結果

問題 No.953 席
ユーザー hitonanodehitonanode
提出日時 2019-12-16 02:18:05
言語 C++14
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 359 ms / 2,000 ms
コード長 3,266 bytes
コンパイル時間 2,032 ms
コンパイル使用メモリ 191,932 KB
実行使用メモリ 30,720 KB
最終ジャッジ日時 2024-07-02 18:56:36
合計ジャッジ時間 9,742 ms
ジャッジサーバーID
(参考情報)
judge2 / judge5
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
5,248 KB
testcase_01 AC 2 ms
5,376 KB
testcase_02 AC 185 ms
26,240 KB
testcase_03 AC 166 ms
25,984 KB
testcase_04 AC 181 ms
26,240 KB
testcase_05 AC 146 ms
25,728 KB
testcase_06 AC 187 ms
26,240 KB
testcase_07 AC 307 ms
24,832 KB
testcase_08 AC 331 ms
29,184 KB
testcase_09 AC 273 ms
23,168 KB
testcase_10 AC 80 ms
10,752 KB
testcase_11 AC 245 ms
22,912 KB
testcase_12 AC 306 ms
29,056 KB
testcase_13 AC 344 ms
30,464 KB
testcase_14 AC 279 ms
28,416 KB
testcase_15 AC 270 ms
27,904 KB
testcase_16 AC 279 ms
28,160 KB
testcase_17 AC 207 ms
26,272 KB
testcase_18 AC 195 ms
26,296 KB
testcase_19 AC 244 ms
27,000 KB
testcase_20 AC 193 ms
26,140 KB
testcase_21 AC 156 ms
25,984 KB
testcase_22 AC 298 ms
29,312 KB
testcase_23 AC 216 ms
27,136 KB
testcase_24 AC 221 ms
27,136 KB
testcase_25 AC 359 ms
30,720 KB
testcase_26 AC 126 ms
25,600 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

#include <bits/stdc++.h>
using namespace std;
using lint = long long int;
using plint = pair<lint, lint>;
struct fast_ios { fast_ios(){ cin.tie(0); ios::sync_with_stdio(false); cout << fixed << setprecision(20); }; } fast_ios_;
#define FOR(i, begin, end) for(int i=(begin),i##_end_=(end);i<i##_end_;i++)
#define REP(i, n) FOR(i,0,n)
template<typename T> istream &operator>>(istream &is, vector<T> &vec){ for (auto &v : vec) is >> v; return is; }
///// This part below is only for debug, not used /////
template<typename T> ostream &operator<<(ostream &os, const vector<T> &vec){ os << "["; for (auto v : vec) os << v << ","; os << "]"; return os; }
template<typename T> ostream &operator<<(ostream &os, const set<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; }
template<typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &pa){ os << "(" << pa.first << "," << pa.second << ")"; return os; }
template<typename TK, typename TV> ostream &operator<<(ostream &os, const map<TK, TV> &mp){ os << "{"; for (auto v : mp) os << v.first << "=>" << v.second << ","; os << "}"; return os; }
#define dbg(x) cerr << #x << " = " << (x) << " (L" << __LINE__ << ") " << __FILE__ << endl;
///// END /////

int main()
{
    int N, K, K2;
    cin >> N >> K >> K2;
    vector<int> yusen(N + 2);

    int i = K, j = K2, pr = 0;
    if (K2 < K) {
        i = K2, j = K + 1, pr = 1;
    }
    while (true) {
        if (i <= 0 and j > N) break;
        if (i > 0) yusen[i--] = pr++;
        if (j <= N) yusen[j++] = pr++;
    }
    auto f = [&](int l, int r) { return yusen[l] < yusen[r]; };
    set<int, function<bool(int l, int r)>> aki(f), aki_pri(f);
    FOR(i, 1, N + 1) aki.insert(i), aki_pri.insert(i);
    map<lint, vector<plint>> kyaku;
    int Q;
    cin >> Q;
    REP(q, Q) {
        lint a, b;
        cin >> a >> b;
        kyaku[a].emplace_back(q, b);  // hito, duration
    }
    lint t = -1;
    vector<int> ret(Q);
    queue<plint> waiting;
    vector<int> state(N + 2);
    while (true)
    {
        auto p = kyaku.upper_bound(t);
        if (p == kyaku.end()) break;
        t = p->first;
        for (auto pa : p->second) {
            lint q = pa.first, T = pa.second;
            if (q >= 0) waiting.emplace(q, T);
            if (q < 0) {
                aki.insert(T);
                state[T] = 0;
                FOR(d, -1, 2) if (T + d > 0 and T + d <= N and !state[T + d - 1] and !state[T + d] and !state[T + d + 1]) aki_pri.insert(T + d);
            }
        }
        while (aki.size() and waiting.size()) {
            lint q = waiting.front().first, T = waiting.front().second;
            int v;
            if (aki_pri.size())
            {
                v = *aki_pri.begin();
            }
            else
            {
                v = *aki.begin();
            }
            kyaku[t + T].emplace_back(-1, v);
            aki_pri.erase(v);
            aki_pri.erase(v - 1);
            aki_pri.erase(v + 1);
            aki.erase(v);
            state[v] = 1;
            ret[q] = v;
            waiting.pop();
        }
    }

    if (aki.size() != N or aki_pri.size() != N) exit(8);

    for (auto q : ret)
    {
        if (q <= 0 or q > N) exit(8);
        printf("%d\n", q);
    }
}
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