#37161 (C++11) No.245 貫け！

提出ソース

結果

問題	No.245 貫け！
ユーザー	shimomire
提出日時	2015-07-17 22:38:11
言語	C++11 (gcc 11.4.0)
結果	WA
実行時間	-
コード長	10,205 bytes
コンパイル時間	1,393 ms
コンパイル使用メモリ	126,340 KB
実行使用メモリ	6,944 KB
最終ジャッジ日時	2024-07-08 08:31:12
合計ジャッジ時間	2,431 ms
ジャッジサーバーID （参考情報）	judge2 / judge3

このコードへのチャレンジ
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テストケース

テストケース表示

入力	結果	実行時間実行使用メモリ
testcase_00	AC	1 ms 6,816 KB
testcase_01	AC	2 ms 6,944 KB
testcase_02	AC	2 ms 6,940 KB
testcase_03	AC	2 ms 6,944 KB
testcase_04	AC	1 ms 6,940 KB
testcase_05	AC	2 ms 6,944 KB
testcase_06	AC	2 ms 6,940 KB
testcase_07	AC	2 ms 6,944 KB
testcase_08	AC	2 ms 6,940 KB
testcase_09	WA	-
testcase_10	AC	7 ms 6,944 KB
testcase_11	AC	25 ms 6,944 KB
testcase_12	AC	68 ms 6,944 KB
testcase_13	WA	-
testcase_14	WA	-
testcase_15	AC	69 ms 6,944 KB
testcase_16	WA	-
testcase_17	WA	-
testcase_18	WA	-
testcase_19	WA	-

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ソースコード

raw source code

#include <cassert>// c
#include <iostream>// io
#include <iomanip>
#include <fstream>
#include <sstream>
#include <vector>// container
#include <map>
#include <set>
#include <queue>
#include <bitset>
#include <stack>
#include <algorithm>// other
#include <complex>
#include <numeric>
#include <functional>
#include <random>
#include <regex>
using namespace std;

typedef long long ll;
typedef unsigned long long ull;

#define ALL(c) (begin(c)),(end(c))
#define REP(i,n) FOR(i,0,n)
#define REPr(i,n) FORr(i,0,n)
#define FOR(i,l,r) for(int i=(int)(l);i<(int)(r);++i)
#define FORr(i,l,r) for(int i=(int)(r)-1;i>=(int)(l);--i)
#define EACH(it,o) for(auto it = (o).begin(); it != (o).end(); ++it)
#define IN(l,v,r) ((l)<=(v) && (v)<(r))
#define UNIQUE(v) v.erase(unique(ALL(v)),v.end())
//debug
#define DUMP(x)  cerr << #x << " = " << (x)
#define LINE()    cerr<< " (L" << __LINE__ << ")"

class range {
private:
	struct Iter{
		int v;
		int operator*(){return v;}
		bool operator!=(Iter& itr) {return v < itr.v;}
		void operator++() {++v;}
	};
	Iter i, n;
public:
	range(int n) : i({0}), n({n}) {}
	range(int i, int n) : i({i}), n({n}) {}
	Iter& begin() {return i;}
	Iter& end() {return n;}
};

//input
template<typename T1,typename T2> istream& operator >> (istream& is,pair<T1,T2>& p){is>>p.first>>p.second;return is;}
template<typename T1> istream& operator >> (istream& is,tuple<T1>& t){is >> get<0>(t);return is;}
template<typename T1,typename T2> istream& operator >> (istream& is,tuple<T1,T2>& t){is >> get<0>(t) >> get<1>(t);return is;}
template<typename T1,typename T2,typename T3> istream& operator >> (istream& is,tuple<T1,T2,T3>& t){is >>get<0>(t)>>get<1>(t)>>get<2>(t);return is;}
template<typename T1,typename T2,typename T3,typename T4> istream& operator >> (istream& is,tuple<T1,T2,T3,T4>& t){is >> get<0>(t)>>get<1>(t)>>get<2>(t)>>get<3>(t);return is;}
template<typename T1,typename T2,typename T3,typename T4,typename T5> istream& operator >> (istream& is, const tuple<T1,T2,T3,T4,T5>& t){is >> get<0>(t) >> get<1>(t) >> get<2>(t) >> get<3>(t) >> get<4>(t);return is;}
template<typename T1,typename T2,typename T3,typename T4,typename T5,typename T6> istream& operator >> (istream& is, const tuple<T1,T2,T3,T4,T5,T6>& t){is >> get<0>(t) >> get<1>(t) >> get<2>(t) >> get<3>(t) >> get<4>(t) >> get<5>(t);return is;}
template<typename T1,typename T2,typename T3,typename T4,typename T5,typename T6,typename T7> istream& operator >> (istream& is, const tuple<T1,T2,T3,T4,T5,T6,T7>& t){is >> get<0>(t) >> get<1>(t) >> get<2>(t) >> get<3>(t) >> get<4>(t) >> get<5>(t) >> get<6>(t);return is;}
template<typename T> istream& operator >> (istream& is,vector<T>& as){REP(i,as.size())is >>as[i];return is;}

