結果
| 問題 | No.880 Yet Another Segment Tree Problem |
| コンテスト | |
| ユーザー |
HIR180
|
| 提出日時 | 2019-09-10 21:50:29 |
| 言語 | C++11(廃止可能性あり) (gcc 13.3.0 + boost 1.89.0) |
| 結果 |
AC
|
| 実行時間 | 714 ms / 5,000 ms |
| コード長 | 3,147 bytes |
| 記録 | |
| コンパイル時間 | 1,950 ms |
| コンパイル使用メモリ | 177,004 KB |
| 実行使用メモリ | 9,984 KB |
| 最終ジャッジ日時 | 2025-06-20 10:29:46 |
| 合計ジャッジ時間 | 11,795 ms |
|
ジャッジサーバーID (参考情報) |
judge5 / judge2 |
(要ログイン)
| ファイルパターン | 結果 |
|---|---|
| sample | AC * 1 |
| other | AC * 38 |
コンパイルメッセージ
main.cpp: In function ‘int main()’:
main.cpp:104:14: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
104 | scanf("%d%d",&n,&q);
| ~~~~~^~~~~~~~~~~~~~
main.cpp:106:28: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
106 | ll a; scanf("%lld",&a);
| ~~~~~^~~~~~~~~~~
main.cpp:111:40: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
111 | int ty,L,R; ll x; scanf("%d%d%d",&ty,&L,&R);
| ~~~~~^~~~~~~~~~~~~~~~~~~~
main.cpp:112:34: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
112 | if(ty <= 2) scanf("%lld",&x);
| ~~~~~^~~~~~~~~~~
ソースコード
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
typedef long long ll;
typedef pair<int,int> P;
typedef pair<int,P> P1;
typedef pair<P,P> P2;
#define pu push
#define pb push_back
#define mp make_pair
#define eps 1e-7
#define INF 1500000000
#define mod 998244353
#define fi first
#define sc second
#define rep(i,x) for(int i=0;i<x;i++)
#define repn(i,x) for(int i=1;i<=x;i++)
#define SORT(x) sort(x.begin(),x.end())
#define ERASE(x) x.erase(unique(x.begin(),x.end()),x.end())
#define POSL(x,v) (lower_bound(x.begin(),x.end(),v)-x.begin())
#define POSU(x,v) (upper_bound(x.begin(),x.end(),v)-x.begin())
ll gcdd(ll a,ll b){
return __gcd(a,b);
}
ll makeL(ll a,ll b){
if(a == 0) return b;
if(b == 0) return a;
if(a >= INF || b >= INF) return INF;
return min((ll)(INF),a*b/gcdd(a,b));
}
ll L[1<<18],mx[1<<18],sum[1<<18];
ll upd[1<<18];
void push(int k,ll val){
L[k*2+1] = L[k*2+2] = mx[k*2+1] = mx[k*2+2] = upd[k*2+1] = upd[k*2+2] = upd[k];
sum[k*2+1] = sum[k*2+2] = val * upd[k];
upd[k] = 0;
}
void update(int x,ll v){
x += (1<<17)-1;
L[x] = sum[x] = mx[x] = v;
while(x){
x = (x-1)/2;
L[x] = makeL(L[x*2+1],L[x*2+2]);
sum[x] = sum[x*2+1]+sum[x*2+2];
mx[x] = max(mx[x*2+1],mx[x*2+2]);
}
}
void set_val(int a,int b,int k,int l,int r,ll x){
if(r<a || b<l) return;
if(a<=l && r<=b){
L[k] = x;
sum[k] = x * (r-l+1);
mx[k] = x;
upd[k] = x;
return;
}
if(upd[k]) push(k,(r-l+1)/2);
set_val(a,b,k*2+1,l,(l+r)/2,x);
set_val(a,b,k*2+2,(l+r)/2+1,r,x);
L[k] = makeL(L[k*2+1],L[k*2+2]);
sum[k] = sum[k*2+1]+sum[k*2+2];
mx[k] = max(mx[k*2+1],mx[k*2+2]);
}
void gcd_val(int a,int b,int k,int l,int r,ll x){
if(r<a || b<l || (L[k]<=x && x%L[k]==0)) return;
if(a<=l && r<=b && L[k]*(r-l+1) == sum[k]){
L[k] = gcdd(x,L[k]);
sum[k] = L[k] * (r-l+1);
upd[k] = L[k];
mx[k] = L[k];
return;
}
if(upd[k]) push(k,(r-l+1)/2);
gcd_val(a,b,k*2+1,l,(l+r)/2,x);
gcd_val(a,b,k*2+2,(l+r)/2+1,r,x);
//assume time complexity is log^2
if(a<=l && r<=b) {
if(L[k] < INF) L[k] = gcdd(L[k],x);
else L[k] = makeL(L[k*2+1],L[k*2+2]);
}
else L[k] = makeL(L[k*2+1],L[k*2+2]);
sum[k] = sum[k*2+1]+sum[k*2+2];
mx[k] = max(mx[k*2+1],mx[k*2+2]);
}
ll calc_max(int a,int b,int k,int l,int r){
if(r<a || b<l) return 0;
if(a<=l && r<=b){
return mx[k];
}
if(upd[k]) push(k,(r-l+1)/2);
return max(calc_max(a,b,k*2+1,l,(l+r)/2),calc_max(a,b,k*2+2,(l+r)/2+1,r));
}
ll calc_sum(int a,int b,int k,int l,int r){
if(r<a || b<l) return 0;
if(a<=l && r<=b){
return sum[k];
}
if(upd[k]) push(k,(r-l+1)/2);
return (calc_sum(a,b,k*2+1,l,(l+r)/2)+calc_sum(a,b,k*2+2,(l+r)/2+1,r));
}
int main(){
int n,q;
scanf("%d%d",&n,&q);
repn(i,n){
ll a; scanf("%lld",&a);
update(i,a);
}
rep(i,q){
int ty,L,R; ll x; scanf("%d%d%d",&ty,&L,&R);
if(ty <= 2) scanf("%lld",&x);
if(ty == 1){
set_val(L,R,0,0,(1<<17)-1,x);
}
else if(ty == 2){
gcd_val(L,R,0,0,(1<<17)-1,x);
}
else if(ty == 3){
printf("%lld\n",calc_max(L,R,0,0,(1<<17)-1));
}
else{
printf("%lld\n",calc_sum(L,R,0,0,(1<<17)-1));
}
}
return 0;
}
HIR180