結果
| 問題 |
No.158 奇妙なお使い
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2019-09-21 22:42:42 |
| 言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 42 ms / 5,000 ms |
| コード長 | 3,782 bytes |
| コンパイル時間 | 1,308 ms |
| コンパイル使用メモリ | 167,536 KB |
| 実行使用メモリ | 47,616 KB |
| 最終ジャッジ日時 | 2024-09-19 03:10:30 |
| 合計ジャッジ時間 | 3,271 ms |
|
ジャッジサーバーID (参考情報) |
judge3 / judge2 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 4 |
| other | AC * 27 |
ソースコード
// includes
#include <bits/stdc++.h>
using namespace std;
// macros
#define pb emplace_back
#define mk make_pair
#define FOR(i, a, b) for(int i=(a);i<(b);++i)
#define rep(i, n) FOR(i, 0, n)
#define rrep(i, n) for(int i=((int)(n)-1);i>=0;i--)
#define irep(itr, st) for(auto itr = (st).begin(); itr != (st).end(); ++itr)
#define irrep(itr, st) for(auto itr = (st).rbegin(); itr != (st).rend(); ++itr)
#define all(x) (x).begin(),(x).end()
#define sz(x) ((int)(x).size())
#define UNIQUE(v) v.erase(unique(v.begin(), v.end()), v.end())
#define bit(n) (1LL<<(n))
// functions
template <class T>bool chmax(T &a, const T &b){if(a < b){a = b; return 1;} return 0;}
template <class T>bool chmin(T &a, const T &b){if(a > b){a = b; return 1;} return 0;}
template <typename T> istream &operator>>(istream &is, vector<T> &vec){for(auto &v: vec)is >> v; return is;}
template <typename T> ostream &operator<<(ostream &os, const vector<T>& vec){for(int i = 0; i < vec.size(); i++){ os << vec[i]; if(i + 1 != vec.size())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const unordered_set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const unordered_multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &p){os << p.first << " " << p.second; return os;}
template <typename T1, typename T2> ostream &operator<<(ostream &os, const map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end(); ++itr){ os << itr->first << ":" << itr->second; auto titr = itr; if(++titr != mp.end())os << " "; } return os;}
template <typename T1, typename T2> ostream &operator<<(ostream &os, const unordered_map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end(); ++itr){ os << itr->first << ":" << itr->second; auto titr = itr; if(++titr != mp.end())os << " "; } return os;}
// types
using ll = long long int;
using P = pair<int, int>;
// constants
const int inf = 1e9;
const ll linf = 1LL << 50;
const double EPS = 1e-10;
const int mod = 1000000007;
const int dx[4] = {-1, 0, 1, 0};
const int dy[4] = {0, -1, 0, 1};
// io
struct fast_io{
fast_io(){ios_base::sync_with_stdio(false); cin.tie(0); cout << fixed << setprecision(20);}
} fast_io_;
int a[3], b[3], c[3], db, dc;
int memo[11][110][10010];
int calc(int a0, int a1, int a2){
if(memo[a0][a1][a2] >= 0)return memo[a0][a1][a2];
int res = 0;
int tdb = db;
int b0 = min(tdb / 1000, a0); tdb -= b0 * 1000;
int b1 = min(tdb / 100, a1); tdb -= b1 * 100;
int b2 = tdb;
if(b2 <= a2){
res = max(res, 1 + calc(a0 - b0 + b[0], a1 - b1 + b[1], a2 - b2 + b[2]));
}
tdb = dc;
b0 = min(tdb / 1000, a0); tdb -= b0 * 1000;
b1 = min(tdb / 100, a1); tdb -= b1 * 100;
b2 = tdb;
if(b2 <= a2){
res = max(res, 1 + calc(a0 - b0 + c[0], a1 - b1 + c[1], a2 - b2 + c[2]));
}
return memo[a0][a1][a2] = res;
}
int main(int argc, char const* argv[])
{
rep(i, 3)cin >> a[i];
cin >> db;
rep(i, 3)cin >> b[i];
cin >> dc;
rep(i, 3)cin >> c[i];
rep(i, 11){
rep(j, 101){
rep(k, 10001)memo[i][j][k] = -1;
}
}
cout << calc(a[0], a[1], a[2]) << endl;
return 0;
}