結果
問題 | No.90 品物の並び替え |
ユーザー |
|
提出日時 | 2019-10-07 15:52:25 |
言語 | Java (openjdk 23) |
結果 |
AC
|
実行時間 | 171 ms / 5,000 ms |
コード長 | 4,736 bytes |
コンパイル時間 | 2,062 ms |
コンパイル使用メモリ | 77,992 KB |
実行使用メモリ | 40,000 KB |
最終ジャッジ日時 | 2024-10-13 07:49:18 |
合計ジャッジ時間 | 3,390 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge5 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 1 |
other | AC * 9 |
ソースコード
import java.util.*;import java.io.*;public class Main {public static void main(String[] args) {FastScanner sc = new FastScanner();int n = sc.nextInt();int m = sc.nextInt();int[][] score = new int[n + 1][n + 1];for (int i = 0; i < m; i++) {int a = sc.nextInt();int b = sc.nextInt();int c = sc.nextInt();score[a][b] = c;}int[] data = new int[n];for (int i = 0; i < n; i++) {data[i] = i;}int ans = 0;do {int sum = 0;for (int i = 0; i < n; i++) {for (int j = i + 1; j < n; j++) {sum += score[data[i]][data[j]];}}ans = Math.max(ans, sum);} while (findNextPermutation(data));System.out.println(ans);}public static boolean findNextPermutation(int data[]) {// If the given dataset is empty// or contains only one element// next_permutation is not possibleif (data.length <= 1)return false;int last = data.length - 2;// find the longest non-increasing suffix// and find the pivotwhile (last >= 0) {if (data[last] < data[last + 1]) {break;}last--;}if (last < 0)return false;int nextGreater = data.length - 1;// Find the rightmost successor to the pivotfor (int i = data.length - 1; i > last; i--) {if (data[i] > data[last]) {nextGreater = i;break;}}// Swap the successor and the pivotdata = swap(data, nextGreater, last);// Reverse the suffixdata = reverse(data, last + 1, data.length - 1);return true;}public static int[] swap(int data[], int left, int right) {// Swap the dataint temp = data[left];data[left] = data[right];data[right] = temp;// Return the updated arrayreturn data;}public static int[] reverse(int data[], int left, int right) {// Reverse the sub-arraywhile (left < right) {int temp = data[left];data[left++] = data[right];data[right--] = temp;}// Return the updated arrayreturn data;}}class FastScanner {private final InputStream in = System.in;private final byte[] buffer = new byte[1024];private int ptr = 0;private int buflen = 0;private boolean hasNextByte() {if (ptr < buflen) {return true;} else {ptr = 0;try {buflen = in.read(buffer);} catch (IOException e) {e.printStackTrace();}if (buflen <= 0) {return false;}}return true;}private int readByte() {if (hasNextByte())return buffer[ptr++];elsereturn -1;}private static boolean isPrintableChar(int c) {return 33 <= c && c <= 126;}public boolean hasNext() {while (hasNextByte() && !isPrintableChar(buffer[ptr]))ptr++;return hasNextByte();}public String next() {if (!hasNext())throw new NoSuchElementException();StringBuilder sb = new StringBuilder();int b = readByte();while (isPrintableChar(b)) {sb.appendCodePoint(b);b = readByte();}return sb.toString();}public long nextLong() {if (!hasNext())throw new NoSuchElementException();long n = 0;boolean minus = false;int b = readByte();if (b == '-') {minus = true;b = readByte();}if (b < '0' || '9' < b) {throw new NumberFormatException();}while (true) {if ('0' <= b && b <= '9') {n *= 10;n += b - '0';} else if (b == -1 || !isPrintableChar(b)) {return minus ? -n : n;} else {throw new NumberFormatException();}b = readByte();}}public int nextInt() {long nl = nextLong();if (nl < Integer.MIN_VALUE || nl > Integer.MAX_VALUE)throw new NumberFormatException();return (int) nl;}public double nextDouble() {return Double.parseDouble(next());}}