結果

問題 No.879 Range Mod 2 Query
ユーザー hitonanodehitonanode
提出日時 2019-10-26 12:05:36
言語 C++14
(gcc 12.3.0 + boost 1.83.0)
結果
WA  
実行時間 -
コード長 7,588 bytes
コンパイル時間 1,906 ms
コンパイル使用メモリ 182,420 KB
実行使用メモリ 13,364 KB
最終ジャッジ日時 2024-09-14 04:58:26
合計ジャッジ時間 6,313 ms
ジャッジサーバーID
(参考情報)
judge2 / judge4
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
5,248 KB
testcase_01 WA -
testcase_02 WA -
testcase_03 WA -
testcase_04 WA -
testcase_05 WA -
testcase_06 WA -
testcase_07 WA -
testcase_08 WA -
testcase_09 WA -
testcase_10 WA -
testcase_11 WA -
testcase_12 WA -
testcase_13 WA -
testcase_14 WA -
testcase_15 WA -
testcase_16 WA -
testcase_17 WA -
testcase_18 WA -
testcase_19 AC 257 ms
13,220 KB
testcase_20 AC 257 ms
13,332 KB
testcase_21 AC 272 ms
13,300 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

#include <bits/stdc++.h>
using namespace std;
using lint = long long int;
using pint = pair<int, int>;
using plint = pair<lint, lint>;
struct fast_ios { fast_ios(){ cin.tie(0); ios::sync_with_stdio(false); cout << fixed << setprecision(20); }; } fast_ios_;
#define ALL(x) (x).begin(), (x).end()
#define SZ(x) ((lint)(x).size())
#define POW2(n) (1LL << (n))
#define FOR(i, begin, end) for(int i=(begin),i##_end_=(end);i<i##_end_;i++)
#define IFOR(i, begin, end) for(int i=(end)-1,i##_begin_=(begin);i>=i##_begin_;i--)
#define REP(i, n) FOR(i,0,n)
#define IREP(i, n) IFOR(i,0,n)
template<typename T> void ndarray(vector<T> &vec, int len) { vec.resize(len); }
template<typename T, typename... Args> void ndarray(vector<T> &vec, int len, Args... args) { vec.resize(len); for (auto &v : vec) ndarray(v, args...); }
template<typename T> bool mmax(T &m, const T q) { if (m < q) {m = q; return true;} else return false; }
template<typename T> bool mmin(T &m, const T q) { if (m > q) {m = q; return true;} else return false; }
template<typename T1, typename T2> pair<T1, T2> operator+(const pair<T1, T2> &l, const pair<T1, T2> &r) { return make_pair(l.first + r.first, l.second + r.second); }
template<typename T1, typename T2> pair<T1, T2> operator-(const pair<T1, T2> &l, const pair<T1, T2> &r) { return make_pair(l.first - r.first, l.second - r.second); }
template<typename T> istream &operator>>(istream &is, vector<T> &vec){ for (auto &v : vec) is >> v; return is; }
///// This part below is only for debug, not used /////
template<typename T> ostream &operator<<(ostream &os, const vector<T> &vec){ os << "["; for (auto v : vec) os << v << ","; os << "]"; return os; }
template<typename T> ostream &operator<<(ostream &os, const deque<T> &vec){ os << "deq["; for (auto v : vec) os << v << ","; os << "]"; return os; }
template<typename T> ostream &operator<<(ostream &os, const set<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; }
template<typename T> ostream &operator<<(ostream &os, const unordered_set<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; }
template<typename T> ostream &operator<<(ostream &os, const multiset<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; }
template<typename T> ostream &operator<<(ostream &os, const unordered_multiset<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; }
template<typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &pa){ os << "(" << pa.first << "," << pa.second << ")"; return os; }
template<typename TK, typename TV> ostream &operator<<(ostream &os, const map<TK, TV> &mp){ os << "{"; for (auto v : mp) os << v.first << "=>" << v.second << ","; os << "}"; return os; }
template<typename TK, typename TV> ostream &operator<<(ostream &os, const unordered_map<TK, TV> &mp){ os << "{"; for (auto v : mp) os << v.first << "=>" << v.second << ","; os << "}"; return os; }
#define dbg(x) cerr << #x << " = " << (x) << " (L" << __LINE__ << ") " << __FILE__ << endl;
///// END /////
/*
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/tag_and_trait.hpp>
using namespace __gnu_pbds; // find_by_order(), order_of_key()
template<typename TK> using pbds_set = tree<TK, null_type, less<TK>, rb_tree_tag, tree_order_statistics_node_update>;
template<typename TK, typename TV> using pbds_map = tree<TK, TV, less<TK>, rb_tree_tag, tree_order_statistics_node_update>;
*/
template <typename VAL, typename DVAL>
struct LazySegTree
{
    int N;
    int head;

    vector<VAL> val;
    vector<DVAL> dval;
    VAL I_val;
    DVAL I_dval;

    using vv2v = function<VAL(const VAL&, const VAL&)>;
    using d2d = function<void(DVAL&, const DVAL&)>;
    using d2v = function<void(VAL&, const DVAL&)>;
    vv2v merge_val;
    d2d add_dval;
    d2v refl_dval;

