結果
| 問題 |
No.953 席
|
| コンテスト | |
| ユーザー |
hitonanode
|
| 提出日時 | 2019-12-16 02:23:40 |
| 言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 356 ms / 2,000 ms |
| コード長 | 3,290 bytes |
| コンパイル時間 | 2,331 ms |
| コンパイル使用メモリ | 193,000 KB |
| 実行使用メモリ | 30,720 KB |
| 最終ジャッジ日時 | 2024-07-02 18:57:41 |
| 合計ジャッジ時間 | 9,952 ms |
|
ジャッジサーバーID (参考情報) |
judge2 / judge1 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 2 |
| other | AC * 25 |
ソースコード
#include <bits/stdc++.h>
using namespace std;
using lint = long long int;
using plint = pair<lint, lint>;
struct fast_ios { fast_ios(){ cin.tie(0); ios::sync_with_stdio(false); cout << fixed << setprecision(20); }; } fast_ios_;
#define FOR(i, begin, end) for(int i=(begin),i##_end_=(end);i<i##_end_;i++)
#define REP(i, n) FOR(i,0,n)
template<typename T> istream &operator>>(istream &is, vector<T> &vec){ for (auto &v : vec) is >> v; return is; }
///// This part below is only for debug, not used /////
template<typename T> ostream &operator<<(ostream &os, const vector<T> &vec){ os << "["; for (auto v : vec) os << v << ","; os << "]"; return os; }
template<typename T> ostream &operator<<(ostream &os, const set<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; }
template<typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &pa){ os << "(" << pa.first << "," << pa.second << ")"; return os; }
template<typename TK, typename TV> ostream &operator<<(ostream &os, const map<TK, TV> &mp){ os << "{"; for (auto v : mp) os << v.first << "=>" << v.second << ","; os << "}"; return os; }
#define dbg(x) cerr << #x << " = " << (x) << " (L" << __LINE__ << ") " << __FILE__ << endl;
///// END /////
int main()
{
int N, K, K2;
cin >> N >> K >> K2;
vector<int> yusen(N + 2);
int i = K, j = K2, pr = 0;
if (K2 < K) {
i = K2, j = K + 1, pr = 1;
}
while (true) {
if (i <= 0 and j > N) break;
if (i > 0) yusen[i--] = pr++;
if (j <= N) yusen[j++] = pr++;
}
auto f = [&](int l, int r) { return yusen[l] < yusen[r]; };
set<int, function<bool(int l, int r)>> aki(f), aki_pri(f);
FOR(i, 1, N + 1) aki.insert(i), aki_pri.insert(i);
map<lint, vector<plint>> kyaku;
int Q;
cin >> Q;
REP(q, Q) {
lint a, b;
cin >> a >> b;
kyaku[a].emplace_back(q, b); // hito, duration
}
lint t = -1;
vector<int> ret(Q);
queue<plint> waiting;
vector<int> state(N + 2);
while (true)
{
auto p = kyaku.upper_bound(t);
if (p == kyaku.end()) break;
t = p->first;
auto vec = p->second;
for (auto pa : vec) {
lint q = pa.first, T = pa.second;
if (q >= 0) waiting.emplace(q, T);
if (q < 0) {
aki.insert(T);
state[T] = 0;
FOR(d, -1, 2) if (T + d > 0 and T + d <= N and !state[T + d - 1] and !state[T + d] and !state[T + d + 1]) aki_pri.insert(T + d);
}
}
while (aki.size() and waiting.size()) {
lint q = waiting.front().first, T = waiting.front().second;
int v;
if (aki_pri.size())
{
v = *aki_pri.begin();
}
else
{
v = *aki.begin();
}
kyaku[t + T].emplace_back(-1, v);
aki_pri.erase(v);
aki_pri.erase(v - 1);
aki_pri.erase(v + 1);
aki.erase(v);
state[v] = 1;
ret[q] = v;
waiting.pop();
}
}
if (aki.size() != N or aki_pri.size() != N) exit(8);
for (auto q : ret)
{
if (q <= 0 or q > N) exit(8);
printf("%d\n", q);
}
}
hitonanode