結果

問題 No.885 アマリクエリ
コンテスト
ユーザー dn6049949
提出日時 2019-09-14 00:05:14
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 982 ms / 2,000 ms
コード長 3,129 bytes
コンパイル時間 169 ms
コンパイル使用メモリ 82,432 KB
実行使用メモリ 98,816 KB
最終ジャッジ日時 2024-07-04 10:40:45
合計ジャッジ時間 6,540 ms
ジャッジサーバーID
（参考情報） 		judge1 / judge5
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 19
権限があれば一括ダウンロードができます

ソースコード

diff #
raw source code 

#!usr/bin/env python3
from collections import defaultdict,deque
from heapq import heappush, heappop
import sys
import math
import bisect
import random
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def I(): return int(sys.stdin.readline())
def LS():return [list(x) for x in sys.stdin.readline().split()]
def S():
    res = list(sys.stdin.readline())
    if res[-1] == "\n":
        return res[:-1]
    return res
def IR(n):
    return [I() for i in range(n)]
def LIR(n):
    return [LI() for i in range(n)]
def SR(n):
    return [S() for i in range(n)]
def LSR(n):
    return [LS() for i in range(n)]

sys.setrecursionlimit(1000000)
mod = 1000000007

#A
def A():
    a,b = LI()
    for i in range(1,101):
        if a%i == 0 and i%b == 0:
            print("YES")
            return
    print("NO")
    return

#B
def B():
    n,k = LI()
    if n >= k**2:
        h = math.ceil(n/k)
        s = []
        l = 0
        for i in range(n//k):
            s.append(["#" if l <= i < l+k or (i < (l+k)%h and l+k >= h) else "." for i in range(h)])
            l += 1
        l %= h
        su = n%k
        if su:
            s.append(["#" if l <= i < l+su else "." for i in range(h)])
        print(h)
        for i in s:
            print(*i,sep="")
    else:
        p = n//(k**2)
        n_ = n-p*k**2
        for k_ in range(100000):
            if k_**2 >= n_:break
        h = p*k+k_
        s = []
        l = 0
        r = k
        for i in range(p):
            for j in range(k):
                s.append(["#" if l <= i < r else "." for i in range(h)])
            l,r = r,r+k
        for j in range(k_):
            s.append(["#" if l <= i < r else "." for i in range(h)])
        su = p*k**2+k_**2
        for i in range(p*k,h)[::-1]:
            if su == n:
                break
            s[-1][i] = "."
            su -= 1
        for i in range(p*k,h-1)[::-1]:
            if su == n:
                break
            s[i][-1] = "."
            su -= 1
        print(h)
        for i in s:
            print(*i,sep = "")
    return

#C
def C():
    s = list(map(int, input()))
    s = s[::-1]
    s.append(0)
    n = len(s)
    dp = [[float("inf")]*2 for i in range(n+1)]
    dp[0][0] = 0
    for i in range(n):
        if s[i] == 0:
            dp[i+1][0] = min(dp[i+1][0],dp[i][0])
            dp[i+1][0] = min(dp[i+1][0],dp[i][1]+1)
            dp[i+1][1] = min(dp[i+1][1],dp[i][1]+1)
        else:
            dp[i+1][0] = min(dp[i+1][0],dp[i][0]+1)
            dp[i+1][1] = min(dp[i+1][1],dp[i][0]+1)
            dp[i+1][1] = min(dp[i+1][1],dp[i][1])
    print(min(dp[n]))
    return

#D
def D():
    n = I()
    a = LI()
    q = []
    for i in a:
        heappush(q,-i)
    Q = I()
    x = LI()
    ans = sum(a)
    for i in range(Q):
        xi = x[i]
        while 1:
            y = heappop(q)
            y *= -1
            if y < xi:
                heappush(q,-y)
                break
            ans -= y-y%xi
            y %= xi
            heappush(q,-y)
        print(ans)
    return

#E
def E():

    return

#F
def F():

    return

#Solve
if __name__ == "__main__":
    D()
0