結果
問題 | No.247 線形計画問題もどき |
ユーザー |
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提出日時 | 2015-07-17 22:56:01 |
言語 | C++11(廃止可能性あり) (gcc 13.3.0) |
結果 |
AC
|
実行時間 | 1,792 ms / 2,000 ms |
コード長 | 1,860 bytes |
コンパイル時間 | 2,292 ms |
コンパイル使用メモリ | 202,944 KB |
実行使用メモリ | 12,956 KB |
最終ジャッジ日時 | 2024-07-08 09:22:07 |
合計ジャッジ時間 | 10,040 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge5 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 5 |
other | AC * 23 |
コンパイルメッセージ
main.cpp: In function ‘int main()’: main.cpp:36:14: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 36 | scanf("%d", &c); | ~~~~~^~~~~~~~~~ main.cpp:37:14: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 37 | scanf("%d", &n); | ~~~~~^~~~~~~~~~ main.cpp:40:22: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 40 | scanf("%d", &a); | ~~~~~^~~~~~~~~~
ソースコード
#include<iostream>#include<cstdio>#include<cstring>#include<string>#include<cctype>#include<cstdlib>#include<algorithm>#include<bitset>#include<vector>#include<list>#include<deque>#include<queue>#include<map>#include<set>#include<stack>#include<cmath>#include<sstream>#include<fstream>#include<iomanip>#include<ctime>#include<complex>#include<functional>#include<climits>#include<cassert>#include<iterator>#include<immintrin.h>#include<unordered_map>using namespace std;int c;int n;#define MAX 100002vector<int> v;unordered_map<int, vector<pair<int,int> > > dp;int su[MAX];int main(){scanf("%d", &c);scanf("%d", &n);for (int i = 0; i < n; i++){int a;scanf("%d", &a);v.push_back(a);}sort(v.begin(), v.end());v.erase(unique(v.begin(), v.end()),v.end());dp[0].push_back(make_pair(0, 0));for (int i = 0; i < v.size(); i++){for (int j = 0; j <= c; j++){int ind = j%v[i];if (dp.count(ind) == 0){su[j] = INT_MAX;continue;}int ind2 = upper_bound(dp[ind].begin(), dp[ind].end(), make_pair(j, INT_MAX)) - dp[ind].begin();ind2--;if (ind2 < 0){su[j] = INT_MAX;continue;}int val = dp[ind][ind2].first;int sa = abs(val - j);sa /= v[i];sa += dp[ind][ind2].second;su[j] = sa;}dp.clear();if (i + 1 == v.size()){break;}for (int j = 0; j <= c; j++){if (su[j] == INT_MAX){continue;}dp[j%v[i + 1]].push_back(make_pair(j,su[j]));}for (int j = 0; j < v[i + 1]; j++){if (dp.count(j)){sort(dp[j].begin(), dp[j].end());for (int k = 1; k < dp[j].size(); k++){dp[j][k].second = min(dp[j][k].second, dp[j][k - 1].second + abs(dp[j][k - 1].first - dp[j][k].first) / v[i + 1]);}}}}int ans = su[c];if (ans == INT_MAX){puts("-1");return 0;}cout << ans << endl;return 0;}