結果

問題 No.399 動的な領主
コンテスト
ユーザー fumiphys
提出日時 2019-08-04 16:03:16
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
WA  
実行時間 -
コード長 5,096 bytes
コンパイル時間 1,725 ms
コンパイル使用メモリ 184,688 KB
実行使用メモリ 31,816 KB
最終ジャッジ日時 2024-07-08 09:28:01
合計ジャッジ時間 4,403 ms
ジャッジサーバーID
（参考情報） 		judge3 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
other AC * 3 WA * 16
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ソースコード

diff # 

// includes
#include <bits/stdc++.h>

// macros
#define pb emplace_back
#define mk make_pair
#define pq priority_queue
#define FOR(i, a, b) for(int i=(a);i<(b);++i)
#define rep(i, n) FOR(i, 0, n)
#define rrep(i, n) for(int i=((int)(n)-1);i>=0;i--)
#define irep(itr, st) for(auto itr = (st).begin(); itr != (st).end(); ++itr)
#define irrep(itr, st) for(auto itr = (st).rbegin(); itr != (st).rend(); ++itr)
#define vrep(v, i) for(int i = 0; i < (v).size(); i++)
#define all(x) (x).begin(),(x).end()
#define sz(x) ((int)(x).size())
#define UNIQUE(v) v.erase(unique(v.begin(), v.end()), v.end())
#define FI first
#define SE second
#define bit(n) (1LL<<(n))
#define INT(n) int n; cin >> n;
#define LL(n) ll n; cin >> n;
#define DOUBLE(n) double n; cin >> n;
using namespace std;

template <class T>bool chmax(T &a, const T &b){if(a < b){a = b; return 1;} return 0;}
template <class T>bool chmin(T &a, const T &b){if(a > b){a = b; return 1;} return 0;}
template <typename T> istream &operator>>(istream &is, vector<T> &vec){for(auto &v: vec)is >> v; return is;}
template <typename T> ostream &operator<<(ostream &os, const vector<T>& vec){for(int i = 0; i < vec.size(); i++){ os << vec[i]; if(i + 1 != vec.size())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const unordered_set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const unordered_multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &p){os << p.first << " " << p.second; return os;}
template <typename T1, typename T2> ostream &operator<<(ostream &os, const map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end(); ++itr){ os << itr->first << ":" << itr->second; auto titr = itr; if(++titr != mp.end())os << " "; } return os;}
template <typename T1, typename T2> ostream &operator<<(ostream &os, const unordered_map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end(); ++itr){ os << itr->first << ":" << itr->second; auto titr = itr; if(++titr != mp.end())os << " "; } return os;}

//  types
using ll = long long int;
using P = pair<int, int>;
using Pli = pair<ll, int>;
using Pil = pair<int, ll>;
using Pll = pair<ll, ll>;
using Pdd = pair<double, double>;
using cd = complex<double>;

// constants
const int inf = 1e9;
const ll linf = 1LL << 50;
const double EPS = 1e-10;
const int mod = 1e9 + 7;
const int dx[4] = {-1, 0, 1, 0};
const int dy[4] = {0, -1, 0, 1};

// solve
vector<int> child[100010];

struct Tree2{
  int n = 0, m = 0;
  vector<vector<int>> edge;
  vector<vector<int>> par;
  vector<bool> vis;
  vector<int> h;
  Tree2(){}
  Tree2(int n): n(n){
    while((1LL<<m) <= n)m++;
    edge.resize(n);
    par.assign(m + 1, vector<int>(n, 0));
    vis.resize(n, false);
    h.resize(n);
  }
  void adde(int from, int to){
    edge[from].emplace_back(to);
  }
  void dfs(int i){
    vis[i] = true;
    for(auto e: edge[i]){
      if(!vis[e]){
        par[0][e] = i;
        h[e] = h[i] + 1;
        child[i].pb(e);
        dfs(e);
      }
    }
  }
  void build(){
    fill(vis.begin(), vis.end(), false);
    fill(h.begin(), h.end(), 0);
    par[0][0] = 0;
    h[0] = 0;
    dfs(0);
    for(int i = 1; i <= m; i++){
      for(int j = 0; j < n; j++){
        par[i][j] = par[i-1][par[i-1][j]];
      }
    }
  }
  int go_up(int u, int k){
    int i = 0;
    while(k){
      if(k % 2 == 1){
        u = par[i][u];
      }
      i++;
      k /= 2;
    }
    return u;
  }
  int lca(int u, int v){
    if(h[u] > h[v])u = go_up(u, h[u] - h[v]);
    if(h[u] < h[v])v = go_up(v, h[v] - h[u]);
    if(u == v)return u;
    int ld = 0, rd = n;
    while(rd - ld > 1){
      int k = (rd + ld) / 2;
      int uk = go_up(u, k);
      int vk = go_up(v, k);
      if(uk == vk)rd = k;
      else ld = k;
    }
    return go_up(u, rd);
  }
};

ll sum[100010];

void calc(int i){
  for(auto e: child[i]){
    calc(e);
    sum[i] += sum[e];
  }
}

int main(int argc, char const* argv[])
{
  ios_base::sync_with_stdio(false);
  cin.tie(0);
  cout << fixed << setprecision(20);
  INT(n);
  Tree2 t2(n);
  rep(i, n - 1){
    INT(u); INT(v); u--; v--;
    t2.adde(u, v);
    t2.adde(v, u);
  }
  t2.build();
  INT(q);
  rep(i, q){
    INT(a); INT(b); a--; b--;
    sum[a]++;
    sum[b]++;
    int l = t2.lca(a, b);
    sum[l]--;
    if(l != 0)sum[t2.par[0][0]]--;
  }
  calc(0);
  ll res = 0;
  rep(i, n){
    res += (sum[i] + 1) * sum[i] / 2;
  }
  cout << res << endl;
  return 0;
}
0