結果

問題 No.189 SUPER HAPPY DAY
ユーザー fumiphys
提出日時 2019-09-27 19:00:11
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 25 ms / 5,000 ms
コード長 3,688 bytes
コンパイル時間 1,629 ms
コンパイル使用メモリ 169,028 KB
実行使用メモリ 10,240 KB
最終ジャッジ日時 2024-09-24 20:16:20
合計ジャッジ時間 2,825 ms
ジャッジサーバーID
（参考情報） 		judge2 / judge4
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 23
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

// includes
#include <bits/stdc++.h>
using namespace std;
// macros
#define pb emplace_back
#define mk make_pair
#define FOR(i, a, b) for(int i=(a);i<(b);++i)
#define rep(i, n) FOR(i, 0, n)
#define rrep(i, n) for(int i=((int)(n)-1);i>=0;i--)
#define irep(itr, st) for(auto itr = (st).begin(); itr != (st).end(); ++itr)
#define irrep(itr, st) for(auto itr = (st).rbegin(); itr != (st).rend(); ++itr)
#define all(x) (x).begin(),(x).end()
#define sz(x) ((int)(x).size())
#define UNIQUE(v) v.erase(unique(v.begin(), v.end()), v.end())
#define bit(n) (1LL<<(n))
// functions
template <class T>bool chmax(T &a, const T &b){if(a < b){a = b; return 1;} return 0;}
template <class T>bool chmin(T &a, const T &b){if(a > b){a = b; return 1;} return 0;}
template <typename T> istream &operator>>(istream &is, vector<T> &vec){for(auto &v: vec)is >> v; return is;}
template <typename T> ostream &operator<<(ostream &os, const vector<T>& vec){for(int i = 0; i < vec.size(); i++){ os << vec[i]; if(i + 1 != vec.size
    ())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = 
    itr; if(++titr != st.end())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const unordered_set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; 
    auto titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto 
    titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const unordered_multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr
    ; auto titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &p){os << p.first << " " << p.second; return os;}
template <typename T1, typename T2> ostream &operator<<(ostream &os, const map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end(); ++itr){ os << 
    itr->first << ":" << itr->second; auto titr = itr; if(++titr != mp.end())os << " "; } return os;}
template <typename T1, typename T2> ostream &operator<<(ostream &os, const unordered_map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end(); 
    ++itr){ os << itr->first << ":" << itr->second; auto titr = itr; if(++titr != mp.end())os << " "; } return os;}
//  types
using ll = long long int;
using P = pair<int, int>;
// constants
const int inf = 1e9;
const ll linf = 1LL << 50;
const double EPS = 1e-10;
const int mod = 1000000009;
const int dx[4] = {-1, 0, 1, 0};
const int dy[4] = {0, -1, 0, 1};
// io
struct fast_io{
  fast_io(){ios_base::sync_with_stdio(false); cin.tie(0); cout << fixed << setprecision(20);}
} fast_io_;
ll dpm[210][2200], dpd[210][2200];
int main(int argc, char const* argv[])
{
  string m, d;
  cin >> m >> d;
  int curr = 0;
  rep(i, sz(m)){
    rep(j, 2100){
      rep(k, 10){
        (dpm[i+1][j+k] += dpm[i][j]) %= mod;
      }
    }
    for(int k = 0; k < int(m[i] - '0'); k++){
      (dpm[i+1][curr + k] += 1) %= mod;
    }
    curr += int(m[i] - '0');
  }
  (dpm[sz(m)][curr] += 1) %= mod;
  curr = 0;
  rep(i, sz(d)){
    rep(j, 2100){
      rep(k, 10){
        (dpd[i+1][j+k] += dpd[i][j]) %= mod;
      }
    }
    for(int k = 0; k < int(d[i] - '0'); k++){
      (dpd[i+1][curr + k] += 1) %= mod;
    }
    curr += int(d[i] - '0');
  }
  (dpd[sz(d)][curr] += 1) %= mod;
  ll res = 0;
  FOR(j, 1, 2100){
    res = (res + dpm[sz(m)][j] * dpd[sz(d)][j] % mod) % mod;
  }
  cout << res << endl;
  return 0;
}
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