結果

問題 No.935 う　し　た　ぷ　に　き　あ く ん 笑　ビ　－　ム
ユーザー nullnull
提出日時 2019-11-20 16:05:12
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
WA  
実行時間 -
コード長 2,875 bytes
コンパイル時間 1,154 ms
コンパイル使用メモリ 115,360 KB
最終ジャッジ日時 2025-01-08 04:12:04
ジャッジサーバーID
（参考情報） 		judge1 / judge5
このコードへのチャレンジ
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ファイルパターン 結果
sample WA * 2
other WA * 58
権限があれば一括ダウンロードができます
コンパイルメッセージ
main.cpp: In function ‘void scans(std::string&)’:
main.cpp:60:14: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
   60 |         scanf("%c", &c);
      |         ~~~~~^~~~~~~~~~
main.cpp:61:28: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
   61 |         if (c == '\n')scanf("%c", &c);//最初の改行対策
      |                       ~~~~~^~~~~~~~~~
main.cpp:64:22: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
   64 |                 scanf("%c", &c);
      |                 ~~~~~^~~~~~~~~~
main.cpp: In function ‘void scanc(char&)’:
main.cpp:70:14: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
   70 |         scanf("%c", &c);
      |         ~~~~~^~~~~~~~~~
main.cpp:73:22: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
   73 |                 scanf("%c", &c);
      |                 ~~~~~^~~~~~~~~~
main.cpp: In function ‘int main()’:
main.cpp:87:14: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
   87 |         scanf("%d", &n);
      |         ~~~~~^~~~~~~~~~
main.cpp:91:23: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
   91 |         rep(i, n)scanf("%llu", &a[i]);
      |                  ~~~~~^~~~~~~~~~~~~~~
main.cpp:94:14: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
   94 |         scanf("%d", &q);
      |         ~~~~~^~~~~~~~~~
main.cpp:100:22: war

ソースコード

diff # 

/*
このコード、と～おれ!
Be accepted!
∧＿∧　
（｡･ω･｡)つ━☆・*。
⊂　　 ノ 　　　・゜+.
　しーＪ　　　°。+ *´¨)
 　　　　　　　　　.· ´¸.·*´¨) ¸.·*¨)
		  　　　　　　　　　　(¸.·´ (¸.·'* ☆
					*/

#include <stdio.h>
#include <algorithm>
#include <string>
#include <cmath>
#include <cstring>
#include <vector>
#include <numeric>
#include <iostream>
#include <random>
#include <map>
#include <unordered_map>
#include <queue>

#pragma GCC optimize("Ofast")
#define rep(i, n) for(int i = 0; i < (n); ++i)
#define rep1(i, n) for(int i = 1; i <= (n); ++i)
#define rep2(i, n) for(int i = 2; i < (n); ++i)
#define repr(i, n) for(int i = n; i >= 0; --i)
#define reprm(i, n) for(int i = n - 1; i >= 0; --i)
#define printynl(a) printf(a ? "yes\n" : "no\n")
#define printyn(a) printf(a ? "Yes\n" : "No\n")
#define printYN(a) printf(a ? "YES\n" : "NO\n")
#define printin(a) printf(a ? "possible\n" : "inposible\n")
#define printdb(a) printf("%.50lf\n", a)//少数出力
#define printdbd(a) printf("%.16lf\n", a)//少数出力(桁少なめ)
#define prints(s) printf("%s\n", s.c_str())//string出力
#define all(x) (x).begin(), (x).end()
#define allsum(a, b, c) ((a + b) * c / 2)//等差数列の和、初項,末項,項数
#define pb push_back
#define priq priority_queue
#define rpriq priq<int, vector<int>, greater<int>>
#define deg_to_rad(deg) (((deg)/360.0)*2.0*PI)
#define rad_to_deg(rad) (((rad)/2.0/PI)*360.0)
#define Please return
#define AC 0

using ll = long long;

const int INF = 1073741823;
const int MINF = -1073741823;
const ll LINF = ll(4661686018427387903);
const ll MOD = 1000000007;
const double PI = acos(-1);

using namespace std;

void scans(string& str) {
	char c;
	scanf("%c", &c);
	if (c == '\n')scanf("%c", &c);//最初の改行対策
	while (c != '\n' && c != -1) {
		str += c;
		scanf("%c", &c);
	}
}

void scanc(char& str) {
	char c;
	scanf("%c", &c);
	if (c == -1)return;
	while (c == '\n') {
		scanf("%c", &c);
	}
	str = c;
}

double acot(double x) {
	return PI / 2 - atan(x);
}

/*-----------------------------------------ここからコード-----------------------------------------*/

int main(){

	int n;
	scanf("%d", &n);
	string s;
	scans(s);
	vector<unsigned long long int> a(n);
	rep(i, n)scanf("%llu", &a[i]);
	int right = 0, left = 0;
	int q;
	scanf("%d", &q);
	int k;
	unsigned long long int sum = 0, enemy = 0, ans = MINF;
	rep(qq, q) {
		right = left = sum = enemy = 0;
		ans = MINF;
		scanf("%d", &k);
		for (left = 0; left < n; ++left) {
			while (right < n && sum + a[right] <= k) {
				sum += a[right];
				enemy += (s[right] == 'E');
				++right;
			}

			ans = max(ans, enemy);

			if (right == left) {
				if (right != n - 1) {
					++right;
				}
			}
				sum -= a[left];
				enemy -= (s[left] == 'E');
		}
		printf("%llu\n", ans);
	}

	Please AC;
}
0