結果

問題 No.869 ふたつの距離
ユーザー e869120e869120
提出日時 2019-08-16 14:34:17
言語 C++14
(gcc 13.2.0 + boost 1.83.0)
結果
AC  
実行時間 178 ms / 1,500 ms
コード長 3,030 bytes
コンパイル時間 2,566 ms
コンパイル使用メモリ 85,740 KB
実行使用メモリ 36,700 KB
最終ジャッジ日時 2023-10-22 04:50:30
合計ジャッジ時間 13,189 ms
ジャッジサーバーID
(参考情報)
judge14 / judge13
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
4,348 KB
testcase_01 AC 2 ms
4,348 KB
testcase_02 AC 2 ms
4,348 KB
testcase_03 AC 2 ms
4,348 KB
testcase_04 AC 2 ms
4,348 KB
testcase_05 AC 2 ms
4,348 KB
testcase_06 AC 2 ms
4,348 KB
testcase_07 AC 2 ms
4,348 KB
testcase_08 AC 2 ms
4,348 KB
testcase_09 AC 2 ms
4,348 KB
testcase_10 AC 2 ms
4,348 KB
testcase_11 AC 2 ms
4,348 KB
testcase_12 AC 2 ms
4,348 KB
testcase_13 AC 2 ms
4,348 KB
testcase_14 AC 2 ms
4,348 KB
testcase_15 AC 2 ms
4,348 KB
testcase_16 AC 2 ms
4,348 KB
testcase_17 AC 2 ms
4,348 KB
testcase_18 AC 2 ms
4,348 KB
testcase_19 AC 2 ms
4,348 KB
testcase_20 AC 2 ms
4,348 KB
testcase_21 AC 2 ms
4,348 KB
testcase_22 AC 2 ms
4,348 KB
testcase_23 AC 1 ms
4,348 KB
testcase_24 AC 2 ms
4,348 KB
testcase_25 AC 2 ms
4,348 KB
testcase_26 AC 2 ms
4,348 KB
testcase_27 AC 2 ms
4,348 KB
testcase_28 AC 2 ms
4,348 KB
testcase_29 AC 2 ms
4,348 KB
testcase_30 AC 2 ms
4,348 KB
testcase_31 AC 2 ms
4,348 KB
testcase_32 AC 2 ms
4,348 KB
testcase_33 AC 2 ms
4,348 KB
testcase_34 AC 2 ms
4,348 KB
testcase_35 AC 2 ms
4,348 KB
testcase_36 AC 2 ms
4,348 KB
testcase_37 AC 2 ms
4,348 KB
testcase_38 AC 2 ms
4,348 KB
testcase_39 AC 2 ms
4,348 KB
testcase_40 AC 2 ms
4,348 KB
testcase_41 AC 2 ms
4,348 KB
testcase_42 AC 122 ms
20,316 KB
testcase_43 AC 36 ms
6,996 KB
testcase_44 AC 53 ms
10,120 KB
testcase_45 AC 81 ms
12,116 KB
testcase_46 AC 5 ms
4,348 KB
testcase_47 AC 23 ms
5,400 KB
testcase_48 AC 53 ms
8,228 KB
testcase_49 AC 57 ms
10,104 KB
testcase_50 AC 34 ms
8,224 KB
testcase_51 AC 7 ms
4,348 KB
testcase_52 AC 3 ms
4,348 KB
testcase_53 AC 16 ms
5,148 KB
testcase_54 AC 118 ms
18,356 KB
testcase_55 AC 71 ms
10,632 KB
testcase_56 AC 17 ms
5,400 KB
testcase_57 AC 49 ms
8,228 KB
testcase_58 AC 8 ms
4,348 KB
testcase_59 AC 16 ms
4,892 KB
testcase_60 AC 109 ms
18,356 KB
testcase_61 AC 42 ms
8,228 KB
testcase_62 AC 108 ms
20,316 KB
testcase_63 AC 142 ms
20,316 KB
testcase_64 AC 27 ms
5,584 KB
testcase_65 AC 84 ms
16,308 KB
testcase_66 AC 66 ms
12,116 KB
testcase_67 AC 168 ms
28,648 KB
testcase_68 AC 172 ms
20,316 KB
testcase_69 AC 172 ms
20,316 KB
testcase_70 AC 176 ms
20,316 KB
testcase_71 AC 172 ms
20,316 KB
testcase_72 AC 173 ms
28,648 KB
testcase_73 AC 173 ms
20,316 KB
testcase_74 AC 174 ms
20,316 KB
testcase_75 AC 174 ms
20,320 KB
testcase_76 AC 170 ms
20,316 KB
testcase_77 AC 177 ms
28,696 KB
testcase_78 AC 174 ms
28,696 KB
testcase_79 AC 177 ms
28,696 KB
testcase_80 AC 175 ms
28,696 KB
testcase_81 AC 178 ms
28,696 KB
testcase_82 AC 170 ms
20,316 KB
testcase_83 AC 176 ms
20,316 KB
testcase_84 AC 170 ms
20,312 KB
testcase_85 AC 170 ms
20,316 KB
testcase_86 AC 174 ms
20,316 KB
testcase_87 AC 170 ms
20,312 KB
testcase_88 AC 169 ms
20,316 KB
testcase_89 AC 172 ms
20,316 KB
testcase_90 AC 170 ms
20,312 KB
testcase_91 AC 177 ms
36,700 KB
testcase_92 AC 176 ms
28,696 KB
testcase_93 AC 1 ms
4,348 KB
testcase_94 AC 2 ms
4,348 KB
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ソースコード

