結果
問題 | No.31 悪のミックスジュース |
ユーザー | fumiphys |
提出日時 | 2019-08-19 21:47:35 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 228 ms / 5,000 ms |
コード長 | 4,196 bytes |
コンパイル時間 | 1,397 ms |
コンパイル使用メモリ | 170,556 KB |
実行使用メモリ | 19,144 KB |
最終ジャッジ日時 | 2024-10-05 05:28:21 |
合計ジャッジ時間 | 4,707 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge2 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 17 ms
18,944 KB |
testcase_01 | AC | 188 ms
18,944 KB |
testcase_02 | AC | 198 ms
18,944 KB |
testcase_03 | AC | 226 ms
18,944 KB |
testcase_04 | AC | 226 ms
18,876 KB |
testcase_05 | AC | 219 ms
19,144 KB |
testcase_06 | AC | 2 ms
6,820 KB |
testcase_07 | AC | 210 ms
18,996 KB |
testcase_08 | AC | 221 ms
18,944 KB |
testcase_09 | AC | 228 ms
18,956 KB |
testcase_10 | AC | 2 ms
6,816 KB |
testcase_11 | AC | 84 ms
19,024 KB |
testcase_12 | AC | 158 ms
18,980 KB |
testcase_13 | AC | 33 ms
18,960 KB |
testcase_14 | AC | 207 ms
19,096 KB |
testcase_15 | AC | 73 ms
19,052 KB |
testcase_16 | AC | 106 ms
19,108 KB |
ソースコード
// includes #include <bits/stdc++.h> // macros #define pb emplace_back #define mk make_pair #define pq priority_queue #define FOR(i, a, b) for(int i=(a);i<(b);++i) #define rep(i, n) FOR(i, 0, n) #define rrep(i, n) for(int i=((int)(n)-1);i>=0;i--) #define irep(itr, st) for(auto itr = (st).begin(); itr != (st).end(); ++itr) #define irrep(itr, st) for(auto itr = (st).rbegin(); itr != (st).rend(); ++itr) #define vrep(v, i) for(int i = 0; i < (v).size(); i++) #define all(x) (x).begin(),(x).end() #define sz(x) ((int)(x).size()) #define UNIQUE(v) v.erase(unique(v.begin(), v.end()), v.end()) #define FI first #define SE second #define bit(n) (1LL<<(n)) #define INT(n) int n; cin >> n; #define LL(n) ll n; cin >> n; #define DOUBLE(n) double n; cin >> n; using namespace std; template <class T>bool chmax(T &a, const T &b){if(a < b){a = b; return 1;} return 0;} template <class T>bool chmin(T &a, const T &b){if(a > b){a = b; return 1;} return 0;} template <typename T> istream &operator>>(istream &is, vector<T> &vec){for(auto &v: vec)is >> v; return is;} template <typename T> ostream &operator<<(ostream &os, const vector<T>& vec){for(int i = 0; i < vec.size(); i++){ os << vec[i]; if(i + 1 != vec.size())os << " ";} return os;} template <typename T> ostream &operator<<(ostream &os, const set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;} template <typename T> ostream &operator<<(ostream &os, const unordered_set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;} template <typename T> ostream &operator<<(ostream &os, const multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;} template <typename T> ostream &operator<<(ostream &os, const unordered_multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;} template <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &p){os << p.first << " " << p.second; return os;} template <typename T1, typename T2> ostream &operator<<(ostream &os, const map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end(); ++itr){ os << itr->first << ":" << itr->second; auto titr = itr; if(++titr != mp.end())os << " "; } return os;} template <typename T1, typename T2> ostream &operator<<(ostream &os, const unordered_map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end(); ++itr){ os << itr->first << ":" << itr->second; auto titr = itr; if(++titr != mp.end())os << " "; } return os;} // types using ll = long long int; using P = pair<int, int>; using Pli = pair<ll, int>; using Pil = pair<int, ll>; using Pll = pair<ll, ll>; using Pdd = pair<double, double>; using cd = complex<double>; // constants const int inf = 1e9; //const ll linf = 1LL << 50; const ll linf = numeric_limits<ll>::max(); const double EPS = 1e-10; const int mod = 1e9 + 7; const int dx[4] = {-1, 0, 1, 0}; const int dy[4] = {0, -1, 0, 1}; // solve ll dp[2000010]; int main(int argc, char const* argv[]) { ios_base::sync_with_stdio(false); cin.tie(0); cout << fixed << setprecision(20); INT(n); LL(v); vector<ll> c(n); cin >> c; vector<ll> cs(n, 0); rep(i, n)cs[i] = (i > 0 ? cs[i-1]: 0) + c[i]; if(v <= n){ cout << cs[n-1] << endl; return 0; } v -= n; int m = 2000000; rep(i, m + 1)dp[i] = linf; dp[0] = 0; rep(i, n){ rep(j, m + 1){ if(j - i - 1 >= 0)dp[j] = min(dp[j], dp[j - i - 1] + cs[i]); } } for(int i = m - 1; i >= 0; i--){ dp[i] = min(dp[i], dp[i+1]); } double mini = 1e18; int at = 0; rep(i, n){ double tmp = (double(cs[i])) / (double(i + 1)); if(mini > tmp){ mini = tmp; at = i; } } ll res = linf; for(int i = 0; i <= m; i++){ ll tmp = cs[n-1]; ll tar = v - i; if(tar < 0)break; ll req = (tar + at) / (at + 1); ll rem = v - req * (at + 1); tmp += req * cs[at]; if(rem > 0 && rem <= m)tmp += dp[rem]; res = min(res, tmp); } cout << res << endl; return 0; }