結果

問題 No.854 公平なりんご分配
ユーザー bal4u
提出日時 2019-07-27 11:57:37
言語 C
(gcc 13.3.0)
結果
AC  
実行時間 86 ms / 3,153 ms
コード長 4,176 bytes
コンパイル時間 342 ms
コンパイル使用メモリ 34,560 KB
実行使用メモリ 120,448 KB
最終ジャッジ日時 2024-07-02 10:53:06
合計ジャッジ時間 5,400 ms
ジャッジサーバーID
(参考情報)
judge3 / judge4
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 2
other AC * 92
権限があれば一括ダウンロードができます
コンパイルメッセージ
main.c: In function 'in':
main.c:9:14: warning: implicit declaration of function 'getchar_unlocked' [-Wimplicit-function-declaration]
    9 | #define gc() getchar_unlocked()
      |              ^~~~~~~~~~~~~~~~
main.c:17:24: note: in expansion of macro 'gc'
   17 |         int n = 0, c = gc();
      |                        ^~
main.c: In function 'outs':
main.c:10:15: warning: implicit declaration of function 'putchar_unlocked' [-Wimplicit-function-declaration]
   10 | #define pc(c) putchar_unlocked(c)
      |               ^~~~~~~~~~~~~~~~
main.c:22:33: note: in expansion of macro 'pc'
   22 | void outs(char *s) { while (*s) pc(*s++); pc('\n'); }
      |                                 ^~

ソースコード

diff #
プレゼンテーションモードにする

// yukicoder: No.854
// 2019.7.27 bal4u
#include <stdio.h>
#include <string.h>
#include <math.h>
#if 1
#define gc() getchar_unlocked()
#define pc(c) putchar_unlocked(c)
#else
#define gc() getchar()
#define pc(c) putchar(c)
#endif
int in() { //
int n = 0, c = gc();
do n = 10 * n + (c & 0xf); while ((c = gc()) >= '0');
return n;
}
void outs(char *s) { while (*s) pc(*s++); pc('\n'); }
#define MAX 100005
#define SIZE 14
#define TBL 305
int id[2003];
int factor[50], power[50], sz;
int ptbl[TBL] = {0,
2, 3, 5, 7, 11, 13, 17, 19, 23, 29,
31, 37, 41, 43, 47, 53, 59, 61, 67, 71,
73, 79, 83, 89, 97, 101, 103, 107, 109, 113,
127, 131, 137, 139, 149, 151, 157, 163, 167, 173,
179, 181, 191, 193, 197, 199, 211, 223, 227, 229,
233, 239, 241, 251, 257, 263, 269, 271, 277, 281,
283, 293, 307, 311, 313, 317, 331, 337, 347, 349,
353, 359, 367, 373, 379, 383, 389, 397, 401, 409,
419, 421, 431, 433, 439, 443, 449, 457, 461, 463,
467, 479, 487, 491, 499, 503, 509, 521, 523, 541,
547, 557, 563, 569, 571, 577, 587, 593, 599, 601,
607, 613, 617, 619, 631, 641, 643, 647, 653, 659,
661, 673, 677, 683, 691, 701, 709, 719, 727, 733,
739, 743, 751, 757, 761, 769, 773, 787, 797, 809,
811, 821, 823, 827, 829, 839, 853, 857, 859, 863,
877, 881, 883, 887, 907, 911, 919, 929, 937, 941,
947, 953, 967, 971, 977, 983, 991, 997,1009,1013,
1019,1021,1031,1033,1039,1049,1051,1061,1063,1069,
1087,1091,1093,1097,1103,1109,1117,1123,1129,1151,
1153,1163,1171,1181,1187,1193,1201,1213,1217,1223,
1229,1231,1237,1249,1259,1277,1279,1283,1289,1291,
1297,1301,1303,1307,1319,1321,1327,1361,1367,1373,
1381,1399,1409,1423,1427,1429,1433,1439,1447,1451,
1453,1459,1471,1481,1483,1487,1489,1493,1499,1511,
1523,1531,1543,1549,1553,1559,1567,1571,1579,1583,
1597,1601,1607,1609,1613,1619,1621,1627,1637,1657,
1663,1667,1669,1693,1697,1699,1709,1721,1723,1733,
1741,1747,1753,1759,1777,1783,1787,1789,1801,1811,
1823,1831,1847,1861,1867,1871,1873,1877,1879,1889,
1901,1907,1913,1931,1933,1949,1951,1973,1979,1987,
1993,1997,1999 };
int prime_factor(int n) {
int i, b, d, w;
sz = 0, b = (int)sqrt((double)n);
for (i = 1; n > 1; i++) {
if ((d = ptbl[i]) == 0) break;
if (d > b) break;
if (n % d) continue;
factor[sz] = d, w = 0;
do n /= d, w++;
while (n % d == 0);
power[sz++] = w;
}
if (n >= 2003) return 0;
if (n > 1) factor[sz] = n, power[sz++] = 1;
return 1;
}
int bit[TBL][MAX], bitn;
void add(int k, int i, int v) {
while (i <= bitn) bit[k][i] += v, i += i & -i;
}
int sum(int k, int i) {
int s = 0;
while (i > 0) s += bit[k][i], i -= i & -i;
return s;
}
void calc_prime(int k, int n) {
int i, v, w;
for (i = 1; n > 1 && i <= SIZE; i++) {
if (n % ptbl[i]) continue;
v = ptbl[i], w = 0;
do n /= v, w++;
while (n % v == 0);
add(i, k, w);
}
if (n > 1) add(id[n], k, 1);
}
int zero[MAX], zw;
// a[i]>=key i
int lower_bound(int x) {
int m, l = 0, r = zw;
while (l+1 < r) {
m = (l+r)/2;
if (zero[m] < x) l = m; else r = m;
}
return zero[l] < x? r: l;
}
// a[i]>key i
int upper_bound(int l, int x) {
int m, r = zw;
while (l+1 < r) {
m = (l+r)/2;
if (zero[m] <= x) l = m; else r = m;
}
return zero[l] <= x? r: l;
}
int main()
{
int i, k, Q, ans;
int P, L, R, _P, _L, _R, _a;
for (i = 1; i < TBL; i++) id[ptbl[i]] = i;
bitn = in(), zero[0] = 1;
for (i = 1; i <= bitn; i++) {
int a = in();
if (a) calc_prime(i, a);
else zero[zw++] = i;
}
Q = in(); _P = -1;
while (Q--) {
P = in(), L = in(), R = in();
if (P == _P && L == _L && R == _R) { ans = _a; goto done; }
_P = P, _L = L, _R = R;
ans = 1;
if (P == 1) goto done;
if (zw) {
i = lower_bound(L), k = upper_bound(i, R);
if (k-1 >= i) goto done;
}
ans = 0;
if (prime_factor(P)) {
ans = 1;
for (i = 0; i < sz; i++) {
k = id[factor[i]];
int s = sum(k, R);
if (L > 1) s -= sum(k, L-1);
if (s < power[i]) { ans = 0; break; }
}
}
done: outs(ans? "Yes": "NO");
_a = ans;
}
return 0;
}
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