結果
問題 | No.599 回文かい |
ユーザー |
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提出日時 | 2019-09-28 17:43:03 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 101 ms / 4,000 ms |
コード長 | 4,069 bytes |
コンパイル時間 | 1,184 ms |
コンパイル使用メモリ | 102,904 KB |
実行使用メモリ | 5,248 KB |
最終ジャッジ日時 | 2024-10-02 13:25:44 |
合計ジャッジ時間 | 2,560 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge1 |
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ファイルパターン | 結果 |
---|---|
other | AC * 22 |
ソースコード
#include <cassert>#include <cstdio>#include <cmath>#include <iostream>#include <iomanip>#include <sstream>#include <vector>#include <set>#include <map>#include <queue>#include <numeric>#include <algorithm>using namespace std;using lint = long long;constexpr int MOD = 1000000007, INF = 1010101010;constexpr lint LINF = 1LL << 60;template <class T>ostream &operator<<(ostream &os, const vector<T> &vec) {for (const auto &e : vec) os << e << (&e == &vec.back() ? "" : " ");return os;}#ifdef _DEBUGtemplate <class T>void dump(const char* str, T &&h) { cerr << str << " = " << h << "\n"; };template <class Head, class... Tail>void dump(const char* str, Head &&h, Tail &&... t) {while (*str != ',') cerr << *str++; cerr << " = " << h << "\n";dump(str + (*(str + 1) == ' ' ? 2 : 1), t...);}#define DMP(...) dump(#__VA_ARGS__, __VA_ARGS__)#else#define DMP(...) ((void)0)#endiftemplate<int Modulo> struct Mint {lint val;constexpr Mint(lint v = 0) noexcept : val(v % Modulo) { if (val < 0) v += Modulo; }constexpr Mint& operator += (const Mint &r) noexcept {val += r.val;if (val >= Modulo) val -= Modulo;return *this;}constexpr Mint& operator -= (const Mint &r) noexcept {val -= r.val;if (val < 0) val += Modulo;return *this;}constexpr Mint& operator *= (const Mint &r) noexcept {val = val * r.val % Modulo;return *this;}constexpr Mint& operator /= (const Mint &r) noexcept {lint a = r.val, b = Modulo, u = 1, v = 0;while (b) {lint t = a / b;a -= t * b; swap(a, b);u -= t * v; swap(u, v);}val = val * u % Modulo;if (val < 0) val += Modulo;return *this;}constexpr Mint operator + (const Mint &r) const noexcept { return Mint(*this) += r; }constexpr Mint operator - (const Mint &r) const noexcept { return Mint(*this) -= r; }constexpr Mint operator * (const Mint &r) const noexcept { return Mint(*this) *= r; }constexpr Mint operator / (const Mint &r) const noexcept { return Mint(*this) /= r; }constexpr int getmod() { return Modulo; }constexpr Mint operator - () const noexcept { return val ? Modulo - val : 0; }constexpr bool operator == (const Mint &r) const noexcept { return val == r.val; }constexpr bool operator != (const Mint &r) const noexcept { return val != r.val; }friend ostream &operator << (ostream &os, const Mint<Modulo> &x) noexcept { return os << x.val; }friend istream &operator >> (istream &is, Mint<Modulo> &x) noexcept {lint tmp; is >> tmp;x = Mint<Modulo>(tmp);return is;}friend constexpr Mint<Modulo> modpow(const Mint<Modulo> &a, lint n) noexcept {Mint res(1), tmp = a;while (n > 0) {if (n & 1) res *= tmp;tmp *= tmp;n >>= 1;}return res;}};//// mod, base from https://gist.github.com/privet-kitty/295ac9202b7abb3039b493f8238bf40fclass RollingHash {private:using Mint1 = Mint<2147483647>;using Mint2 = Mint<2147483629>;vector<Mint1> hash1, pow1;vector<Mint2> hash2, pow2;const int base1 = 2147483634;const int base2 = 2147483627;int sz;public:RollingHash() {}RollingHash(const string &s) :sz(s.size()) {hash1.assign(sz + 1, 0); pow1.assign(sz + 1, 1);hash2.assign(sz + 1, 0); pow2.assign(sz + 1, 1);for (int i = 0; i < sz; i++) {hash1[i + 1] = hash1[i] * base1 + s[i];pow1[i + 1] = pow1[i] * base1;hash2[i + 1] = hash2[i] * base2 + s[i];pow2[i + 1] = pow2[i] * base2;}}pair<int, int> get(int l, int r) {int res1 = (hash1[r] - hash1[l] * pow1[r - l]).val;int res2 = (hash2[r] - hash2[l] * pow2[r - l]).val;return { res1, res2 };}};int main() {cin.tie(nullptr);ios::sync_with_stdio(false);string S;cin >> S;int sz = S.size();RollingHash rh(S);using mint = Mint<MOD>;vector<mint> dp(sz / 2 + 1, 0);dp[0] = 1;for (int i = 1; i <= sz / 2; i++) {for (int j = 1; j <= i; j++) {if (rh.get(i - j, i) == rh.get(sz - i, sz - (i - j))) {dp[i] += dp[i - j];}}}mint ans = 0;for (int i = 0; i < sz / 2 + 1; i++) ans += dp[i];cout << ans << "\n";return 0;}