結果
問題 | No.250 atetubouのzetubou |
ユーザー |
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提出日時 | 2015-07-24 23:30:23 |
言語 | C++11 (gcc 13.3.0) |
結果 |
AC
|
実行時間 | 241 ms / 5,000 ms |
コード長 | 1,880 bytes |
コンパイル時間 | 1,218 ms |
コンパイル使用メモリ | 160,360 KB |
実行使用メモリ | 189,056 KB |
最終ジャッジ日時 | 2024-07-08 14:15:17 |
合計ジャッジ時間 | 7,322 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge1 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 2 |
other | AC * 20 |
ソースコード
#include <bits/stdc++.h>using namespace std;long long gcd(long long a,long long b){return b ? gcd(b,a%b) : a;}long long lcm(long long a,long long b){return a / gcd(a,b) * b;}long long mul(long long a,long long b,const long long mod){return b?(mul(a*2,b/2,mod)+(b&1?a:0))%mod:0;}long long bpow(long long a,long long b,const long long mod){return (b?bpow(a*a%mod,b/2,mod)*(b&1?a:1):1)%mod;}long long inv(long long a,const long long mod){return bpow(a,mod-2,mod);}// to overflow/*long long bpow(long long a,long long b,const long long mod){return (b?mul(bpow(mul(a,a,mod),b/2,mod),(b&1?a:1),mod):1)%mod;}*/class mInt{public:static const long long mod = 1000000007;long long v;mInt():v(0){}mInt(long long v):v((v%mod+mod)%mod){}};mInt& operator += (mInt &a,mInt b){ return a = a.v + b.v; }mInt& operator -= (mInt &a,mInt b){ return a = a.v - b.v; }mInt& operator *= (mInt &a,mInt b){ return a = a.v * b.v; }mInt& operator /= (mInt &a,mInt b){ return a = a.v * inv(b.v,mInt::mod); }mInt operator + (mInt a,mInt b){ return a += b; }mInt operator - (mInt a,mInt b){ return a -= b; }mInt operator * (mInt a,mInt b){ return a *= b; }mInt operator / (mInt a,mInt b){ return a /= b; }ostream& operator<<(ostream& os, const mInt& x){ return os << x.v; }double ncr1[4000][4000];long long ncr2[4000][4000];long long nHr(int n,int r){int a = n + r - 1;int b = r-1;if( ncr1[a][b] > 1e17 ) return 1e17;return ncr2[a][b];}int main(){ncr1[0][0] = ncr2[0][0] = 1;for(int i = 0 ; i < 3200 ; i++)for(int j = 0 ; j < 3200 ; j++)ncr1[i+1][j] += ncr1[i][j],ncr1[i+1][j+1] += ncr1[i][j],ncr2[i+1][j] += ncr2[i][j],ncr2[i+1][j+1] += ncr2[i][j];int Q;cin >> Q;while(Q--){long long D,X,T;cin >> D >> X >> T;X++;D--;if( nHr(D,X) > T ){cout << "ZETUBOU" << endl;}else cout << "AC" << endl;}}