    LazySegTree(vector<VAL> &val_init, VAL val_default, DVAL dval_default,
                vv2v f, d2d dadd, d2v dreflect)
            : N(val_init.size()), I_val(val_default), I_dval(dval_default),
              merge_val(f),
              add_dval(dadd),
              refl_dval(dreflect)
    {
        int N_tmp = 1;
        while (N_tmp < N) N_tmp <<= 1;
        val = vector<VAL>(N_tmp*2, I_val);
        dval = vector<DVAL>(N_tmp*2, I_dval);
        head = N_tmp - 1;
        for (int i=0; i<N; i++) val[head+i] = val_init[i];
        for (int pos=head-1; pos>=0; pos--) val[pos] = merge_val(val[pos*2+1], val[pos*2+2]);
    }

    void resolve_dval(int pos, int l, int r) { // posで遅延を解消して子孫に押し付ける
        refl_dval(val[pos], dval[pos]);
        if (pos < head)
        {
            add_dval(dval[pos*2+1], dval[pos]);
            add_dval(dval[pos*2+2], dval[pos]);
        }
        dval[pos] = I_dval;
    }

    void update(int begin, int end, DVAL dval_q) { update(begin, end, dval_q, 0, 0, head+1); }
    void update(int begin, int end, DVAL dval_q, int pos, int l, int r)
    {
        // 後でリファクタリング
        if (begin <= l && r <= end) { // 担当区間全部使う
            add_dval(dval[pos], dval_q);
            resolve_dval(pos, l, r);
        }
        else if (begin < r && l < end) { // 少なくともどこかで交差
            resolve_dval(pos, l, r);
            update(begin, end, dval_q, pos*2+1, l, (l+r)/2);
            update(begin, end, dval_q, pos*2+2, (l+r)/2, r);
            val[pos] = merge_val(val[pos*2+1], val[pos*2+2]);
        }
        else resolve_dval(pos, l, r);
    }

    VAL getvalue(int begin, int end) { return getvalue(begin, end, 0, 0, head+1); }
    VAL getvalue(int begin, int end, int pos, int l, int r)
    {
        resolve_dval(pos, l, r);
        if (begin <= l && r <= end) return val[pos];
        else if (begin<r && l<end) {
            VAL vl = getvalue(begin, end, pos*2+1, l, (l+r)/2);
            VAL vr = getvalue(begin, end, pos*2+2, (l+r)/2, r);
            val[pos] = merge_val(val[pos*2+1], val[pos*2+2]);
            return merge_val(vl, vr);
        }
        else return I_val;
    }
};
int N, Q;

int main()
{
    cin >> N >> Q;
    vector<int> A(N);
    cin >> A;
    struct Node
    {
        int n_even, n_odd;
        lint total;
        Node(int ne=0, int no=0, lint tot=0) : n_even(ne), n_odd(no), total(tot) {}
    };
    vector<Node> v(N);
    REP(i, N) v[i] = Node(!(A[i] % 2), (A[i] % 2), A[i]);
    LazySegTree<Node, plint> s(v, Node(), plint(0, 0),
                               [](const Node &l, const Node &r) {
                                   return Node(l.n_even + r.n_even, l.n_odd + r.n_odd, l.total + r.total);
                               },
                               [](plint &x, const plint &y) {
                                   if (y.second) x = y;
                                   else x.first += y.first;
                               },
                               [](Node &n, plint x) {
                                   if (x.second) n.total = n.n_odd;
                                   n.total += (n.n_even + n.n_odd) * x.first;
                                   if (x.first % 2) swap(n.n_even, n.n_odd);
                               });
    REP(_, Q)
    {
        int q, l, r;
        cin >> q >> l >> r;
        l--;
        if (q == 1)
        {
            s.update(l, r, plint(0, 1));
        }
        else if (q == 2)
        {
            lint x;
            cin >> x;
            s.update(l, r, plint(x, 0));
        }
        else
        {
            cout << s.getvalue(l, r).total << endl;
        }
    }
}
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