結果

問題 No.705 ゴミ拾い Hard
コンテスト
ユーザー chocorusk
提出日時 2019-10-19 11:03:51
言語 C++14
(gcc 15.2.0 + boost 1.89.0)
コンパイル:
g++-15 -O2 -lm -std=c++14 -Wuninitialized -DONLINE_JUDGE -o a.out _filename_
実行:
./a.out
結果
AC  
実行時間 169 ms / 1,500 ms
コード長 1,621 bytes
記録
記録タグの例:
初AC ショートコード 純ショートコード 純主流ショートコード 最速実行時間
コンパイル時間 941 ms
コンパイル使用メモリ 140,216 KB
実行使用メモリ 17,664 KB
最終ジャッジ日時 2026-03-13 19:56:12
合計ジャッジ時間 7,012 ms
ジャッジサーバーID
（参考情報） 		judge1_0 / judge2_0
このコードへのチャレンジ
（要ログイン）
ファイルパターン 結果
sample AC * 4
other AC * 40
権限があれば一括ダウンロードができます
コンパイルメッセージ
In file included from /home/linuxbrew/.linuxbrew/Cellar/gcc/15.2.0_1/include/c++/15/bits/stl_algobase.h:64,
                 from /home/linuxbrew/.linuxbrew/Cellar/gcc/15.2.0_1/include/c++/15/string:53,
                 from /home/linuxbrew/.linuxbrew/Cellar/gcc/15.2.0_1/include/c++/15/bits/locale_classes.h:42,
                 from /home/linuxbrew/.linuxbrew/Cellar/gcc/15.2.0_1/include/c++/15/bits/ios_base.h:43,
                 from /home/linuxbrew/.linuxbrew/Cellar/gcc/15.2.0_1/include/c++/15/ios:46,
                 from /home/linuxbrew/.linuxbrew/Cellar/gcc/15.2.0_1/include/c++/15/bits/ostream.h:43,
                 from /home/linuxbrew/.linuxbrew/Cellar/gcc/15.2.0_1/include/c++/15/ostream:42,
                 from /home/linuxbrew/.linuxbrew/Cellar/gcc/15.2.0_1/include/c++/15/iostream:43,
                 from main.cpp:3:
In member function 'std::pair<_T1, _T2>& std::pair<_T1, _T2>::operator=(std::__conditional_t<((bool)std::__and_<std::is_move_assignable<_Tp>, std::is_move_assignable<_T2> >::value), std::pair<_T1, _T2>&&, std::__nonesuch&&>) [with _T1 = int; _T2 = long long int]',
    inlined from 'monotone_minima(int, int, const std::function<long long int(int, int)>&)::<lambda(auto:1, int, int, int, int)> [with auto:1 = monotone_minima(int, int, const std::function<long long int(int, int)>&)::<lambda(auto:1, int, int, int, int)>]' at main.cpp:45:16:
/home/linuxbrew/.linuxbrew/Cellar/gcc/15.2.0_1/include/c++/15/bits/stl_pair.h:957:15: warning: 'k' may be used uninitialized [-Wmaybe-uninitialized]
  957 |         first = std::forward<first_type>(__p.first);
      |         ~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
main.cpp: In lambda function:
main.cpp:37:21: note: 'k' was declared here
   37 |                 int k;
      |                     ^
In member function 'std::pair<_T1, _T2>& std::pair<_T1, _T2>::operator=(std::__conditional_t<((bool)std::__and_<std::is_move_assignable<_Tp>, std::is_move_assignable<_T2> >::value), std::pair<_T1, _T2>&&, std::__non

ソースコード

diff #
raw source code 

#include <cstdio>
#include <cstring>
#include <iostream>
#include <string>
#include <cmath>
#include <bitset>
#include <vector>
#include <map>
#include <set>
#include <queue>
#include <deque>
#include <algorithm>
#include <complex>
#include <unordered_map>
#include <unordered_set>
#include <random>
#include <cassert>
#include <fstream>
#include <utility>
#include <functional>
#include <time.h>
#include <stack>
#define popcount __builtin_popcount
using namespace std;
typedef long long int ll;
typedef pair<int, ll> P;
int n;
ll a[300030], x[300030], y[300030];
ll dp[300030];
vector<P> monotone_minima(int h, int w, const function<ll(int, int)> &f){
	vector<P> dp(h);
	const ll INF=1e18;
	auto solve=[&](auto solve, int d, int u, int l, int r)->void{
		if(d>u) return;
		int m=(d+u)/2;
		ll mn=INF;
		int k;
		for(int i=l; i<=r; i++){
			ll v=f(m, i);
			if(mn>v){
				mn=v;
				k=i;
			}
		}
		dp[m]=P(k, mn);
		solve(solve, d, m-1, l, k);
		solve(solve, m+1, u, k, r);
	};
	solve(solve, 0, h-1, 0, w-1);
	return dp;
}
void solve(int l, int r){
	if(l>r) return;
	int m=(l+r)/2;
	solve(l, m-1);
	vector<P> dp1=monotone_minima(r-m+1, m-l+1, [&](int i, int j){ return dp[j+l-1]+y[j+l]*y[j+l]*y[j+l]+abs(x[j+l]-a[i+m])*abs(x[j+l]-a[i+m])*abs(x[j+l]-a[i+m]);});
	for(int i=m; i<=r; i++) dp[i]=min(dp[i], dp1[i-m].second);
	solve(m+1, r);
}
int main()
{
	scanf("%d", &n);
	const ll INF=1e18;
	fill(dp, dp+n+1, INF);
	dp[0]=0;
	for(int i=1; i<=n; i++) scanf("%lld", &a[i]);
	for(int i=1; i<=n; i++) scanf("%lld", &x[i]);
	for(int i=1; i<=n; i++) scanf("%lld", &y[i]);
	solve(1, n);
	printf("%lld\n", dp[n]);
    return 0;
}
0