結果

問題 No.269 見栄っ張りの募金活動
ユーザー frmon60frmon60
提出日時 2019-09-09 19:45:15
言語 C++14
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 9 ms / 5,000 ms
コード長 2,984 bytes
コンパイル時間 1,596 ms
コンパイル使用メモリ 170,300 KB
実行使用メモリ 11,520 KB
最終ジャッジ日時 2024-06-28 13:56:39
合計ジャッジ時間 2,635 ms
ジャッジサーバーID
(参考情報)
judge3 / judge2
このコードへのチャレンジ
(要ログイン)

テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 5 ms
11,308 KB
testcase_01 AC 6 ms
11,244 KB
testcase_02 AC 5 ms
11,436 KB
testcase_03 AC 6 ms
11,308 KB
testcase_04 AC 8 ms
11,324 KB
testcase_05 AC 5 ms
11,308 KB
testcase_06 AC 6 ms
11,392 KB
testcase_07 AC 9 ms
11,372 KB
testcase_08 AC 5 ms
11,308 KB
testcase_09 AC 7 ms
11,264 KB
testcase_10 AC 6 ms
11,312 KB
testcase_11 AC 6 ms
11,308 KB
testcase_12 AC 6 ms
11,276 KB
testcase_13 AC 6 ms
11,476 KB
testcase_14 AC 6 ms
11,300 KB
testcase_15 AC 7 ms
11,264 KB
testcase_16 AC 6 ms
11,304 KB
testcase_17 AC 6 ms
11,272 KB
testcase_18 AC 8 ms
11,436 KB
testcase_19 AC 6 ms
11,520 KB
testcase_20 AC 5 ms
11,392 KB
testcase_21 AC 6 ms
11,308 KB
testcase_22 AC 6 ms
11,440 KB
testcase_23 AC 5 ms
11,372 KB
testcase_24 AC 6 ms
11,248 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

#include <bits/stdc++.h>
using namespace std;
using Int = long long;
typedef pair<int,int> P; typedef priority_queue<int> Pr; typedef vector<int> V; typedef vector<P> Vp; typedef map<int,int> MP;
const int mod = 1000000007; const Int INF = 1145141919810893931;
#define rer(i,l,u) for(int (i)=(int)(l);(i)<=(int)(u);++(i))
#define END {cout<<ans<<'\n'; return 0;}
template<class T> inline bool cmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }
template<class T> inline bool cmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }

template<int MOD>
struct ModInt {
	static const int Mod = MOD;
	unsigned x;
	ModInt() : x(0) {}
	ModInt(signed sig) { int sigt = sig % MOD; if(sigt < 0) sigt += MOD; x = sigt; }
	ModInt(signed long long sig) { int sigt = sig % MOD; if(sigt < 0) sigt += MOD; x = sigt; }
	int get() const { return (int)x; }

	ModInt &operator+=(ModInt that) { if((x += that.x) >= MOD) x -= MOD; return *this; }
	ModInt &operator-=(ModInt that) { if((x += MOD - that.x) >= MOD) x -= MOD; return *this; }
	ModInt &operator*=(ModInt that) { x = (unsigned long long)x * that.x % MOD; return *this; }
	ModInt &operator/=(ModInt that) { return *this *= that.inverse(); }

	ModInt operator+(ModInt that) const { return ModInt(*this) += that; }
	ModInt operator-(ModInt that) const { return ModInt(*this) -= that; }
	ModInt operator*(ModInt that) const { return ModInt(*this) *= that; }
	ModInt operator/(ModInt that) const { return ModInt(*this) /= that; }

	ModInt inverse() const {
		signed a = x, b = MOD, u = 1, v = 0;
		while(b) {
			signed t = a / b;
			a -= t * b; std::swap(a, b);
			u -= t * v; std::swap(u, v);
		}
		if(u < 0) u += Mod;
		ModInt res; res.x = (unsigned)u;
		return res;
	}

	bool operator==(ModInt that) const { return x == that.x; }
	bool operator!=(ModInt that) const { return x != that.x; }
	ModInt operator-() const { ModInt t; t.x = x == 0 ? 0 : Mod - x; return t; }
};
template<int MOD> ModInt<MOD> operator^(ModInt<MOD> a, unsigned long long k) {
	ModInt<MOD> r = 1;
	while(k) {
		if(k & 1) r *= a;
		a *= a;
		k >>= 1;
	}
	return r;
}
typedef ModInt<mod> mint;
vector<mint> fact, factinv;

void COMinit(int N) {
	N = min(N, mint::Mod - 1);
	fact.resize(N + 1); factinv.resize(N + 1);
	fact[0] = 1;
	rer(i, 1, N) fact[i] = fact[i - 1] * i;
	factinv[N] = fact[N].inverse();
	for(int i = N; i >= 1; i --) factinv[i - 1] = factinv[i] * i;
}

mint C(int n, int r) {
	if(n >= mint::Mod)
		return C(n % mint::Mod, r % mint::Mod) * C(n / mint::Mod, r / mint::Mod);
	return r > n ? 0 : fact[n] * factinv[n - r] * factinv[r];
}

mint dp[101][20001];

int main(){
    cin.tie(0);
    ios::sync_with_stdio(false);

    int n,s,k; cin>>n>>s>>k; int ans=0;
    COMinit(40000);
    dp[0][0]=1;
    for (int i = 1; i <= n; i++){
        for (int j = 0; j <= s; j++){
            if(j>=i)dp[i][j]=dp[i-1][j]+dp[i][j-i];
            else dp[i][j]=dp[i-1][j];
        }
    }
    if(k*n*(n-1)/2>s)END
    cout<<dp[n][s-k*n*(n-1)/2].get()<<'\n';
}
0