結果

問題 No.859 路線A、路線B、路線C
ユーザー RTnF
提出日時 2019-08-09 22:36:17
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 2 ms / 1,000 ms
コード長 3,820 bytes
コンパイル時間 2,485 ms
コンパイル使用メモリ 209,072 KB
最終ジャッジ日時 2025-01-07 11:26:16
ジャッジサーバーID
（参考情報） 		judge4 / judge1
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ファイルパターン 結果
sample AC * 3
other AC * 12
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ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using vi = vector<int>;
using vvi = vector<vi>;
using vvvi = vector<vvi>;
using vll = vector<ll>;
using vvll = vector<vll>;
using vvvll = vector<vvll>;
using vs = vector<string>;
using pll = pair<ll, ll>;
using vp = vector<pll>;
#define rep(i, n) for(ll i = 0; i < (n); i++)
#define repr(i, a, b) for(ll i = (a); i < (b); i++)
#define ALL(a) (a).begin(), (a).end()
#define SZ(x) ((ll)(x).size())
const ll MOD = 1000000007;
const ll INF = 100000000000000000LL;
inline ll GCD(ll a, ll b){ return b?GCD(b, a % b):a; }
inline ll LCM(ll a, ll b){ return a/GCD(a, b)*b; }
inline ll powint(ll x, ll y){ ll r=1; while(y){ if(y&1) r*=x; x*=x; y>>=1; } return r; }
inline ll powmod(ll x, ll y, ll m = MOD){ ll r=1; while(y){ if(y&1) r*=x; x*=x; r%=m; x%=m; y>>=1; } return r; }
template<class T>bool chmax(T &a, const T &b){ if(a<b) { a=b; return 1; } return 0; }
template<class T>bool chmin(T &a, const T &b){ if(b<a) { a=b; return 1; } return 0; }
#ifdef OJ_LOCAL
#include "dump.hpp"
#else
#define dump(...) ((void)0)
#endif
// http://ronly.hatenablog.com/entry/2017/06/17/161641
struct edge {
    ll to, cost;
    edge(ll t, ll c){
        to = t;
        cost = c;
    }
};
typedef vector<vector<edge> > AdjList;
AdjList graph;
typedef pair<ll, ll> P;
vector<ll> dist;
void dijkstra(ll n, ll s){
    dist = vector<ll>(n,INF);
    dist[s] = 0;
    priority_queue<P, vector<P>, greater<P> > que;
    que.push(P(0,s));
    while(!que.empty()){
        P p = que.top();
        que.pop();
        ll v = p.second;
        if(dist[v] < p.first){
            continue;
        }
        for(ll i=0;i<SZ(graph[v]);i++){
            edge e = graph[v][i];
            if(dist[e.to] > dist[v] + e.cost){
                dist[e.to] = dist[v] + e.cost;
                que.push(P(dist[e.to],e.to));
            }
        }
    }
}
int main(){
    cin.tie(0); ios::sync_with_stdio(false);
    cout << fixed << setprecision(15);
    ll x, y, z;
    cin >> x >> y >> z;
    char s1, s2;
    ll t1, t2;
    cin >> s1 >> t1 >> s2 >> t2;
    s1 -= 'A';
    s2 -= 'A';
    graph = AdjList(8);
    rep(i, 3)repr(j, i+1, 3){
        if(i != j) graph[i].emplace_back(j, 1);
        if(i != j) graph[j].emplace_back(i, 1);
    }
    repr(i, 3, 6)repr(j, i+1, 6){
        if(i != j) graph[i].emplace_back(j, 1);
        if(i != j) graph[j].emplace_back(i, 1);
    }
    if(s1 == s2){
        vll r{x, y, z};
        if(t1 > t2) swap(t1, t2);
        rep(i, 3){
            if(i == s1){
                graph[i].emplace_back(6, t1-1);
                graph[6].emplace_back(i, t1-1);
                graph[6].emplace_back(7, t2-t1);
                graph[7].emplace_back(6, t2-t1);
                graph[7].emplace_back(i+3, r[i]-t2);
                graph[i+3].emplace_back(7, r[i]-t2);
            }else{
                graph[i].emplace_back(i+3, r[i]-1);
                graph[i+3].emplace_back(i, r[i]-1);
            }
        }
    }else{
        vll r{x, y, z};
        rep(i, 3){
            if(i == s1){
                graph[i].emplace_back(6, t1-1);
                graph[6].emplace_back(i, t1-1);
                graph[6].emplace_back(i+3, r[i]-t1);
                graph[i+3].emplace_back(6, r[i]-t1);
            }else if(i == s2){
                graph[i].emplace_back(7, t2-1);
                graph[7].emplace_back(i, t2-1);
                graph[7].emplace_back(i+3, r[i]-t2);
                graph[i+3].emplace_back(7, r[i]-t2);
            }else{
                graph[i].emplace_back(i+3, r[i]-1);
                graph[i+3].emplace_back(i, r[i]-1);
            }
        }
    }
    rep(i, 8)rep(j, SZ(graph[i])){
        dump(i, j, graph[i][j].to, graph[i][j].cost);
    }
    dijkstra(8, 6);
    dump(dist);
    cout << dist[7] << endl;
    return 0;
}
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