結果
問題 | No.41 貯金箱の溜息(EASY) |
ユーザー | firiexp |
提出日時 | 2019-10-22 16:30:20 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
CE
(最新)
AC
(最初)
|
実行時間 | - |
コード長 | 2,633 bytes |
コンパイル時間 | 868 ms |
コンパイル使用メモリ | 87,248 KB |
最終ジャッジ日時 | 2024-11-14 21:47:01 |
合計ジャッジ時間 | 1,429 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge2 |
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コンパイルエラー時のメッセージ・ソースコードは、提出者また管理者しか表示できないようにしております。(リジャッジ後のコンパイルエラーは公開されます)
ただし、clay言語の場合は開発者のデバッグのため、公開されます。
ただし、clay言語の場合は開発者のデバッグのため、公開されます。
コンパイルメッセージ
main.cpp:17:39: error: '::numeric_limits' has not been declared 17 | template<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208; | ^~~~~~~~~~~~~~ main.cpp:17:55: error: expected primary-expression before '>' token 17 | template<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208; | ^ main.cpp:17:61: error: no matching function for call to 'max()' 17 | template<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208; | ~~~~~^~ In file included from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/string:50, from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/bits/locale_classes.h:40, from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/bits/ios_base.h:41, from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/ios:42, from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/ostream:38, from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/iostream:39, from main.cpp:1: /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/bits/stl_algobase.h:254:5: note: candidate: 'template<class _Tp> constexpr const _Tp& std::max(const _Tp&, const _Tp&)' 254 | max(const _Tp& __a, const _Tp& __b) | ^~~ /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/bits/stl_algobase.h:254:5: note: template argument deduction/substitution failed: main.cpp:17:61: note: candidate expects 2 arguments, 0 provided 17 | template<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208; | ~~~~~^~ /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/bits/stl_algobase.h:300:5: note: candidate: 'templat
ソースコード
#include <iostream> #include <algorithm> #include <iomanip> #include <map> #include <set> #include <queue> #include <stack> #include <numeric> #include <bitset> #include <cmath> static const int MOD = 1000000009; using ll = long long; using u32 = uint32_t; using namespace std; template<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208; template<ll M = 1000000007> struct modint{ ll val; modint(): val(0){} template<typename T> explicit modint(T t){val = t%M; if(val < 0) val += M;} modint pow(ll k){ modint res(1), x(val); while(k){ if(k&1) res *= x; x *= x; k >>= 1; } return res; } template<typename T> modint& operator=(T a){ val = a%M; if(val < 0) val += M; return *this; } modint inv() {return pow(M-2);} modint& operator+=(modint a){ val += a.val; if(val >= M) val -= M; return *this;} modint& operator-=(modint a){ val += M-a.val; if(val >= M) val -= M; return *this;} modint& operator*=(modint a){ val = 1LL*val*a.val%M; return *this;} modint& operator/=(modint a){ return (*this) *= a.inv();} modint operator+(modint a) const {return modint(val) +=a;} modint operator-(modint a) const {return modint(val) -=a;} modint operator*(modint a) const {return modint(val) *=a;} modint operator/(modint a) const {return modint(val) /=a;} modint operator-(){ return modint(-val);} bool operator==(const modint a) const {return val == a.val;} bool operator!=(const modint a) const {return val != a.val;} bool operator<(const modint a) const {return val < a.val;} }; using mint = modint<MOD>; template <class T, class U> vector<T> make_v(U size, const T& init){ return vector<T>(static_cast<size_t>(size), init); } template<class... Ts, class U> auto make_v(U size, Ts... rest) { return vector<decltype(make_v(rest...))>(static_cast<size_t>(size), make_v(rest...)); } template<class T> void chmin(T &a, const T &b){ a = (a < b ? a : b); } template<class T> void chmax(T &a, const T &b){ a = (a > b ? a : b); } int main() { int t; cin >> t; auto dp = make_v(2, 90001, mint(0)); dp[0][0] = 1; for (int i = 1; i <= 9; ++i) { int now = i&1, prv = now^1; for (int j = 0; j <= 90000; ++j) { dp[now][j] = dp[prv][j]; if(j >= i) dp[now][j] += dp[now][j-i]; } } int now = 1; for (int i = 0; i < 90000; ++i) { dp[now][i+1] += dp[now][i]; } for (int i = 0; i < t; ++i) { ll x; scanf("%lld", &x); printf("%lld\n", dp[now][x/111111].val); } return 0; }