//output
template<typename T> ostream& operator << (ostream& os, const set<T>& ss){for(auto a:ss){if(a!=ss.begin())os<<" "; os<<a;}return os;}
template<typename T1,typename T2> ostream& operator << (ostream& os, const pair<T1,T2>& p){os<<p.first<<" "<<p.second;return os;}
template<typename K,typename V> ostream& operator << (ostream& os, const map<K,V>& m){bool isF=true;for(auto& p:m){if(!isF)os<<endl;os<<p;isF=false;}return os;}
template<typename T1> ostream& operator << (ostream& os, const tuple<T1>& t){os << get<0>(t);return os;}
template<typename T1,typename T2> ostream& operator << (ostream& os, const tuple<T1,T2>& t){os << get<0>(t)<<" "<<get<1>(t);return os;}
template<typename T1,typename T2,typename T3> ostream& operator << (ostream& os, const tuple<T1,T2,T3>& t){os << get<0>(t)<<" "<<get<1>(t)<<" "<<get<2>(t);return os;}
template<typename T1,typename T2,typename T3,typename T4> ostream& operator << (ostream& os, const tuple<T1,T2,T3,T4>& t){os << get<0>(t)<<" "<<get<1>(t)<<" "<<get<2>(t)<<" "<<get<3>(t);return os;}
template<typename T1,typename T2,typename T3,typename T4,typename T5> ostream& operator << (ostream& os, const tuple<T1,T2,T3,T4,T5>& t){os << get<0>(t)<<" "<<get<1>(t)<<" "<<get<2>(t)<<" "<<get<3>(t)<<" "<<get<4>(t);return os;}
template<typename T1,typename T2,typename T3,typename T4,typename T5,typename T6> ostream& operator << (ostream& os, const tuple<T1,T2,T3,T4,T5,T6>& t){os << get<0>(t)<<" "<<get<1>(t)<<" "<<get<2>(t)<<" "<<get<3>(t)<<" "<<get<4>(t)<<" "<<get<5>(t);return os;}
template<typename T1,typename T2,typename T3,typename T4,typename T5,typename T6,typename T7> ostream& operator << (ostream& os, const tuple<T1,T2,T3,T4,T5,T6,T7>& t){os << get<0>(t)<<" "<<get<1>(t)<<" "<<get<2>(t)<<" "<<get<3>(t)<<" "<<get<4>(t)<<" "<<get<5>(t)<<" "<<get<6>(t);return os;}
template<typename T> ostream& operator << (ostream& os, const vector<T>& as){REP(i,as.size()){if(i!=0)os<<" "; os<<as[i];}return os;}
template<typename T> ostream& operator << (ostream& os, const vector<vector<T>>& as){REP(i,as.size()){if(i!=0)os<<endl; os<<as[i];}return os;}

//input
char tmp[1000];
#define nextInt(n) scanf("%d",&n)
#define nextLong(n) scanf("%lld",&n) //I64d
#define nextDouble(n) scanf("%lf",&n) 
#define nextChar(n) scanf("%c",&n)
#define nextString(n) scanf("%s",tmp);n=tmp

// values
template<typename T> T INF(){assert(false);};
template<> int INF<int>(){return 1<<28;};
template<> ll INF<ll>(){return 1LL<<58;};
template<> double INF<double>(){return 1e16;};
template<> long double INF<long double>(){return 1e16;};

template<class T> T EPS(){assert(false);};
template<> int EPS<int>(){return 1;};
template<> ll EPS<ll>(){return 1LL;};
template<> double EPS<double>(){return 1e-8;};
template<> long double EPS<long double>(){return 1e-8;};

template<typename T,typename U> T pmod(T v,U M){return (v%M+M)%M;}



namespace _double_tmpl{
	typedef long double D;
	
	static constexpr D Ae=0;
	D A(D a,D b){return a+b;}D Ainv(D a){return -a;}
	D S(D a,D b){return A(a,Ainv(b));}
	
	static constexpr D Me=1;
	D M(D a,D b){return a*b;}D Minv(D a){return 1.0/a;};

	int sig(D a,D b=0){return a<b-EPS<D>()?-1:a>b+EPS<D>()?1:0;}
	template<typename T> bool eq(const T& a,const T& b){return sig(abs(a-b))==0;}

	D pfmod(D v,D MOD=2*M_PI){return fmod(fmod(v,MOD)+MOD,MOD);}
	
	//[0,PI)
	D AbsArg(D a){
		D ret=pfmod(max(a,-a),2*M_PI);return min(ret,2*M_PI-ret);
	}
}
using namespace _double_tmpl;

typedef complex<D> P,Vec;
const P O=P(0,0);
#define X real()
#define Y imag()
istream& operator >> (istream& is,complex<D>& p){
	D x,y;is >> x >> y;p=P(x,y);return is;
}
bool compX (const P& a,const P& b){return !eq(a.X,b.X)?sig(a.X,b.X)<0:sig(a.Y,b.Y)<0;}
bool compY (const P& a,const P& b){return !eq(a.Y,b.Y)?sig(a.Y,b.Y)<0:sig(a.X,b.X)<0;}

