結果
問題 | No.196 典型DP (1) |
ユーザー | fumiphys |
提出日時 | 2019-07-23 20:57:33 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
TLE
|
実行時間 | - |
コード長 | 4,368 bytes |
コンパイル時間 | 1,573 ms |
コンパイル使用メモリ | 170,596 KB |
実行使用メモリ | 31,104 KB |
最終ジャッジ日時 | 2024-06-26 08:45:55 |
合計ジャッジ時間 | 7,012 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge2 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
10,752 KB |
testcase_01 | AC | 2 ms
5,376 KB |
testcase_02 | AC | 2 ms
5,376 KB |
testcase_03 | AC | 2 ms
5,376 KB |
testcase_04 | AC | 2 ms
5,376 KB |
testcase_05 | AC | 2 ms
5,376 KB |
testcase_06 | AC | 2 ms
5,376 KB |
testcase_07 | AC | 2 ms
5,376 KB |
testcase_08 | AC | 2 ms
5,376 KB |
testcase_09 | AC | 2 ms
5,376 KB |
testcase_10 | AC | 2 ms
5,376 KB |
testcase_11 | AC | 2 ms
5,376 KB |
testcase_12 | AC | 2 ms
5,376 KB |
testcase_13 | AC | 2 ms
5,376 KB |
testcase_14 | AC | 2 ms
5,376 KB |
testcase_15 | AC | 4 ms
5,376 KB |
testcase_16 | AC | 7 ms
6,528 KB |
testcase_17 | AC | 12 ms
7,936 KB |
testcase_18 | AC | 31 ms
9,600 KB |
testcase_19 | AC | 19 ms
10,496 KB |
testcase_20 | AC | 9 ms
11,904 KB |
testcase_21 | AC | 10 ms
11,904 KB |
testcase_22 | AC | 8 ms
11,776 KB |
testcase_23 | AC | 362 ms
17,408 KB |
testcase_24 | AC | 30 ms
15,616 KB |
testcase_25 | AC | 731 ms
14,976 KB |
testcase_26 | AC | 19 ms
26,368 KB |
testcase_27 | AC | 268 ms
26,496 KB |
testcase_28 | TLE | - |
testcase_29 | -- | - |
testcase_30 | -- | - |
testcase_31 | -- | - |
testcase_32 | -- | - |
testcase_33 | -- | - |
testcase_34 | -- | - |
testcase_35 | -- | - |
testcase_36 | -- | - |
testcase_37 | -- | - |
testcase_38 | -- | - |
testcase_39 | -- | - |
testcase_40 | -- | - |
testcase_41 | -- | - |
testcase_42 | -- | - |
testcase_43 | -- | - |
ソースコード
// includes #include <bits/stdc++.h> // macros #define ll long long int #define pb emplace_back #define mk make_pair #define pq priority_queue #define FOR(i, a, b) for(int i=(a);i<(b);++i) #define rep(i, n) FOR(i, 0, n) #define rrep(i, n) for(int i=((int)(n)-1);i>=0;i--) #define irep(itr, st) for(auto itr = (st).begin(); itr != (st).end(); ++itr) #define irrep(itr, st) for(auto itr = (st).rbegin(); itr != (st).rend(); ++itr) #define vrep(v, i) for(int i = 0; i < (v).size(); i++) #define all(x) (x).begin(),(x).end() #define sz(x) ((int)(x).size()) #define UNIQUE(v) v.erase(unique(v.begin(), v.end()), v.end()) #define FI first #define SE second #define dump(a, n) for(int i = 0; i < n; i++)cout << a[i] << "\n "[i + 1 != n]; #define dump2(a, n, m) for(int i = 0; i < n; i++)for(int j = 0; j < m; j++)cout << a[i][j] << "\n "[j + 1 != m]; #define bit(n) (1LL<<(n)) #define INT(n) int n; cin >> n; #define LL(n) ll n; cin >> n; #define DOUBLE(n) double n; cin >> n; using namespace std; template <class T>bool chmax(T &a, const T &b){if(a < b){a = b; return 1;} return 0;} template <class T>bool chmin(T &a, const T &b){if(a > b){a = b; return 1;} return 0;} template <typename T> istream &operator>>(istream &is, vector<T> &vec){for(auto &v: vec)is >> v; return is;} template <typename T> ostream &operator<<(ostream &os, const vector<T>& vec){for(int i = 0; i < vec.size(); i++){ os << vec[i]; if(i + 1 != vec.size())os << " ";} return os;} template <typename T> ostream &operator<<(ostream &os, const set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;} template <typename T> ostream &operator<<(ostream &os, const unordered_set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;} template <typename T> ostream &operator<<(ostream &os, const multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;} template <typename T> ostream &operator<<(ostream &os, const unordered_multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;} template <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &p){os << p.first << " " << p.second; return os;} template <typename T1, typename T2> ostream &operator<<(ostream &os, const map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end(); ++itr){ os << itr->first << ":" << itr->second; auto titr = itr; if(++titr != mp.end())os << " "; } return os;} template <typename T1, typename T2> ostream &operator<<(ostream &os, const unordered_map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end(); ++itr){ os << itr->first << ":" << itr->second; auto titr = itr; if(++titr != mp.end())os << " "; } return os;} // types typedef pair<int, int> P; typedef pair<ll, int> Pl; typedef pair<ll, ll> Pll; typedef pair<double, double> Pd; typedef complex<double> cd; // constants const int inf = 1e9; const ll linf = 1LL << 50; const double EPS = 1e-10; const int mod = 1e9 + 7; const int dx[4] = {-1, 0, 1, 0}; const int dy[4] = {0, -1, 0, 1}; // solve vector<int> edge[2001], child[2001]; int size[2001]; bool vis[2001]; void dfs(int i){ vis[i] = true; size[i] = 1; for(auto e: edge[i]){ if(!vis[e]){ dfs(e); child[i].pb(e); size[i] += size[e]; } } } ll dp[2001][2001]; ll dp2[2][2001]; int k; void calc(int i){ for(auto c: child[i])calc(c); int all = min(k, size[i] - 1); rep(l, 2){ rep(j, all + 1){ dp2[l][j] = 0; } } dp2[0][0] = 1; int acc = 0; rep(j, sz(child[i])){ acc += size[child[i][j]]; rep(l, min(acc, k) + 1){ dp2[(j+1)&1][l] = 0; rep(m, min(size[child[i][j]], l) + 1){ dp2[(j+1)&1][l] = (dp2[(j+1)&1][l] + dp[child[i][j]][m] * dp2[j&1][l-m] % mod) % mod; } } } rep(j, acc + 1){ dp[i][j] = dp2[(sz(child[i]))&1][j]; } dp[i][size[i]] = 1; } int main(int argc, char const* argv[]) { ios_base::sync_with_stdio(false); cin.tie(0); cout << fixed << setprecision(20); INT(n); cin >> k; rep(i, n - 1){ INT(a); INT(b); edge[a].pb(b); edge[b].pb(a); } dfs(0); calc(0); cout << dp[0][k] << endl; return 0; }