結果

問題 No.868 ハイパー部分和問題
ユーザー 👑 はまやんはまやんはまやんはまやん
提出日時 2019-08-18 10:56:32
言語 C++17
(gcc 13.2.0 + boost 1.83.0)
結果
WA  
実行時間 -
コード長 4,027 bytes
コンパイル時間 2,037 ms
コンパイル使用メモリ 203,188 KB
実行使用メモリ 6,676 KB
最終ジャッジ日時 2024-04-08 22:55:59
合計ジャッジ時間 90,363 ms
ジャッジサーバーID
(参考情報)
judge15 / judge13
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 WA -
testcase_01 WA -
testcase_02 AC 14 ms
6,676 KB
testcase_03 AC 6 ms
6,676 KB
testcase_04 AC 3 ms
6,676 KB
testcase_05 AC 4 ms
6,676 KB
testcase_06 AC 4 ms
6,676 KB
testcase_07 AC 4 ms
6,676 KB
testcase_08 AC 4 ms
6,676 KB
testcase_09 AC 3 ms
6,676 KB
testcase_10 AC 4 ms
6,676 KB
testcase_11 AC 4 ms
6,676 KB
testcase_12 AC 4 ms
6,676 KB
testcase_13 AC 3 ms
6,676 KB
testcase_14 AC 6,423 ms
6,676 KB
testcase_15 AC 6,413 ms
6,676 KB
testcase_16 AC 6,417 ms
6,676 KB
testcase_17 AC 6,423 ms
6,676 KB
testcase_18 AC 6,412 ms
6,676 KB
testcase_19 AC 2,236 ms
6,676 KB
testcase_20 AC 2,242 ms
6,676 KB
testcase_21 AC 2,239 ms
6,676 KB
testcase_22 AC 2,241 ms
6,676 KB
testcase_23 AC 2,244 ms
6,676 KB
testcase_24 AC 2,239 ms
6,676 KB
testcase_25 AC 2,249 ms
6,676 KB
testcase_26 AC 2,242 ms
6,676 KB
testcase_27 AC 2,240 ms
6,676 KB
testcase_28 AC 2,244 ms
6,676 KB
testcase_29 AC 2,995 ms
6,676 KB
testcase_30 AC 2,999 ms
6,676 KB
testcase_31 AC 3,000 ms
6,676 KB
testcase_32 AC 3,990 ms
6,676 KB
testcase_33 AC 3,983 ms
6,676 KB
testcase_34 AC 4,150 ms
6,676 KB
testcase_35 AC 4,134 ms
6,676 KB
testcase_36 AC 3,130 ms
6,676 KB
testcase_37 AC 3,129 ms
6,676 KB
testcase_38 AC 2 ms
6,676 KB
testcase_39 AC 3 ms
6,676 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

#include<bits/stdc++.h>
#define rep(i,a,b) for(int i=a;i<b;i++)
#define rrep(i,a,b) for(int i=a;i>=b;i--)
#define fore(i,a) for(auto &i:a)
#define all(x) (x).begin(),(x).end()
//#pragma GCC optimize ("-O3")
using namespace std; void _main(); int main() { cin.tie(0); ios::sync_with_stdio(false); _main(); }
typedef long long ll; const int inf = INT_MAX / 2; const ll infl = 1LL << 60;
template<class T>bool chmax(T& a, const T& b) { if (a < b) { a = b; return 1; } return 0; }
template<class T>bool chmin(T& a, const T& b) { if (b < a) { a = b; return 1; } return 0; }
//---------------------------------------------------------------------------------------------------
template<int MOD> struct ModInt {
    static const int Mod = MOD; unsigned x; ModInt() : x(0) { }
    ModInt(signed sig) { x = sig < 0 ? sig % MOD + MOD : sig % MOD; }
    ModInt(signed long long sig) { x = sig < 0 ? sig % MOD + MOD : sig % MOD; }
    int get() const { return (int)x; }
    ModInt &operator+=(ModInt that) { if ((x += that.x) >= MOD) x -= MOD; return *this; }
    ModInt &operator-=(ModInt that) { if ((x += MOD - that.x) >= MOD) x -= MOD; return *this; }
    ModInt &operator*=(ModInt that) { x = (unsigned long long)x * that.x % MOD; return *this; }
    ModInt &operator/=(ModInt that) { return *this *= that.inverse(); }
    ModInt operator+(ModInt that) const { return ModInt(*this) += that; }
    ModInt operator-(ModInt that) const { return ModInt(*this) -= that; }
    ModInt operator*(ModInt that) const { return ModInt(*this) *= that; }
    ModInt operator/(ModInt that) const { return ModInt(*this) /= that; }
    ModInt inverse() const { long long a = x, b = MOD, u = 1, v = 0;
        while (b) { long long t = a / b; a -= t * b; std::swap(a, b); u -= t * v; std::swap(u, v); }
        return ModInt(u); }
    bool operator==(ModInt that) const { return x == that.x; }
    bool operator!=(ModInt that) const { return x != that.x; }
    ModInt operator-() const { ModInt t; t.x = x == 0 ? 0 : Mod - x; return t; }
};
template<int MOD> ostream& operator<<(ostream& st, const ModInt<MOD> a) { st << a.get(); return st; };
template<int MOD> ModInt<MOD> operator^(ModInt<MOD> a, unsigned long long k) {
    ModInt<MOD> r = 1; while (k) { if (k & 1) r *= a; a *= a; k >>= 1; } return r; }
typedef ModInt<1000000007> mint1;
typedef ModInt<1000000009> mint2;
/*---------------------------------------------------------------------------------------------------
            ∧_∧
      ∧_∧  (´<_` )  Welcome to My Coding Space!
     ( ´_ゝ`) /  ⌒i     @hamayanhamayan
    /   \     | |
    /   / ̄ ̄ ̄ ̄/  |
  __(__ニつ/     _/ .| .|____
     \/____/ (u ⊃
---------------------------------------------------------------------------------------------------*/














int N, K, A[15101]; int Q;
mint1 dp1[50101];
mint2 dp2[50101];
int MA = 15000;
//---------------------------------------------------------------------------------------------------
void _main() {
	cin >> N >> K;
	rep(i, 0, N) cin >> A[i];
	cin >> Q;

	dp1[0] = 1;
	rep(i, 0, N) if(0 < A[i]) rrep(k, MA * 2, 0) if(k + A[i] <= MA * 2) dp1[k + A[i]] += dp1[k];
	dp2[0] = 1;
	rep(i, 0, N) if (0 < A[i]) rrep(k, MA * 2, 0) if (k + A[i] <= MA * 2) dp2[k + A[i]] += dp2[k];

	rep(q, 0, Q) {
		int x, v; cin >> x >> v;
		x--;

		// reverse
		if (0 < A[x]) {
			rep(k, 0, MA * 2 + 1) if (0 <= k - A[x]) dp1[k] -= dp1[k - A[x]];
			rep(k, 0, MA * 2 + 1) if (0 <= k - A[x]) dp2[k] -= dp2[k - A[x]];
		}

		// change
		A[x] = v;

		// remake
		rrep(k, K * 2, 0) if (0 < A[x]) if (k + v <= MA * 2) dp1[k + v] += dp1[k];
		rrep(k, K * 2, 0) if (0 < A[x]) if (k + v <= MA * 2) dp2[k + v] += dp2[k];

		if (0 < dp1[K].get() and 0 < dp2[K].get()) printf("1\n");
		else printf("0\n");
	}
}



















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