結果
| 問題 |
No.867 避難経路
|
| コンテスト | |
| ユーザー |
gazelle
|
| 提出日時 | 2019-08-16 22:22:54 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 6,734 bytes |
| コンパイル時間 | 2,853 ms |
| コンパイル使用メモリ | 204,592 KB |
| 最終ジャッジ日時 | 2025-01-07 12:28:31 |
|
ジャッジサーバーID (参考情報) |
judge3 / judge4 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 37 WA * 4 |
コンパイルメッセージ
main.cpp: In function ‘int main()’:
main.cpp:172:27: warning: narrowing conversion of ‘(((ll)a[gx][gy]) + (i * i))’ from ‘ll’ {aka ‘long int’} to ‘int’ [-Wnarrowing]
172 | q.push({a[gx][gy] + i * i, {gx, gy}});
| ~~~~~~~~~~^~~~~~~
ソースコード
#include <bits/stdc++.h>
#define FOR(i, n, m) for(ll i = n; i < (int)m; i++)
#define REP(i, n) FOR(i, 0, n)
#define ALL(v) v.begin(), v.end()
#define pb push_back
using namespace std;
using ll = std::int_fast64_t;
using P = pair<ll, ll>;
constexpr ll inf = 1000000000;
constexpr ll mod = 998244353;
constexpr long double eps = 1e-15;
template<typename T1, typename T2>
ostream& operator<<(ostream& os, pair<T1, T2> p) {
os << to_string(p.first) << " " << to_string(p.second);
return os;
}
template<typename T>
ostream& operator<<(ostream& os, vector<T>& v) {
REP(i, v.size()) {
if(i) os << " ";
os << to_string(v[i]);
}
return os;
}
struct modint {
ll n;
public:
modint(const ll n = 0) : n((n % mod + mod) % mod) {}
static modint pow(modint a, int m) {
modint r = 1;
while(m > 0) {
if(m & 1) { r *= a; }
a = (a * a); m /= 2;
}
return r;
}
modint &operator++() { *this += 1; return *this; }
modint &operator--() { *this -= 1; return *this; }
modint operator++(int) { modint ret = *this; *this += 1; return ret; }
modint operator--(int) { modint ret = *this; *this -= 1; return ret; }
modint operator~() const { return (this -> pow(n, mod - 2)); } // inverse
friend bool operator==(const modint& lhs, const modint& rhs) {
return lhs.n == rhs.n;
}
friend bool operator<(const modint& lhs, const modint& rhs) {
return lhs.n < rhs.n;
}
friend bool operator>(const modint& lhs, const modint& rhs) {
return lhs.n > rhs.n;
}
friend modint &operator+=(modint& lhs, const modint& rhs) {
lhs.n += rhs.n;
if (lhs.n >= mod) lhs.n -= mod;
return lhs;
}
friend modint &operator-=(modint& lhs, const modint& rhs) {
lhs.n -= rhs.n;
if (lhs.n < 0) lhs.n += mod;
return lhs;
}
friend modint &operator*=(modint& lhs, const modint& rhs) {
lhs.n = (lhs.n * rhs.n) % mod;
return lhs;
}
friend modint &operator/=(modint& lhs, const modint& rhs) {
lhs.n = (lhs.n * (~rhs).n) % mod;
return lhs;
}
friend modint operator+(const modint& lhs, const modint& rhs) {
return modint(lhs.n + rhs.n);
}
friend modint operator-(const modint& lhs, const modint& rhs) {
return modint(lhs.n - rhs.n);
}
friend modint operator*(const modint& lhs, const modint& rhs) {
return modint(lhs.n * rhs.n);
}
friend modint operator/(const modint& lhs, const modint& rhs) {
return modint(lhs.n * (~rhs).n);
}
};
istream& operator>>(istream& is, modint m) { is >> m.n; return is; }
ostream& operator<<(ostream& os, modint m) { os << m.n; return os; }
#define MAX_N 3030303
long long extgcd(long long a, long long b, long long& x, long long& y) {
long long d = a;
if (b != 0) {
