結果
問題 | No.260 世界のなんとか3 |
ユーザー |
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提出日時 | 2015-07-31 22:32:14 |
言語 | C++11(廃止可能性あり) (gcc 13.3.0) |
結果 |
AC
|
実行時間 | 106 ms / 2,000 ms |
コード長 | 2,796 bytes |
コンパイル時間 | 851 ms |
コンパイル使用メモリ | 82,600 KB |
実行使用メモリ | 8,576 KB |
最終ジャッジ日時 | 2024-11-07 17:58:23 |
合計ジャッジ時間 | 3,158 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge4 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 27 |
ソースコード
#include <string>#include <vector>#include <algorithm>#include <numeric>#include <set>#include <map>#include <queue>#include <iostream>#include <sstream>#include <cstdio>#include <cmath>#include <ctime>#include <cstring>#include <cctype>#include <cassert>#include <limits>#include <functional>#define rep(i,n) for(int (i)=0;(i)<(int)(n);++(i))#define rer(i,l,u) for(int (i)=(int)(l);(i)<=(int)(u);++(i))#define reu(i,l,u) for(int (i)=(int)(l);(i)<(int)(u);++(i))#if defined(_MSC_VER) || __cplusplus > 199711L#define aut(r,v) auto r = (v)#else#define aut(r,v) __typeof(v) r = (v)#endif#define each(it,o) for(aut(it, (o).begin()); it != (o).end(); ++ it)#define all(o) (o).begin(), (o).end()#define pb(x) push_back(x)#define mp(x,y) make_pair((x),(y))#define mset(m,v) memset(m,v,sizeof(m))#define INF 0x3f3f3f3f#define INFL 0x3f3f3f3f3f3f3f3fLLusing namespace std;typedef vector<int> vi; typedef pair<int,int> pii; typedef vector<pair<int,int> > vpii; typedef long long ll;template<typename T, typename U> inline void amin(T &x, U y) { if(y < x) x = y; }template<typename T, typename U> inline void amax(T &x, U y) { if(x < y) x = y; }template<int MOD>struct ModInt {static const int Mod = MOD;unsigned x;ModInt(): x(0) { }ModInt(signed sig) { int sigt = sig % MOD; if(sigt < 0) sigt += MOD; x = sigt; }ModInt(signed long long sig) { int sigt = sig % MOD; if(sigt < 0) sigt += MOD; x = sigt; }int get() const { return (int)x; }ModInt &operator+=(ModInt that) { if((x += that.x) >= MOD) x -= MOD; return *this; }ModInt &operator-=(ModInt that) { if((x += MOD - that.x) >= MOD) x -= MOD; return *this; }ModInt &operator*=(ModInt that) { x = (unsigned long long)x * that.x % MOD; return *this; }ModInt operator+(ModInt that) const { return ModInt(*this) += that; }ModInt operator-(ModInt that) const { return ModInt(*this) -= that; }ModInt operator*(ModInt that) const { return ModInt(*this) *= that; }};typedef ModInt<1000000007> mint;int digits[10003];bool eqok;mint memo[10003][24][2][2];mint rec(int i, int mod, bool three, bool lt) {mint &r = memo[i+1][mod][three][lt];if(r.x != -1) return r;if(i == -1) return r = mod % 8 != 0 && (three || mod % 3 == 0) && (eqok || lt);r = 0;int e = digits[i];rep(d, 10) if(lt || d <= e)r += rec(i-1, (mod * 10 + d) % 24, three || d == 3, lt || d < e);return r;}int main() {string A, B;while(cin >> A >> B) {mint ans;eqok = true;mset(digits, 0);rep(i, B.size()) digits[B.size() - 1 - i] = B[i] - '0';mset(memo, -1);ans += rec(10001, 0, false, false);eqok = false;mset(digits, 0);rep(i, A.size()) digits[A.size() - 1 - i] = A[i] - '0';mset(memo, -1);ans -= rec(10001, 0, false, false);printf("%d\n", ans.get());}return 0;}