結果

問題 No.854 公平なりんご分配
ユーザー dn6049949
提出日時 2019-07-26 23:18:42
言語 PyPy3
(7.3.15)
結果
MLE  
実行時間 -
コード長 2,967 bytes
コンパイル時間 271 ms
コンパイル使用メモリ 82,264 KB
実行使用メモリ 328,156 KB
最終ジャッジ日時 2024-07-02 09:40:08
合計ジャッジ時間 31,215 ms
ジャッジサーバーID
(参考情報)
judge2 / judge4
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 2
other AC * 80 TLE * 1 MLE * 11
権限があれば一括ダウンロードができます

ソースコード

diff #

#!usr/bin/env python3
from collections import defaultdict,deque
from heapq import heappush, heappop
import sys
import math
import bisect
import random
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def I(): return int(sys.stdin.readline())
def LS():return [list(x) for x in sys.stdin.readline().split()]
def S(): return list(sys.stdin.readline())[:-1]
def IR(n):
    return [I() for i in range(n)]
def LIR(n):
    return [LI() for i in range(n)]
def SR(n):
    return [S() for i in range(n)]
def LSR(n):
    return [LS() for i in range(n)]

sys.setrecursionlimit(1000000)
mod = 1000000007

#A
def A():
    try:
        n = I()
        a = IR(n)
        l = []
        for i in range(n):
            for j in range(i):
                l.append(a[i]+a[j])
        l = list(set(l))
        l.sort()
        l = l[::-1]
        print(l[1])
    except:
        print('"assert"')
    return

#B
def B():
    n = I()

    return

#C
def C():
    def su(n):
        return n*(n+1)//2
    h,w = LI()
    w = abs(w)
    if w == 0:
        print(0)
    if h < w:
        ans = su(w)-su(w-h)
    else:
        ans = h-w+su(w)
    print(ans)
    return

#D
def D():
    def factor(n):
        if n < 4:
            return [n]
        res = []
        i = 2
        while i ** 2 <= n:
            if n%i == 0:
                while n%i == 0:
                    n //= i
                    res.append(i)
            i += 1
            if i == 2000:
                return []
        if n != 1:
            res.append(n)
        return res
    n = I()
    a = LI()
    li = [i for i in range(2,2000)]
    for d in li:
        li = [x for x in li if(x == d or x%d != 0)]
    li.insert(0,0)
    m = len(li)
    ind = [0]*2000
    for i in range(m):
        ind[li[i]] = i
    f = [[0]*m for i in range(n+1)]
    for i in range(n):
        for j in range(m):
            f[i+1][j] += f[i][j]
        if a[i] == 1:
            continue
        res = factor(a[i])
        for j in res:
            f[i+1][ind[j]] += 1

    q = I()

    for i in range(q):
        p,l,r = LI()
        if p == 1:
            print("Yes")
        else:
            if f[r][0]-f[l-1][0]:
                print("Yes")
            else:
                res = factor(p)
                if res == []:
                    print("NO")
                else:
                    d = defaultdict(lambda : 0)
                    for j in res:
                        if j > 1999:
                            print("NO")
                            break
                        d[ind[j]] += 1
                    else:
                        for k,x in d.items():
                            if f[r][k]-f[l-1][k] < x:
                                print("NO")
                                break
                        else:
                            print("Yes")
    return

#E
def E():
    n = I()

    return

#F
def F():
    n = I()

    return

#Solve
if __name__ == "__main__":
    D()
0