d = extgcd(b, a % b, y, x);
y -= (a / b) * x;
} else {
x = 1; y = 0;
}
return d;
}
long long mod_inverse(long long a, long long m) {
long long x, y;
if(extgcd(a, m, x, y) == 1) return (m + x % m) % m;
else return -1;
}
vector<long long> fact(MAX_N+1, inf);
long long mod_fact(long long n, long long& e) {
if(fact[0] == inf) {
fact[0]=1;
if(MAX_N != 0) fact[1]=1;
for(ll i = 2; i <= MAX_N; ++i) {
fact[i] = (fact[i-1] * i) % mod;
}
}
e = 0;
if(n == 0) return 1;
long long res = mod_fact(n / mod, e);
e += n / mod;
if((n / mod) % 2 != 0) return (res * (mod - fact[n % mod])) % mod;
return (res * fact[n % mod]) % mod;
}
// return nCk
long long mod_comb(long long n, long long k) {
if(n < 0 || k < 0 || n < k) return 0;
long long e1, e2, e3;
long long a1 = mod_fact(n, e1), a2 = mod_fact(k, e2), a3 = mod_fact(n - k, e3);
if(e1 > e2 + e3) return 0;
return (a1 * mod_inverse((a2 * a3) % mod, mod)) % mod;
}
using mi = modint;
int ans1[201][250][250];
int ans2[251][250][250];
int dx[] = {1, -1, 0, 0}, dy[] = {0, 0, 1, -1};
int h, w;
int gx, gy;
int a[250][250];
int memo(int r, int x, int y) {
if(x < 0 || x >= h || y < 0 || y >= w) return inf;
if(ans2[r][x][y] != -1) return ans2[r][x][y];
if(x == gx && y == gy) return ans2[r][x][y] = a[gx][gy];
int ret = inf;
if(x == gx) {
if(r) ret = min({ret, memo(r - 1, x - 1, y), memo(r - 1, x + 1, y)});
} else if(x > gx) {
ret = min(ret, memo(r, x - 1, y));
if(r) ret = min(ret, memo(r - 1, x + 1, y));
} else {
ret = min(ret, memo(r, x + 1, y));
if(r) ret = min(ret, memo(r - 1, x - 1, y));
}
if(y == gy) {
if(r) ret = min({ret, memo(r - 1, x, y - 1), memo(r - 1, x, y + 1)});
} else if(y > gy) {
ret = min(ret, memo(r, x, y - 1));
if(r) ret = min(ret, memo(r - 1, x, y + 1));
} else {
ret = min(ret, memo(r, x, y + 1));
if(r) ret = min(ret, memo(r - 1, x, y - 1));
}
return ans2[r][x][y] = ret + a[x][y];
}
int main() {
ios::sync_with_stdio(false);
cin.tie(0);
REP(i, 201) REP(j, 250) REP(k, 250) ans1[i][j][k] = inf;
REP(i, 251) REP(j, 250) REP(k, 250) ans2[i][j][k] = -1;
cin >> h >> w;
cin >> gx >> gy;
gx--; gy--;
REP(i, h) REP(j, w) cin >> a[i][j];
FOR(i, 1, 201) {
ans1[i][gx][gy] = a[gx][gy] + i * i;
priority_queue<pair<int, pair<int, int>>, vector<pair<int, pair<int, int>>>, greater<pair<int, pair<int, int>>>> q;
q.push({a[gx][gy] + i * i, {gx, gy}});
while(!q.empty()) {
int cost = q.top().first;
pair<int, int> pos = q.top().second;
q.pop();
if(cost != ans1[i][pos.first][pos.second]) continue;
REP(j, 4) {
pair<int, int> np = {pos.first + dx[j], pos.second + dy[j]};
if(np.first >= 0 && np.first < h && np.second >= 0 &&
np.second < w && ans1[i][np.first][np.second] > cost + a[np.first][np.second] + i * i) {
ans1[i][np.first][np.second] = cost + a[np.first][np.second] + i * i;
q.push({ans1[i][np.first][np.second], np});
}
}
}
}
REP(i, 251) REP(j, h) REP(k, w) {
memo(i, j, k);
}
int q;
cin >> q;
REP(i, q) {
int x, y;
ll k;
cin >> x >> y >> k;
x--; y--;
if(k <= 120) {
cout << ans1[k][x][y] << "\n";
} else {
ll c = abs(gx - x) + abs(gy - y) + 1;
ll ans = inf * inf;
REP(j, 251) {
ans = min(ans, ans2[j][x][y] + (c + j) * k * k);
}
cout << ans << "\n";
}
}
return 0;
}
gazelle