結果
問題 | No.8014 多項式ハッシュに関する教育的な問題 |
ユーザー |
![]() |
提出日時 | 2019-08-14 11:23:43 |
言語 | Python3 (3.13.1 + numpy 2.2.1 + scipy 1.14.1) |
結果 |
AC
|
実行時間 | 33 ms / 5,000 ms |
コード長 | 2,047 bytes |
コンパイル時間 | 117 ms |
コンパイル使用メモリ | 12,928 KB |
実行使用メモリ | 11,520 KB |
最終ジャッジ日時 | 2024-09-19 13:44:32 |
合計ジャッジ時間 | 715 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge1 |
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ファイルパターン | 結果 |
---|---|
other | AC * 1 |
ソースコード
#! /usr/bin/env python3from fractions import Fractiondef dot(x, y): return sum(xi * yi for xi, yi in zip(x, y))def norm(x): return sum(xi * xi for xi in x)def gso(g, r, u):n = len(g)for i in range(n):for j in range(i):u[i][j] = dot(g[i], r[j]) * Fraction(1, norm(r[j]))r[i] = g[i]for j in range(i):r[i] = [rik - u[i][j]*rjk for rik, rjk in zip(r[i], r[j])]return g, r, udef reduce_basis(f):n = len(f)g = [[Fraction(fij) for fij in fi] for fi in f]r = [[0] * n for i in range(n)]u = [[0] * i for i in range(n)]g, r, u = gso(g, r, u)half = Fraction(1, 2)i = 1while i < n:for j in range(i-1, -1, -1):if abs(u[i][j]) < half: continuef0 = u[i][j] + halfc = f0.numerator // f0.denominatorg[i] = [gik - c*gjk for gik, gjk in zip(g[i], g[j])]f[i] = [fik - c*fjk for fik, fjk in zip(f[i], f[j])]g, r, u = gso(g, r, u)if i > 0 and norm(r[i-1]) > 2 * norm(r[i]):g[i-1], g[i] = g[i], g[i-1]f[i-1], f[i] = f[i], f[i-1]g, r, u = gso(g, r, u)i -= 1else:i += 1return fdef hack_hash(mod, base):sigma = 26n = 16while True:L = [[0] * n for i in range(n)]for i in range(n-1):L[i][i+0] = -base % modL[i][i+1] = 1L[n-1][0] = modpoly = reduce_basis(L)[0]if all(map(lambda x: abs(x) < sigma, poly)): breakn += 4while poly[-1] == 0: poly.pop()s, t = [], []for c in poly:s.append(c if c >= 0 else 0)t.append(0 if c >= 0 else -c)return s, tdef main():P, B = map(int, input().split())s, t = hack_hash(P, B)S = ''.join(chr(ord('a')+c) for c in s)[::-1]T = ''.join(chr(ord('a')+c) for c in t)[::-1]print(S)print(T)if __name__ == '__main__':print('baeaaaaaaafaaj')print('agafbhabceaaha')# main()