結果

問題 No.913 木の燃やし方
ユーザー NyaanNyaan
提出日時 2019-10-23 01:28:53
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 322 ms / 3,000 ms
コード長 5,234 bytes
コンパイル時間 2,001 ms
コンパイル使用メモリ 178,484 KB
実行使用メモリ 15,920 KB
最終ジャッジ日時 2024-07-05 06:02:43
合計ジャッジ時間 15,316 ms
ジャッジサーバーID
(参考情報)
judge1 / judge3
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 3
other AC * 34
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
#define whlie while
#define pb push_back
#define eb emplace_back
#define fi first
#define se second
#define rep(i,N) for(int i = 0; i < (N); i++)
#define repr(i,N) for(int i = (N) - 1; i >= 0; i--)
#define rep1(i,N) for(int i = 1; i <= (N) ; i++)
#define repr1(i,N) for(int i = (N) ; i > 0 ; i--)
#define each(x,v) for(auto& x : v)
#define all(v) (v).begin(),(v).end()
#define sz(v) ((int)(v).size())
#define vrep(v,it) for(auto it = v.begin(); it != v.end(); it++)
#define vrepr(v,it) for(auto it = v.rbegin(); it != v.rend(); it++)
#define ini(...) int __VA_ARGS__; in(__VA_ARGS__)
#define inl(...) ll __VA_ARGS__; in(__VA_ARGS__)
#define ins(...) string __VA_ARGS__; in(__VA_ARGS__)
using namespace std; void solve();
using ll = long long; using vl = vector<ll>;
using vi = vector<int>; using vvi = vector< vector<int> >;
constexpr int inf = 1001001001;
constexpr ll infLL = (1LL << 61) - 1;
struct IoSetupNya {IoSetupNya() { cin.tie(nullptr); ios::sync_with_stdio(false); cout << fixed << setprecision(15); cerr << fixed << setprecision(7
    );} } iosetupnya;
template<typename T, typename U> inline bool amin(T &x, U y) { return (y < x) ? (x = y, true) : false; }
template<typename T, typename U> inline bool amax(T &x, U y) { return (x < y) ? (x = y, true) : false; }
template<typename T, typename U> ostream& operator <<(ostream& os, const pair<T, U> &p) { os << p.first << " " << p.second; return os; }
template<typename T, typename U> istream& operator >>(istream& is, pair<T, U> &p) { is >> p.first >> p.second; return is; }
template<typename T> ostream& operator <<(ostream& os, const vector<T> &v) { int s = (int)v.size(); rep(i,s) os << (i ? " " : "") << v[i]; return os;
    }
template<typename T> istream& operator >>(istream& is, vector<T> &v) { for(auto &x : v) is >> x; return is; }
void in(){} template <typename T,class... U> void in(T &t,U &...u){ cin >> t; in(u...);}
void out(){cout << "\n";} template <typename T,class... U> void out(const T &t,const U &...u){ cout << t; if(sizeof...(u)) cout << " "; out(u...);}
template<typename T>void die(T x){out(x); exit(0);}
#ifdef NyaanDebug
#include "NyaanDebug.h"
#define trc(...) do { cerr << #__VA_ARGS__ << " = "; dbg_out(__VA_ARGS__);} while(0)
#define trca(v,N) do { cerr << #v << " = "; array_out(v , N);cout << endl;} while(0)
#else
#define trc(...)
#define trca(...)
int main(){solve();}
#endif
using P = pair<int,int>; using vp = vector<P>;
constexpr int MOD = /** 1000000007; //*/ 998244353;
////////////////
template<typename T>
struct LiChaoTree{
struct Line{
T slope , intercept;
Line(T slope,T intercept) : slope(slope),intercept(intercept){}
inline T get(T x) const{
return slope * x + intercept;
}
inline bool over(const Line& other , const T &x) const{
return get(x) < other.get(x);
}
};
// remind 0-indexed
vector<T> xset;
vector<Line> seg;
int _size;
// xx
LiChaoTree(const vector<T> &x, T INF) : xset(x) {
_size = 1; while(_size < (int)xset.size()) _size <<= 1;
while( (int)xset.size() < _size) xset.push_back(xset.back() + 1);
seg.assign(2 * _size - 1, Line(0, INF));
}
// y = ax + b
void update(T a, T b){
Line x(a , b);
// x.over(xset[right])out of bound
int left = 0 , right = _size , seg_idx = 0;
while(1){
int mid = (left + right) >> 1;
bool l_over = x.over(seg[seg_idx], xset[left]);
bool r_over = x.over(seg[seg_idx], xset[mid]);
if(r_over) swap(seg[seg_idx], x);
if(left + 1 >= right) return;
else if(l_over != r_over) seg_idx = 2 * seg_idx + 1 , right = mid;
else seg_idx = 2 * seg_idx + 2 , left = mid;
}
}
// x = xset[k]
T query(int k) {
const T x = xset[k];
k += _size - 1;
T ret = seg[k].get(x);
while(k > 0) {
k = (k - 1) >> 1;
ret = min(ret, seg[k].get(x) );
}
return ret;
}
};
int N; vl a , s;
vl dp;
void divideconquer(int L,int R){
if(L == R) return;
if(L + 1 == R){ amin(dp[L] , 1 + a[L]); return; }
int M = (L + R) >> 1;
// L <= i < M
{
vl xs(M - L); rep(i , M - L) xs[i] = i + L;
LiChaoTree<ll> lichao(xs , infLL);
for(ll l = M+1; l <= R; l++) lichao.update(l * (-2) , l*l + s[l]);
ll y[M - L];
for(ll k = L; k < M; k++) y[k-L] = lichao.query(k-L) + k*k - s[k];
rep1(i , M - L - 1) amin(y[i] , y[i-1]);
for(ll k = L; k < M; k++) amin(dp[k] , y[k-L]);
}
// M <= i < R
{
vl xs(R - M); rep(i , R - M) xs[i] = i + M + 1;
LiChaoTree<ll> lichao(xs , infLL);
for(ll k = L; k <= M; k++) lichao.update(k * (-2) , k*k - s[k]);
ll y[R - M];
for(ll l = M + 1; l <= R; l++) y[l-M-1] = lichao.query(l-M-1)+l*l+s[l];
repr1(i , R - M - 1) amin(y[i-1] , y[i]);
for(int l = M; l < R; l++) amin(dp[l] , y[l-M]);
}
divideconquer(L , M);
divideconquer(M + 1 , R);
}
void solve(){
in(N);
a.resize(N); in(a);
dp.resize(N , infLL);
s.resize(N + 1 , 0);
rep1(i , N) s[i] = s[i - 1] + a[i - 1];
divideconquer(0 , N);
each(x , dp) out(x);
}
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