os; }
template <typename T, typename S> istream& operator>>(istream &is, pair<T, S> &p) { is >> p.first >> p.second; return is; }
template <typename T, typename S> ostream& operator<<(ostream &os, pair<T, S> &p) { os << p.first << ' ' << p.second; return os; }
template <int mod>
struct ModInt {
int x;
ModInt(): x(0) {}
ModInt(long long a) { x = a % mod; if (x < 0) x += mod; }
ModInt &operator+=(ModInt that) { x = (x + that.x) % mod; return *this; }
ModInt &operator-=(ModInt that) { x = (x + mod - that.x) % mod; return *this; }
ModInt &operator*=(ModInt that) { x = (long long) x * that.x % mod; return *this; }
ModInt &operator/=(ModInt that) { return *this *= that.inverse(); }
ModInt inverse() {
int a = x, b = mod, u = 1, v = 0;
while (b) { int t = a / b; a -= t * b; u -= t * v; swap(a, b); swap(u, v); }
return ModInt(u);
}
#define op(o, p) ModInt operator o(ModInt that) { return ModInt(*this) p that; }
op(+, +=) op(-, -=) op(*, *=) op(/, /=)
#undef op
friend ostream& operator<<(ostream &os, ModInt m) { return os << m.x; }
};
using mint = ModInt<1000000007>;
unordered_map<int, unordered_map<int, unordered_map<int, mint>>> me;
function<mint(int, int, int)> dfs;
void solve() {
int n, s, k; cin >> n >> s >> k;
dfs = [&](int i, int l, int x) {
if (i == n) {
if (x == s) return (mint) 1;
return (mint) 0;
}
if (me[i][l].count(x)) {
return me[i][l][x];
}
{
int c = n - i;
if (s - x < l * c + k * c * (c - 1) / 2) return (mint) 0;
}
mint co = 0;
repic(j, l, s - k) {
co += dfs(i + 1, j + k, x + j);
}
return me[i][l][x] = co;
};
cout << dfs(0, 0, 0) << '\n';
}
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