結果

問題 No.90 品物の並び替え
ユーザー wdkkou
提出日時 2019-10-07 15:52:25
言語 Java
(openjdk 23)
結果
AC  
実行時間 171 ms / 5,000 ms
コード長 4,736 bytes
コンパイル時間 2,062 ms
コンパイル使用メモリ 77,992 KB
実行使用メモリ 40,000 KB
最終ジャッジ日時 2024-10-13 07:49:18
合計ジャッジ時間 3,390 ms
ジャッジサーバーID
(参考情報)
judge3 / judge5
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 1
other AC * 9
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

import java.util.*;
import java.io.*;
public class Main {
public static void main(String[] args) {
FastScanner sc = new FastScanner();
int n = sc.nextInt();
int m = sc.nextInt();
int[][] score = new int[n + 1][n + 1];
for (int i = 0; i < m; i++) {
int a = sc.nextInt();
int b = sc.nextInt();
int c = sc.nextInt();
score[a][b] = c;
}
int[] data = new int[n];
for (int i = 0; i < n; i++) {
data[i] = i;
}
int ans = 0;
do {
int sum = 0;
for (int i = 0; i < n; i++) {
for (int j = i + 1; j < n; j++) {
sum += score[data[i]][data[j]];
}
}
ans = Math.max(ans, sum);
} while (findNextPermutation(data));
System.out.println(ans);
}
public static boolean findNextPermutation(int data[]) {
// If the given dataset is empty
// or contains only one element
// next_permutation is not possible
if (data.length <= 1)
return false;
int last = data.length - 2;
// find the longest non-increasing suffix
// and find the pivot
while (last >= 0) {
if (data[last] < data[last + 1]) {
break;
}
last--;
}
if (last < 0)
return false;
int nextGreater = data.length - 1;
// Find the rightmost successor to the pivot
for (int i = data.length - 1; i > last; i--) {
if (data[i] > data[last]) {
nextGreater = i;
break;
}
}
// Swap the successor and the pivot
data = swap(data, nextGreater, last);
// Reverse the suffix
data = reverse(data, last + 1, data.length - 1);
return true;
}
public static int[] swap(int data[], int left, int right) {
// Swap the data
int temp = data[left];
data[left] = data[right];
data[right] = temp;
// Return the updated array
return data;
}
public static int[] reverse(int data[], int left, int right) {
// Reverse the sub-array
while (left < right) {
int temp = data[left];
data[left++] = data[right];
data[right--] = temp;
}
// Return the updated array
return data;
}
}
class FastScanner {
private final InputStream in = System.in;
private final byte[] buffer = new byte[1024];
private int ptr = 0;
private int buflen = 0;
private boolean hasNextByte() {
if (ptr < buflen) {
return true;
} else {
ptr = 0;
try {
buflen = in.read(buffer);
} catch (IOException e) {
e.printStackTrace();
}
if (buflen <= 0) {
return false;
}
}
return true;
}
private int readByte() {
if (hasNextByte())
return buffer[ptr++];
else
return -1;
}
private static boolean isPrintableChar(int c) {
return 33 <= c && c <= 126;
}
public boolean hasNext() {
while (hasNextByte() && !isPrintableChar(buffer[ptr]))
ptr++;
return hasNextByte();
}
public String next() {
if (!hasNext())
throw new NoSuchElementException();
StringBuilder sb = new StringBuilder();
int b = readByte();
while (isPrintableChar(b)) {
sb.appendCodePoint(b);
b = readByte();
}
return sb.toString();
}
public long nextLong() {
if (!hasNext())
throw new NoSuchElementException();
long n = 0;
boolean minus = false;
int b = readByte();
if (b == '-') {
minus = true;
b = readByte();
}
if (b < '0' || '9' < b) {
throw new NumberFormatException();
}
while (true) {
if ('0' <= b && b <= '9') {
n *= 10;
n += b - '0';
} else if (b == -1 || !isPrintableChar(b)) {
return minus ? -n : n;
} else {
throw new NumberFormatException();
}
b = readByte();
}
}
public int nextInt() {
long nl = nextLong();
if (nl < Integer.MIN_VALUE || nl > Integer.MAX_VALUE)
throw new NumberFormatException();
return (int) nl;
}
public double nextDouble() {
return Double.parseDouble(next());
}
}
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