結果

問題 No.917 Make One With GCD
ユーザー ningenMeningenMe
提出日時 2019-09-09 04:50:34
言語 C++14
(gcc 12.3.0 + boost 1.83.0)
結果
RE  
実行時間 -
コード長 2,714 bytes
コンパイル時間 1,775 ms
コンパイル使用メモリ 176,592 KB
実行使用メモリ 5,376 KB
最終ジャッジ日時 2024-06-28 00:30:53
合計ジャッジ時間 6,442 ms
ジャッジサーバーID
(参考情報)
judge1 / judge4
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 RE -
testcase_01 AC 2 ms
5,376 KB
testcase_02 AC 2 ms
5,376 KB
testcase_03 AC 2 ms
5,376 KB
testcase_04 AC 2 ms
5,376 KB
testcase_05 WA -
testcase_06 RE -
testcase_07 RE -
testcase_08 RE -
testcase_09 RE -
testcase_10 RE -
testcase_11 RE -
testcase_12 RE -
testcase_13 RE -
testcase_14 RE -
testcase_15 RE -
testcase_16 RE -
testcase_17 RE -
testcase_18 RE -
testcase_19 RE -
testcase_20 RE -
testcase_21 RE -
testcase_22 RE -
testcase_23 RE -
testcase_24 RE -
testcase_25 RE -
testcase_26 RE -
testcase_27 AC 2 ms
5,376 KB
testcase_28 AC 2 ms
5,376 KB
testcase_29 WA -
testcase_30 RE -
testcase_31 RE -
testcase_32 RE -
testcase_33 RE -
testcase_34 RE -
testcase_35 RE -
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ソースコード

diff #

#include <bits/stdc++.h>
using namespace std;

template <class T, class U>ostream &operator<<(ostream &o, const map<T, U>&obj) {o << "{"; for (auto &x : obj) o << " {" << x.first << " : " << x.second << "}" << ","; o << " }"; return o;}
template <class T>ostream &operator<<(ostream &o, const set<T>&obj) {o << "{"; for (auto itr = obj.begin(); itr != obj.end(); ++itr) o << (itr != obj.begin() ? ", " : "") << *itr; o << "}"; return o;}
template <class T>ostream &operator<<(ostream &o, const multiset<T>&obj) {o << "{"; for (auto itr = obj.begin(); itr != obj.end(); ++itr) o << (itr != obj.begin() ? ", " : "") << *itr; o << "}"; return o;}
template <class T>ostream &operator<<(ostream &o, const vector<T>&obj) {o << "{"; for (int i = 0; i < (int)obj.size(); ++i)o << (i > 0 ? ", " : "") << obj[i]; o << "}"; return o;}
template <class T, class U>ostream &operator<<(ostream &o, const pair<T, U>&obj) {o << "{" << obj.first << ", " << obj.second << "}"; return o;}
template <template <class tmp>  class T, class U> ostream &operator<<(ostream &o, const T<U> &obj) {o << "{"; for (auto itr = obj.begin(); itr != obj.end(); ++itr)o << (itr != obj.begin() ? ", " : "") << *itr; o << "}"; return o;}
void print(void) {cout << endl;}
template <class Head> void print(Head&& head) {cout << head;print();}
template <class Head, class... Tail> void print(Head&& head, Tail&&... tail) {cout << head << " ";print(forward<Tail>(tail)...);}

//divisor O(sqrt(N))
set<long long> Divisor(long long N) {
    set<long long> ret;
    for (long long i = 1; i*i <= N; ++i) {
        if (N%i == 0) {
            ret.insert(i);
            ret.insert(N / i);
        }
    }
    return ret;
}

//Greatest Common Divisor
long long GCD(long long a, long long b) {
    return ((b == 0) ? a : GCD(b, a % b));
}

//半分全列挙嘘解法
int main() {
	int N,MAX_A = 10; cin >> N;
	vector<int> A(N);
	for(int i = 0; i < N; ++i) cin >> A[i];
	if(N==1){
		cout << (A[0]==1) << endl;
		return 0;
	}

	vector<int> L,R;
	for(int i = 0; i < N/2; ++i) L.push_back(A[i]);
	for(int i = N/2; i < N; ++i) R.push_back(A[i]);
	vector<int> cntL(MAX_A+1,0),cntR(MAX_A+1,0);
	int NL = L.size(), NR = R.size();
	for(int i = 1; i < (1<<NL); ++i){
		int cnt = 0;
		for(int j = 0; j < NL; ++j) if(i&(1<<j)) cnt = GCD(cnt,A[j]);
		cntL[cnt]++;
	}
	for(int i = 1; i < (1<<NR); ++i){
		int cnt = 0;
		for(int j = 0; j < NR; ++j) if(i&(1<<j)) cnt = GCD(cnt,A[j+(N/2)]);
		cntR[cnt]++;
	}

	int ans = cntL[1]+cntR[1]+cntL[1]*cntR[1];
	int sum = accumulate(cntR.begin(),cntR.end(),0);
	for(int i = 1; i <= MAX_A; ++i){
		int cnt = sum;
		auto d = Divisor(i);
		for(auto e:d) cnt -= cntR[e];
		cnt *= cntL[i];
		ans += cnt;
	}
	cout << ans << endl;
	return 0;
}
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