結果

問題 No.875 Range Mindex Query
ユーザー 里旬
提出日時 2019-09-08 00:12:43
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 66 ms / 2,000 ms
コード長 2,132 bytes
コンパイル時間 1,839 ms
コンパイル使用メモリ 194,696 KB
最終ジャッジ日時 2025-01-07 17:22:36
ジャッジサーバーID
(参考情報)
judge5 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 1
other AC * 18
権限があれば一括ダウンロードができます
コンパイルメッセージ
main.cpp: In function ‘int main()’:
main.cpp:60:10: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
   60 |     scanf("%d%d", &N, &Q);
      |     ~~~~~^~~~~~~~~~~~~~~~
main.cpp:64:14: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
   64 |         scanf("%d", &a);
      |         ~~~~~^~~~~~~~~~
main.cpp:70:14: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
   70 |         scanf("%d%d%d", &t, &l, &r);
      |         ~~~~~^~~~~~~~~~~~~~~~~~~~~~

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
using namespace std;
template<typename Tp>
class segtree{
Tp *tree;
Tp (*operation)(const Tp&, const Tp&);
Tp ident;
size_t len, depth;
public:
segtree(size_t n, Tp (*op)(const Tp&, const Tp&), Tp id)
: operation(op), ident(id){
for(depth=1;(1ULL<<depth)<n;++depth);
len = 1ULL<<depth;
++depth;
tree = new Tp[2*len];
for(size_t i=0;i<2*len;++i) tree[i] = id;
}
~segtree(){
delete[] tree;
}
void update(size_t pos, Tp val){
tree[len+pos] = val;
for(size_t p=(len+pos)>>1;p>0;p>>=1){
tree[p] = operation(tree[2*p], tree[2*p+1]);
}
}
void add(size_t pos, Tp val){
tree[len+pos] += val;
for(size_t p=(len+pos)>>1;p>0;p>>=1){
tree[p] = operation(tree[2*p], tree[2*p+1]);
}
}
Tp queue(size_t left, size_t right){
Tp lval = ident, rval = ident;
left += len;
right += len;
while(true){
if(left >= right) return operation(lval, rval);
if(right - left == 1) return operation(lval, operation(tree[left], rval));
if(left & 1) lval = operation(lval, tree[left++]);
left >>= 1;
if(right & 1) rval = operation(tree[right-1], rval);
right >>= 1;
}
}
Tp &operator[](size_t pos){
return tree[len+pos];
}
void refresh(){
for(size_t p=len-1;p>0;--p){
tree[p] = operation(tree[2*p], tree[2*p+1]);
}
}
};
int main(){
int N, Q;
int a, t, l, r;
scanf("%d%d", &N, &Q);
segtree<pair<int,int>> st(N, [](auto x, auto y){ return min(x, y); }, {N+1, -1});
for(int i=0;i<N;++i){
scanf("%d", &a);
st[i] = {a, i+1};
}
st.refresh();
for(int i=0;i<Q;++i){
scanf("%d%d%d", &t, &l, &r);
if(t==1){
int tmp = st[l-1].first;
st.update(l-1, {st[r-1].first, st[l-1].second});
st.update(r-1, {tmp, st[r-1].second});
}
else printf("%d\n", st.queue(l-1, r).second);
}
return 0;
}
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