// a×b
D cross(const Vec& a,const Vec& b){return imag(conj(a)*b);}
// a・b
D dot(const Vec&a,const Vec& b) {return real(conj(a)*b);}

int ccw(const P& a,P b,P c){
	b -= a; c -= a;
	if (sig(cross(b,c))>0)   return +1;       // counter clockwise
	if (sig(cross(b,c))<0)   return -1;       // clockwise
	if (sig(dot(b,c)) < 0)     return +2;       // c--a--b on line
	if (sig(norm(b),norm(c))<0) return -2;       // a--b--c on line
	return 0;
}

namespace std{
	bool operator < (const P& a,const P& b){return compX(a,b);}
  	bool operator == (const P& a,const P& b){return eq(a,b);}
};

namespace _L{
	struct L : public vector<P> {
		P vec() const {return this->at(1)-this->at(0);}
		L(const P &a, const P &b){push_back(a); push_back(b);}
		L(){push_back(P(0,0));push_back(P(0,0));}
	};
	istream& operator >> (istream& is,L& l){P s,t;is >> s >> t;l=L(s,t);return is;}

	bool isIntersectLL(const L &l, const L &m) {
	 	return sig(cross(l.vec(), m.vec()))!=0 || // non-parallel
	    sig(cross(l.vec(), m[0]-l[0])) ==0;   // same line
	}
	bool isIntersectLS(const L &l, const L &s) {
	  return sig(cross(l.vec(), s[0]-l[0])*       // s[0] is left of l
	         cross(l.vec(), s[1]-l[0]))<=0; // s[1] is right of l
	}
	bool isIntersectLP(const L &l, const P &p) {
		return sig(cross(l[1]-p, l[0]-p))==0;
	}

	// verified by ACAC003 B
	// http://judge.u-aizu.ac.jp/onlinejudge/creview.jsp?rid=899178&cid=ACAC003
	bool isIntersectSS(const L &s, const L &t) {
	  return ccw(s[0],s[1],t[0])*ccw(s[0],s[1],t[1]) <= 0 &&
	         ccw(t[0],t[1],s[0])*ccw(t[0],t[1],s[1]) <= 0;
	}
	bool isIntersectSP(const L &s, const P &p) {
	  return sig(abs(s[0]-p)+abs(s[1]-p),abs(s[1]-s[0])) <=0; // triangle inequality
	}

	// 直線へ射影した時の点
    // verified by AOJLIB
    // http://judge.u-aizu.ac.jp/onlinejudge/review.jsp?rid=1092212
	P projection(const L &l, const P &p) {
	  D t = dot(p-l[0],l.vec()) / norm(l.vec());
	  return l[0] + t * l.vec();
	}
	//対称な点
	// verified by AOJLIB
	// http://judge.u-aizu.ac.jp/onlinejudge/review.jsp?rid=1092214
	P reflection(const L &l, const P &p) {
	  return p + 2.0L * (projection(l, p) - p);
	}
	D distanceLP(const L &l, const P &p) {
	  return abs(p - projection(l, p));
	}
	D distanceLL(const L &l, const L &m) {
	  return isIntersectLL(l, m) ? 0 : distanceLP(l, m[0]);
	}
	D distanceLS(const L &l, const L &s) {
		if (isIntersectLS(l, s)) return 0;
		return min(distanceLP(l, s[0]), distanceLP(l, s[1]));
	}
	D distanceSP(const L &s, const P &p) {
	  const P r = projection(s, p);
	  if (isIntersectSP(s, r)) return abs(r - p);
	  return min(abs(s[0] - p), abs(s[1] - p));
	}
	D distanceSS(const L &s, const L &t) {
		if (isIntersectSS(s, t)) return 0;
		return min(min(distanceSP(s, t[0]), distanceSP(s, t[1])),
	             min(distanceSP(t, s[0]), distanceSP(t, s[1])));
	}

	// 交点計算
	// verified by AOJLIB
	// http://judge.u-aizu.ac.jp/onlinejudge/review.jsp?rid=1092231
	P crosspoint(const L &l, const L &m) {
	  D A = cross(l.vec(), m.vec()),B = cross(l.vec(), l[1] - m[0]);
	  if (sig(A)==0 && sig(B)==0) return m[0]; // same line
	  assert(sig(A)!=0);//err -> 交点を持たない．
	  return m[0] + B / A * (m[1] - m[0]);
	}
}
using namespace _L;


ll MOD =1e9+7;

class Main{
	public:

	void run(){
		int N;cin >> N;
		vector<P> ps(2*N);cin >> ps;
		vector<L> ls(N);
		for(int i:range(N))ls[i]=L(ps[2*i],ps[2*i+1]);


		int res = 0;
		for(int i:range(2*N))for(int j:range(2*N))if(i!=j){
			L l1=L(ps[i],ps[j]);

			int c = 0;
			for(int k:range(N))if(isIntersectLS(l1,ls[k]))c++;
			res=max(res,c);
		}
		cout << res <<endl;
	}
};

int main(){
	cout <<fixed<<setprecision(20);
	cin.tie(0);
	ios::sync_with_stdio(false);
	Main().run();
	return 0;
}

yukicoder

結果

テストケース

ソースコード