diff #

#include <iostream>
#include <cassert>
#include <vector>
#include <algorithm>
#include <cmath>
using namespace std;

bool check(int N, int A, int B, vector<pair<long double, long double>> E) {
	if (E.size() != N) return false;

	int cnt1 = 0, cnt2 = 0;
	for (int i = 0; i < E.size(); i++) {
		for (int j = i + 1; j < E.size(); j++) {
			long double v = (E[i].first - E[j].first)*(E[i].first - E[j].first) + (E[i].second - E[j].second)*(E[i].second - E[j].second);
			if (v <= 100.0L) cnt1++;
			if (v <= 400.0L) cnt2++;
		}
	}
	if (cnt1 != A) return false;
	if (cnt2 != B) return false;
	return true;
}

vector<long double> construct(int P, int N, int ty) {
	if (P == 0) return vector<long double>{};

	vector<long double> V;
	long double ZA = N * N;
	for (int i = 0; i < P - 1; i++) {
		long double ZZ = 1.0L * i - 1.0L * (P - 2) / 2.0L; ZZ -= 0.314159265358979L;
		V.push_back(abs(ZZ) / ZA);
	}

	vector<long double>Z;
	for (int i = 0; i < P; i++) {
		long double sum = 0;
		for (int j = i + 1; j < P; j++) {
			sum += V[j - 1] * j;
			Z.push_back(1.0L * (10.0L - sum) / (j - i));
		}
	}
	sort(Z.begin(), Z.end());
	reverse(Z.begin(), Z.end());

	long double r = 0;
	if (N == 0) {
		if (ty == 1) r = 30.0L;
		if (ty == 2) r = 40.0L;
	}
	else if (N < Z.size()) {
		if (ty == 1) r = (2.0L * Z[N - 1] + 1.0L * Z[N]) / 3.0L;
		if (ty == 2) r = (1.0L * Z[N - 1] + 2.0L * Z[N]) / 3.0L;
	}
	else {
		if (ty == 1) r = 1e-4;
		if (ty == 2) r = 2e-4;
	}

	vector<long double>A; A.push_back(0);
	for (int i = 1; i < P; i++) {
		A.push_back(A[A.size() - 1] + r + V[i - 1] * i);
	}
	return A;
}

vector<pair<long double, long double>> solve(int N, int A, int B) {
	vector<long double>E1, E2;
	for (int i = N / 2; i <= N; i++) {
		int Z1 = i, Z2 = N - i;
		int S1 = Z1 * (Z1 - 1) / 2, S2 = Z2 * (Z2 - 1) / 2;
		int S = S1 + S2;
		if (S >= A) {
			int parity1 = 1LL * A * S1 / (1LL * (S1 + S2));
			int parity2 = A - parity1;
			E1 = construct(Z1, parity1, 1);
			E2 = construct(Z2, parity2, 2);
			break;
		}
	}

	vector<long double> T;
	for (int i = 0; i < E1.size(); i++) {
		for (int j = 0; j < E2.size(); j++) {
			long double V = 400.0L - (E1[i] - E2[j]) * (E1[i] - E2[j]);
			V = sqrtl(V);
			T.push_back(V);
		}
	}
	sort(T.begin(), T.end());
	reverse(T.begin(), T.end());

	int rem = B - (E1.size() * (E1.size() - 1) / 2) - (E2.size() * (E2.size() - 1) / 2);
	long double ret = 2.0;
	if (rem == 0) ret = 30.0L;
	else if (rem < T.size()) ret = (T[rem - 1] + T[rem]) / 2.0L;
	else ret = 10.1L;

	vector<pair<long double, long double>>ans;
	for (int i = 0; i < E1.size(); i++) ans.push_back(make_pair(0.0L, E1[i]));
	for (int i = 0; i < E2.size(); i++) ans.push_back(make_pair(ret, E2[i]));
	return ans;
}

int main() {
	int N, A, B;
	cin >> N >> A >> B;
	assert(1 <= N && N <= 1500);
	assert(N * (N - 1) <= 4 * A && 2 * A <= N * (N - 1));
	assert(A + N <= B && 2 * B <= N * (N - 1));
	vector<pair<long double, long double>> D = solve(N, A, B);
	for (int i = 0; i < N; i++) printf("%.12Lf %.12Lf\n", D[i].first, D[i].second);
	return 0;
}
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