結果
問題 |
No.247 線形計画問題もどき
|
ユーザー |
|
提出日時 | 2015-07-17 23:34:25 |
言語 | C90 (gcc 12.3.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 280 bytes |
コンパイル時間 | 202 ms |
コンパイル使用メモリ | 20,224 KB |
実行使用メモリ | 5,376 KB |
最終ジャッジ日時 | 2024-07-08 09:37:26 |
合計ジャッジ時間 | 1,056 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 1 WA * 4 |
other | AC * 8 WA * 15 |
コンパイルメッセージ
main.c:1:1: warning: data definition has no type or storage class 1 | a[100],b[100000],C,N,i,k; | ^ main.c:1:1: warning: type defaults to ‘int’ in declaration of ‘a’ [-Wimplicit-int] main.c:1:8: warning: type defaults to ‘int’ in declaration of ‘b’ [-Wimplicit-int] 1 | a[100],b[100000],C,N,i,k; | ^ main.c:1:18: warning: type defaults to ‘int’ in declaration of ‘C’ [-Wimplicit-int] 1 | a[100],b[100000],C,N,i,k; | ^ main.c:1:20: warning: type defaults to ‘int’ in declaration of ‘N’ [-Wimplicit-int] 1 | a[100],b[100000],C,N,i,k; | ^ main.c:1:22: warning: type defaults to ‘int’ in declaration of ‘i’ [-Wimplicit-int] 1 | a[100],b[100000],C,N,i,k; | ^ main.c:1:24: warning: type defaults to ‘int’ in declaration of ‘k’ [-Wimplicit-int] 1 | a[100],b[100000],C,N,i,k; | ^ main.c:3:1: warning: return type defaults to ‘int’ [-Wimplicit-int] 3 | main(m){ | ^~~~ main.c: In function ‘main’: main.c:3:1: warning: type of ‘m’ defaults to ‘int’ [-Wimplicit-int] main.c:4:9: warning: implicit declaration of function ‘scanf’ [-Wimplicit-function-declaration] 4 | scanf("%d%d",&C,&N); | ^~~~~ main.c:1:1: note: include ‘<stdio.h>’ or provide a declaration of ‘scanf’ +++ |+#include <stdio.h> 1 | a[100],b[100000],C,N,i,k; main.c:4:9: warning: incompatible implicit declaration of built-in function ‘scanf’ [-Wbuiltin-declaration-mismatch] 4 | scanf("%d%d",&C,&N); | ^~~~~ main.c:4:9: note: include ‘<stdio.h>’ or provide a declaration of ‘scanf’ main.c:14:9: warning: implicit declaration of function ‘printf’ [-Wimplicit-function-declaration] 14 | printf("%d\n",b[C]?:-1); | ^~~~~~ main.c:14:9: note: include ‘<stdio.h>’ or provide a declaration of ‘printf’ main.c:14
ソースコード
a[100],b[100000],C,N,i,k; main(m){ scanf("%d%d",&C,&N); for(;i<N;i++)scanf("%d",a+i); for(;m<=N;m++){ k=-1; for(i=0;i<N;i++){ if(m >= a[i] && b[m-a[i]] >= 0 && (k < 0 || b[m-a[i]] + 1 < k)) k = b[m-a[i]] + 1; } b[m] = k; } printf("%d\n",b[C]?:-1); exit(0); }