結果

問題 No.599 回文かい
ユーザー unagiunag
提出日時 2019-09-28 17:43:03
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 101 ms / 4,000 ms
コード長 4,069 bytes
コンパイル時間 1,184 ms
コンパイル使用メモリ 102,904 KB
実行使用メモリ 5,248 KB
最終ジャッジ日時 2024-10-02 13:25:44
合計ジャッジ時間 2,560 ms
ジャッジサーバーID
(参考情報)
judge5 / judge1
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ファイルパターン 結果
other AC * 22
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ソースコード

diff #
プレゼンテーションモードにする

#include <cassert>
#include <cstdio>
#include <cmath>
#include <iostream>
#include <iomanip>
#include <sstream>
#include <vector>
#include <set>
#include <map>
#include <queue>
#include <numeric>
#include <algorithm>
using namespace std;
using lint = long long;
constexpr int MOD = 1000000007, INF = 1010101010;
constexpr lint LINF = 1LL << 60;
template <class T>
ostream &operator<<(ostream &os, const vector<T> &vec) {
for (const auto &e : vec) os << e << (&e == &vec.back() ? "" : " ");
return os;
}
#ifdef _DEBUG
template <class T>
void dump(const char* str, T &&h) { cerr << str << " = " << h << "\n"; };
template <class Head, class... Tail>
void dump(const char* str, Head &&h, Tail &&... t) {
while (*str != ',') cerr << *str++; cerr << " = " << h << "\n";
dump(str + (*(str + 1) == ' ' ? 2 : 1), t...);
}
#define DMP(...) dump(#__VA_ARGS__, __VA_ARGS__)
#else
#define DMP(...) ((void)0)
#endif
template<int Modulo> struct Mint {
lint val;
constexpr Mint(lint v = 0) noexcept : val(v % Modulo) { if (val < 0) v += Modulo; }
constexpr Mint& operator += (const Mint &r) noexcept {
val += r.val;
if (val >= Modulo) val -= Modulo;
return *this;
}
constexpr Mint& operator -= (const Mint &r) noexcept {
val -= r.val;
if (val < 0) val += Modulo;
return *this;
}
constexpr Mint& operator *= (const Mint &r) noexcept {
val = val * r.val % Modulo;
return *this;
}
constexpr Mint& operator /= (const Mint &r) noexcept {
lint a = r.val, b = Modulo, u = 1, v = 0;
while (b) {
lint t = a / b;
a -= t * b; swap(a, b);
u -= t * v; swap(u, v);
}
val = val * u % Modulo;
if (val < 0) val += Modulo;
return *this;
}
constexpr Mint operator + (const Mint &r) const noexcept { return Mint(*this) += r; }
constexpr Mint operator - (const Mint &r) const noexcept { return Mint(*this) -= r; }
constexpr Mint operator * (const Mint &r) const noexcept { return Mint(*this) *= r; }
constexpr Mint operator / (const Mint &r) const noexcept { return Mint(*this) /= r; }
constexpr int getmod() { return Modulo; }
constexpr Mint operator - () const noexcept { return val ? Modulo - val : 0; }
constexpr bool operator == (const Mint &r) const noexcept { return val == r.val; }
constexpr bool operator != (const Mint &r) const noexcept { return val != r.val; }
friend ostream &operator << (ostream &os, const Mint<Modulo> &x) noexcept { return os << x.val; }
friend istream &operator >> (istream &is, Mint<Modulo> &x) noexcept {
lint tmp; is >> tmp;
x = Mint<Modulo>(tmp);
return is;
}
friend constexpr Mint<Modulo> modpow(const Mint<Modulo> &a, lint n) noexcept {
Mint res(1), tmp = a;
while (n > 0) {
if (n & 1) res *= tmp;
tmp *= tmp;
n >>= 1;
}
return res;
}
};
//// mod, base from https://gist.github.com/privet-kitty/295ac9202b7abb3039b493f8238bf40f
class RollingHash {
private:
using Mint1 = Mint<2147483647>;
using Mint2 = Mint<2147483629>;
vector<Mint1> hash1, pow1;
vector<Mint2> hash2, pow2;
const int base1 = 2147483634;
const int base2 = 2147483627;
int sz;
public:
RollingHash() {}
RollingHash(const string &s) :sz(s.size()) {
hash1.assign(sz + 1, 0); pow1.assign(sz + 1, 1);
hash2.assign(sz + 1, 0); pow2.assign(sz + 1, 1);
for (int i = 0; i < sz; i++) {
hash1[i + 1] = hash1[i] * base1 + s[i];
pow1[i + 1] = pow1[i] * base1;
hash2[i + 1] = hash2[i] * base2 + s[i];
pow2[i + 1] = pow2[i] * base2;
}
}
pair<int, int> get(int l, int r) {
int res1 = (hash1[r] - hash1[l] * pow1[r - l]).val;
int res2 = (hash2[r] - hash2[l] * pow2[r - l]).val;
return { res1, res2 };
}
};
int main() {
cin.tie(nullptr);
ios::sync_with_stdio(false);
string S;
cin >> S;
int sz = S.size();
RollingHash rh(S);
using mint = Mint<MOD>;
vector<mint> dp(sz / 2 + 1, 0);
dp[0] = 1;
for (int i = 1; i <= sz / 2; i++) {
for (int j = 1; j <= i; j++) {
if (rh.get(i - j, i) == rh.get(sz - i, sz - (i - j))) {
dp[i] += dp[i - j];
}
}
}
mint ans = 0;
for (int i = 0; i < sz / 2 + 1; i++) ans += dp[i];
cout << ans << "\n";
return 0;
}
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